Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-37)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-37):

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Direction (1-10): What value should come in place of question mark (?) in the following questions?
1).(654.89÷23)% of 1546 = ? + 140

1). Answer: b)
28.47% of 1546 = 28.47*1546/100 = 440.14 ≈ 440
? = 440 – 140 = 300

2). (27.78)² + (56.89)²– (46.50)² + (9)^(1/2) = ?²

2). Answer: c)
?² = 771.73+3236.47 – 2162.25 = 1845.95 ≈ 1846
?² = 1846+3 = 1849 = 43 *43
? = 43

3).499÷4×33.44 +?^(1/2) = (64.78)^2

3). Answer: a)
125*33.44 = 4180
√? ≈ 4225 – 4180 = 45
? = 452= 2025
? = 2025

4). 1023.56 +213.09 – 45.90 + 0.006 – 11.001 = ?

4). Answer: a)
? = 1236.66 – 56.9 = 1179.755 ≈ 1180

5).(6858.78)^(1/3)× (50625.02)^(1/4) + 5² = ?×5

5). Answer: d)
(6858.78)^(1/3)× (50625.02)^(1/4) ≈ 19×15 = 285
285 + 25 = 310
? = 310/5 = 62

6).(325.25÷25)% of 3223.06 = ? + 267.12

6). Answer: b)
13.01% of 3223 = 419.3 ≈ 419
? = 419 – 267 = 152

7).(21.98)² × 7.09 + (23.06)² × 6.45 = ?

7). Answer: c)
? ≈ 484 ×7 + 529 ×6.5
? = 3388 + 3438.5 = 6826.5 ≈ 6825

8).(1/5.89) of 5642 + 285.32 = ?²

8). Answer: c)
?^2 ≈ 5640/6 + 285 = 940+285 = 1225
?^2 = 35*35
? = 35

9). (1/3.01) of (255.8/7) of (21/15.99) of (1/2) of ? = 3647.78

9). Answer: a)
3648 ≈ 1/3 * 256/7 * 21/16 * 1/2 * ?
256*21/(3*7*16*2) = 5376/672 = 8
? = 3648/8 = 456

10).[√(122.19×48.69) ]÷3.467 × 78.03 = ?² + 34.765

10). Answer: d)
[√(122.19×48.69)] ≈ [√(121 * 49)] = 77
77÷3.5 = 22
22*78 = 1716
?2 = 1716 – 35 = 1681 = 41*41
? = 41

Direction (11-20): What value should come in place of question mark (?) in the following questions?
11). (9/18)×(162/207)÷(554/294)+(79/100) = ?

11). Answer: d)
? = 9*162*294/18*207*554+0.79 = 0.20+0.79 = 0.99

12). ([0.081×0.484]/[0.0064×6.25])^(1/2)= ?

12). Answer: c)
? = (81*484/64*625)1/2 = 9*22/8*25 = 0.99

13). 8^(1.4) × 4^(1.7)× 16^(0.2) = 2^?

13). Answer: c)
2^? = 2^4.2 × 2^3.4× 2^(0.8) = 2^(4.2+3.4+0.8)= 2^(8.4)
? = 8.4

14). 43% of 1211 + 67% of 0.08 = ?

14). Answer: b)
? = 520.73+0.0536 =520.7836

15). 1225÷15+223-(100-87) = ?

15). Answer: a)
? = = 1225÷15+223-13
= 81.67+223-13
= 291.67

16).(1/11) of 7645 of (1/0.5) = ? ÷ 0.1

16). Answer: c)
? = 695/0.5 = 1390*0.1 = 139

17). (2505/15)×25 = ? % of 7865

17). Answer : a)
?= 167*25 = 4175
X*7865/100 = 4175
X = 4175*100/7865 = 53.08

18). 276.75 + 4% of 678 + √0.0169 = ?

18). Answer : a)
? = 276.75 + 27.12+ √0.0169 = 304

19). (11.08)² + (24.88)² + ? = 751

19). Answer : c)
?= 122.77 + 619.01 = 741.78
751 – 741.78 = 9.22

20).9² × (1/6561) × 729 = 9^?

20). Answer : a)
9^? = 9^2 × 9^-4 × 9^3 = 9^(3-4+2) = 9^1
? = 1

Direction (21 – 25): What will come in place of (?) in the following number series.
21).5, 12, 40, ?, 215, 390, 642

21). Answer: b)
The series is,
5 + 7 * 1² = 12
12 + 7 * 2² = 40
40 + 7 * 3² = 103…..

22).717, 522, 335, ?, 121, 66

22). Answer: a)
The series is,
9³ – 12 = 717
8³ + 10 = 522
7³ – 8 = 335……

23). 2394, 1290, 620, 252, 78, ?

23). Answer: c)
The series is, 7^4 – 7, 6^4 – 6, 5^4 – 5, 4^4 – 4…

24). 15, 25, 34, ?, 464, 2330, 13980

24). Answer: d)
The series is
(15 * 1 ) + (1 * 10) = 25
(25 * 2 ) – (2 * 8) = 34
(34 * 3 ) + (3 * 6) = 120
(120 * 4) – (4 * 4) = 464
(464 * 5) + (5 * 2) = 2330
(2330 * 6) – (6 * 0) = 13980

25). 2580, 2582, 5160, 15486, 61936, ?

25). Answer: a)
The series is,
2580 * 1 + 2= 2582
2582 * 2 – 4 = 5160
5160 * 3 + 6 = 15486
15486 * 4 – 8 = 61936 ….

Direction (26-30): In each of these questions, two equations I & II are given. You have to solve both the equations and given answer:
A) If X > Y
B) If X < Y
C) If X ≥ Y
D) If X ≤ Y
E) If X = Y or cannot be established

26). I. x² + x – 20 = 0, II. y² – 13y + 40 = 0

26). Answer: b)
x² + x – 20 = 0
(x+5)(x-4) = 0
x = -5, 4
y² – 13y + 40 = 0
(y-5)(y-8) = 0
y = 5, 8
Hence, x < y

27). I. x² – 11x + 24 = 0, II. y² + 9y + 18 = 0

27). Answer: a)
x² – 11x + 24 = 0
(x-3)(x-8) = 0
x = 3, 8
y² + 9y + 18 = 0
(y+3)(y+6) = 0
y = -3, -6
Hence, x > y

28). I. 3x² + 8x + 5 = 0, II. 2y² + y – 1 = 0

28). Answer: d)
3x² + 8x + 5 = 0
3x² + 3x + 5x + 5 = 0
x = -1, -5/3
2y² + y – 1 = 0
2y² + 2y – y -1 = 0
y = -1, 1/2
Therefore y ≥ x

29). I. 3x + 2y = 16, II. 2x+ 3y = 33/2

29). Answer: b)
x = 3, y = 3.5
Therefore, x < y

30). I. 2x² – 9x + 4 = 0, II. 2y² + 7y – 4 = 0

30). Answer: c)
2x² – 9x + 4 = 0
2x² – 8x – x + 4 = 0
x = 4 , 1/2
2y² + 7y – 4 = 0
2y² + 8y – y – 4 = 0
y = -4, 1/2
Therefore, y ≤ x

       

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