Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-11)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-11):

Dear Readers, Nowadays most of the aspirants are facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.

Here in Scoring Part we are providing 10 Questions in simplification, 10 Questions in Approximation, 5 Questions in number Series and 5 Questions in Quadratic Equations, total 30 questions in 20 Minutes. By practicing these questions regularly you can increase your calculation speed and it will help you to increase your score.

Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). [(23.65)^2 - (48.35)^2 ] / 0.9 = ?

1). Answer: a)
? = [(23.65 + 48.35)(23.65 – 48.35)] / 0.9
? = 72 × (– 24.7) / 0.9
or, ? = - 1976

2. 76% of 960 - 45% of 148 = ?% of 5525

2). Answer: e)
? / 100 × 5525 = 76 × 960 /100 – 45 × 148 /100
? / 100 × 5525 = 729.6 - 66.6 = 663
? = 663 × 100 / 5525 = 12

3. (4096)^3.7 ÷ (256)^4.3 × (64)^5 ÷ (16)^-4 = (4)?

3). Answer: d)
(4^6)^3.7 ÷ (4^4)^4.3 × (4^3)^5 ÷ (4^2)^-4 = (4)^?
(4)^? = (4)^22.2 ÷ (4)^17.2 × (4)^15 ÷ (4)^-8
(4)^? = (4)^(22.2 -17.2 + 15 + 8) = (4)^28
? = 28

4. 3 2/7 of 4 5/11 of 3/35 of 3080 = ?

4). Answer: a)
? = 3 2/7 of 4 5/11 of 3/35 of 3080
? = 23/7 × 49/11 × 3/35 × 3080
? = 3864

5). [5√(2√38416)]^(5/2) = ?

5). Answer: a)
[5√(2√38416)]^(5/2) = ?
? = [5√196]^(5/2)
? = 196^(1/2) = 14

6. 4/7 of 3/11 of 24/13 of 15015 = ?

6). Answer: b)
? = 4/7 × 3/11 × 24/13 × 15015
? = 4320

7. 984 + 3.75 × 440 - 1.25 × 248 = ?

7). Answer: c)
? = 984 + 1650 - 310
= 2634 - 310 = 2324

8. [3√(2√20736)]^(3/2) = ?

8). Answer: d)
? = [3√(2√20736)]^(3/2)
? = [3√(144)]^(3/2)
? = 144^(1/2) = 12

9. (?% of 664) ÷ 0.8 = 332

9). Answer: e)
? / 100 × 664 = 332 × 0.8 = 265.6
? = 265.6 × 100 / 664 = 40

10.18.5 % of 7200 + 27.8% of 1800 + 16.6 = (?)^2

10). Answer: c)
(?)^2 = 18.5 × 7200 /100 + 27.8 × 1800 /100 + 16.6
(?)^2 = 1332 + 500.4 + 16.6 = 1849 = (43)2
? = 43

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11.379.87 × 44.12 - 78.89 × 84.15 + 373 = ?

11). Answer: b)
? ≈ (380 × 44) - (79 × 84) + 373
? = 16720 - 6636 + 373 = 10457 ≈ 10460

12. (2.38% of 743) × (1.84% of 588) = ?

12). Answer: a)
? ≈ 2.4 × 740 /100 × 1.8 × 590 / 100
? = 17.76 × 10.62 = 188.6112 ≈ 190

13. 182.06 × 17.987 + 172% of 785 = ?

13). Answer: e)
? ≈ 182 × 18 + 172 × 785 /100
? = 3276 + 1350.2 = 4626.2 ≈ 4625

14. 17.99 × 155.05 + 1245 ÷ 32 = ?

14).Answer: d)
? = 18 × 155 + 1245 / 32
? = 2790 + 38.9 = 2828.9 ≈ 2830

15. 77.003 × 13.998 + 18.04 × 14.996 = ?

15). Answer: c)
? ≈ 77 × 14 + 18 × 15
? = 1078 + 270 = 1348 ≈ 1350

16. 22% of 164.4 + 13.89 % of 65 = ?

16). Answer: b)
? ≈ 22 × 164.4/100 + 14 × 65 / 100
? ≈ 36 + 9 = 45

17. [(1.29)^2 + (3.05)^2] / 0.198 = ?

17). Answer: d)
? ≈ [(1.3)^2 + (3)^2 ] / 0.2
? = (1.69 + 9) / 0.2
? = 10.7 / 0.2 = 53.5 ≈ 54

18. (48.84)^2 × 7.079 = ?

18). Answer: d)
? ≈ 7 × 49^2
? = 16807 ≈ 16800

19. √ 2020 + √320 + √1330 = ?

19). Answer: b)
√2020 ≈ 45, √320 ≈ 18, √1330 ≈ 36.5
? = 45 + 18 + 36.5 = 99.5 ≈ 100

20. (8/3 × 13/5) + (7/2 × 5/3) + (18/7 × 28/16) = ?

20). Answer: c)
? = 104 / 15 + 35 / 6 + 9 / 2
? ≈ 7 + 6 + 4.5 = 17.5

Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.21. 18.3, 20.6 , 16, 22.9 , 13.7, 22.2, 11.4

21). Answer: a)
The series is,
18.3 + 2.3 = 20.6
20.6 - 4.6 = 16
16 + 6.9 = 22.9
22.9 - 9.2 = 13.7
13.7 +11.5 = 25.2 ≠ 22.2
25.2 - 13.8 = 11.4

22. 9 , 5 , 6 , 10.5 , 23 , 61, 183

22). Answer: c)
The sequence in the series is,
9 x 0.5 + 0.5 = 5
5 x 1 + 1 = 6
6 x 1.5 + 1.5 = 10.5
10.5 x 2 + 2 = 23
23 x 2.5 + 2.5 = 60 ≠ 61
60 x 3 + 3 = 183

23. 188, 154, 140, 132 ,128, 126 , 125

23). Answer: e)
The series is,
188 - 32 = 156 ≠ 154
156 - 16 = 140
140 - 8 = 132
132 - 4 = 128
128 - 2 = 126
126 - 1 = 125

24. 2, 4 , 11 , 37 , 151 , 771 , 4633

24). Answer: d)
The sequence in the series is,
2 x 1 + 2 = 4
4 x 2 + 3 = 11
11 x 3 + 4 = 37
37 x 4 + 5 = 153 ≠ 151
153 x 5 + 6 = 771
771 x 6 + 7 = 4633

25. 391 , 394 , 399 , 411 , 431 , 461, 503

25). Answer: b)
The series is,
391 + 2 = 393 ≠ 394
393 + 6 = 399
399 + 12 = 411
411+ 20 = 431
431 + 30 = 461
461 +42 = 503

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) if x > y
b) if x < y
c) if x ≥ y
d) if x ≤ y
e) if x =y, or no relation can be established between x and y.

26. I. 5x^2 – 87x + 378 = 0
II. 3y^2 – 49y + 200 = 0

26). Answer: a)
I. 5x^2 - 45x - 42x + 378 = 0
or,5x(x - 9) - 42(x- 9) = 0
or. (5x - 42)(x -9) = 0
x = 9, 42/5
II. 3y^2 - 24y - 25y + 200=0
or, 3y(y - 8) -25(y - 8) = 0 or, (y - 8)(3y-25)=0
y = 8, 25/3
Hence, x>y

27.I. 10x^2 – x – 24 = 0
II. y^2 – 2y = 0

27). Answer: e)
I. 10x^2 -16x + 15x – 24 = 0
or, 2x(5x -8) + 3(5x - 8)=0
or,(2x + 3)(5x -8) = 0
x = -3/2, 8/5
II. y^2 – 2y = 0
or, y(y -2) = 0
y = 0, 2
i.e. no relationship between x and y.

28. I. x^2 – 5x + 6 = 0
II. 2y^2 – 15y + 27 = 0

28). Answer: d)
I. x^2 - 2x - 3x + 6 =0
or, x(x -2) - 3(x -2) = 0
or, (x -2) (x -3) = 0
x =2, 3
II. 2y^2 - 6y - 9y + 27 = 0
or, 2y(y - 3)-9(y -3) = 0
or, (y- 3) (2y -9) = 0
y = 3, 9/2
hence, x ≤ y

29. I. 3x + 2y = 301
II. 7x – 5y = 74

29). Answer: b)
I. eqn (I) × 5 + eqn (II) × 2
[15x + 10y = 1505] + [14x – 10y = 148] = 29x = 1653
x = (1653/29) = 57
and y = 65
hence, x< y

30. I. 14x^2 – 37x + 24 = 0
II. 28y^2 – 53y + 24 = 0

30). Answer: c)
14x^2 - 37x + 24 = 0
or, 14x^2 - 21x- 16x + 24 = 0
or, 7x(2x -3) -8(2x -3) = 0
or, (2x - 3)(7x - 8) = 0
x = (3/2), (8/7)
II. 28y^2 - 53y + 24 = 0
or, 28y^2 -21y - 32y + 24 =0
or, 7y(4y - 3) -8(4y - 3) = 0
or, (7y - 8) (4y - 3) = 0
y = 8/7, 3/4
x ≥ y