5 Marks Guaranteed in Aptitude Section Especially for IBPS Exams 2017 (Tricks and Tips for Number Series)

5 Marks Guaranteed in Aptitude Section Especially for IBPS Exams 2017 (Tricks and Tips for Number Series):

Dear Readers, Here we have given the Useful Shortcuts and Tricks for Number Series for IBPS Exams 2017, this will definitely help you to answers all the Number Series Questions. Candidates those who are preparing for the upcoming IBPS Exams 2017 can make use of it.

Number Series puzzles can be solved by various tricks provided by mathematics.
Firstly check the direct formulas as in like check

· if all the numbers are prime, even or odd.

· If all the numbers are perfect squares or cubes.

· If all the numbers have a particular divisibility.

· If all the numbers are succeeding by some additions or subtraction or multiplications or divisions by a particular number or addition of their cubes and squares.

Different types of Number series:

1) Integer Number Sequences – There are particular formulas tricks to solve number series. Each number series question is solved in a particular manner. This series is the sequence of real numbers decimals and fractions. Number series example of this is like 1, 3, 5, 9….. etc. in which what should come next is Solved by number series shortcuts tricks performed by the candidate.

2) Rational Number Sequences – These are the numbers which can be written as a fraction or quotient where numerator and denominator both consist of integers. An example of this series is ½, ¾, 1.75 and 3.25.

3) Arithmetic Sequences – It is a mathematical sequence which consisting of a sequence in which the next term originates by adding a constant to its predecessor. It is solved by a particular formula given by the mathematics Xn = x1 + (n – 1)d. An example of this series is 3, 8, 13, 18, 23, 28, 33, 38, in which number 5 is added to its next number.

4) Geometric Sequences – It is a sequence consisting of a multiplying so as to group in which the following term starts the predecessor with a constant. The formula for this series is Xn= x1 r n-1. An example of this type of number sequence could be the following:
2, 4, 8, 16, 32, 64, 128, 256, in which multiples of 2 are there.

5) Square Numbers – These are also known as perfect squares in which an integer is the product of that integer with itself. Formula= Xn= n. An example of this type of number sequence could be the following:
1, 4, 9, 16, 25, 36, 49, 64, 81, ..

6) Cube Numbers – Same as square numbers but in these types of series an integer is the product of that integer by multiplying 3 times. Formula= Xn=n^3. Example:-1, 8, 27, 64, 125, 216, 343, 512, 729, …

7) Fibonacci Series – A sequence consisting of a sequence in which the next term originates by addition of the previous two
Formula = F0 = 0, F1 = 1
Fn = Fn-1 + Fn-2. An example of this type of number sequence could be the following:
0, 1, 1, 2, 3, 5, 8, 13, 21, 34, …

Odd One out: when all but one number is part of a series

5, 10, 12, 15, 20... (Here all numbers except, 12 are multiples of 5)

Square series: These are also known as perfect square series which are based on square of a number in same order. In exam it can be missing square or mistakenly put square in series.

Example:

289, 324, 361, 400, ?'

Solution:
289 = 17², 324 = 18², 361 = 19², 400 = 20², 441 = 21²

Cube series: These type of series based on perfect cube. In exam there can be missing cube or mistakenly put cube in number series.

Example:

1728, 2197, 2744, 3375, ?
Solution:

1728 = 12³, 2197 = 13³, 2744 = 14³, 3375 = 15³, 4096 = 16³

Mixed Series:

This type of number series can be used various method. In this number may be given in addition, subtraction, multiplication and division in the alternate numbers. It is created according to any non-conventional rule.

Example:

10, 31, 94, 283, ?
Solution:

10 x 3 = 30 + 1 = 31,

31 x 3 = 93 + 1 = 94,

94 x 3 = 282 + 1= 283,

283 x 3 = 849 + 1 = 850,

So the missing number is 850.

Two-tier Arithmetic Series:

1) 4, 5, 9, 16, 26, 39, 55, ?

Division series:

In this type, each time the previous element is divided by same digit to obtain the next element.

1600, 400, 100, 25,___.

In the given series, previous element is divided by 4 to get the next element.

1600/4 = 400

400/4 = 100

100/4 = 25

25 /4 = 6.25

Therefore, the correct answer = 6.25

Decimal Fraction:

1) 36, 18, 18, 27, 54,___.

In this series, following pattern is used:

Difference of difference series:

Calculate the differences between the numbers given in the series provided in the question. Then try to observe the pattern in the new set of numbers that you have obtained after taking out the difference.

1) 1, 3, 8, 19, 39, 71,_____.

Solution:

The following pattern is observed in the given series