Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-8):
Here in Scoring Part we are providing 10 Questions in simplification, 10 Questions in Approximation, 5 Questions in number Series and 5 Questions in Quadratic Equations, total 30 questions in 20 Minutes. By practicing these questions regularly you can increase your calculation speed and it will help you to increase your score.
Dear Readers, Nowadays most of the aspirants are facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.
Here in Scoring Part we are providing 10 Questions in simplification, 10 Questions in Approximation, 5 Questions in number Series and 5 Questions in Quadratic Equations, total 30 questions in 20 Minutes. By practicing these questions regularly you can increase your calculation speed and it will help you to increase your score.
Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). 321 × 9 ÷ 0.8 = √? × 11.25
1). Answer: c)
√? = 321 × 9 / (0.8 × 11.25) = 321
? = (321)^2
? = 103041
2. 78.54 ÷ 0.03 + 22.8 ÷ 0.8 - 1470 × 1.25 = ?√? = 321 × 9 / (0.8 × 11.25) = 321
? = (321)^2
? = 103041
2). Answer: a)
? = 2618 + 28.5 - 1837.5
? = 809
3. 44% of 475 + 72% of 55 = 12.5% of ?? = 2618 + 28.5 - 1837.5
? = 809
3). Answer: c)
12.5 × ? / 100 = 44 × 475 /100 + 72 × 55 / 100
12.5 × ? / 100 = 209 + 39.6 = 248.6
? = 24860 / 12.5 = 1988.8
12.5 × ? / 100 = 44 × 475 /100 + 72 × 55 / 100
12.5 × ? / 100 = 209 + 39.6 = 248.6
? = 24860 / 12.5 = 1988.8
4. (³√7)^1/2 ÷ (343)^-1/2 × (³√7)^2 = (³√7)^?
4). Answer: b)
(³√7)^1/2 ÷ (73)^(-1/2) × (³√7)^2 = (³√7)^?
(7)^(1/6) ÷ (7)^(-3/2) × (7)^(2/3) = (7)^(?/3)
(7)^( 1/6 + 3/2 + 2/3) = (7)^(?/3)
(7)^(14/6) = (7)^(?/3)
(7)^(7/3) = (7)^(?/3)
? = 7
(³√7)^1/2 ÷ (73)^(-1/2) × (³√7)^2 = (³√7)^?
(7)^(1/6) ÷ (7)^(-3/2) × (7)^(2/3) = (7)^(?/3)
(7)^( 1/6 + 3/2 + 2/3) = (7)^(?/3)
(7)^(14/6) = (7)^(?/3)
(7)^(7/3) = (7)^(?/3)
? = 7
5). 8 5/8 × 3 3/23 + 7 1/5 × 4 2/9 = ?
5). Answer: e)
? = 69 / 8 × 72 / 23 + 36 / 5 × 38 / 9
? = 27 + 152 / 5
? = (135 + 152) / 5 = 287 / 5
? = 57 2/5
? = 69 / 8 × 72 / 23 + 36 / 5 × 38 / 9
? = 27 + 152 / 5
? = (135 + 152) / 5 = 287 / 5
? = 57 2/5
6. 252 / ? = ? / 63
6). Answer: b)
?^2 = 252 × 63
?^2 = 9 × 7 × 4 × 7 × 9
?^2 = (2 × 7 × 9)^2
? = 2 × 7 × 9 = 126
?^2 = 252 × 63
?^2 = 9 × 7 × 4 × 7 × 9
?^2 = (2 × 7 × 9)^2
? = 2 × 7 × 9 = 126
7. 3 / 7 of 504 ÷ 12 + 17 = √?
7). Answer: a)
√? = 18 + 17 = 35
? = (35)^2 = 1225
√? = 18 + 17 = 35
? = (35)^2 = 1225
8. 82 + 4 × 3.75 – 16 = √?
8). Answer: c)
√? = 82 + 15 - 16 = 81
? = (81)^2 = 6561
9. {5√27}^3 × 81 ÷ 1 / (3)^1/5 = 9^?√? = 82 + 15 - 16 = 81
? = (81)^2 = 6561
9). Answer: c)
9^? = (27)^(3/5) × (3)^4 ÷ (3)^(-1/5)
9^? = (3)^((9/5) + 4 + (1/5)) = 3^6
9^? = 9^3
? = 3
9^? = (27)^(3/5) × (3)^4 ÷ (3)^(-1/5)
9^? = (3)^((9/5) + 4 + (1/5)) = 3^6
9^? = 9^3
? = 3
10. 7.85% of 1240 + 3.6% of 850 = 20% of ?
10). Answer: d)
20 × ? /100 = 7.85 × 1240 / 100 + 3.6 × 850 / 100
20 × ? /100 = 97.34 + 30.6 = 127.94
? = 12794 / 20
? = 639.7
20 × ? /100 = 7.85 × 1240 / 100 + 3.6 × 850 / 100
20 × ? /100 = 97.34 + 30.6 = 127.94
? = 12794 / 20
? = 639.7
Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11.√4355 + 1204.04 / 6.978 × 14.95 = ?
11). Answer: a)
? ≈ 66 + 1204 / 7 × 15
? = 66 + 2580
? = 2646 ≈ 2650
? ≈ 66 + 1204 / 7 × 15
? = 66 + 2580
? = 2646 ≈ 2650
12. 217% of 8458 = ?
12). Answer: b)
? = 217 × 8458 /100
? = 18353.86 ≈ 18350
13. √3020 × ? = 64400? = 217 × 8458 /100
? = 18353.86 ≈ 18350
13). Answer: c)
? ≈ 64400 / 55 = 1170.9 ≈ 1170
14. 45.145 + 13.92 × 15.05 + 148.08 ÷ 3.97 = ?? ≈ 64400 / 55 = 1170.9 ≈ 1170
14). Answer: c)
? = 45 + 14 × 15 + 148 ÷ 4
? = 45 + 210 + 37 = 292 ≈ 290
15. 148% of 1749 - 14.99 × 16.02 = ?? = 45 + 14 × 15 + 148 ÷ 4
? = 45 + 210 + 37 = 292 ≈ 290
15). Answer: c)
? ≈ 148 × 1750 /100 – 15 × 16
? = 2590 - 240 = 2350
16. (0.00072 ÷ 0.000015) × 5.00005 = ?? ≈ 148 × 1750 /100 – 15 × 16
? = 2590 - 240 = 2350
16). Answer: c)
? ≈ 48 × 5 = 240
17. 137% of 1285 = ?? ≈ 48 × 5 = 240
17). Answer: d)
? = 137 × 1285 / 100
? = 1760.45 ≈ 1760
18. √2300 = ?? = 137 × 1285 / 100
? = 1760.45 ≈ 1760
18). Answer: d)
(48)^2 = 2304
Therefore, √2300 ≈ 48
(48)^2 = 2304
Therefore, √2300 ≈ 48
19. 3.068% of 798 + 5.958% of 1089 = ?
19). Answer: b)
? ≈ 3 × 800 / 100 + 6 × 1100 / 100
? = 24 + 66 = 90
? ≈ 3 × 800 / 100 + 6 × 1100 / 100
? = 24 + 66 = 90
20. 13.023 × 102.68 + 197.68 × 12.05 = ?
20). Answer: c)
? ≈ 13 × 103 + 198 × 12
? = 1339 + 2376 = 3715 ≈ 3700
Direction (21 – 25): What value should come in place of the question mark (?) in the following number series?21. 59.76, 58.66, 56.46, 52.06, ?, 25.66? ≈ 13 × 103 + 198 × 12
? = 1339 + 2376 = 3715 ≈ 3700
21). Answer: d)
The sequence in the series is - 1.1, - 2.2, - 4.4, - 8.8, - 17.6
The sequence in the series is - 1.1, - 2.2, - 4.4, - 8.8, - 17.6
22. 36, 157, 301, 470, ?, 891
22). Answer: e)
The sequence in the series is +11^2, +12^2, +13^2, +14^2, +15^2, ….
The sequence in the series is +11^2, +12^2, +13^2, +14^2, +15^2, ….
23. 14, 70, 350, ?, 8750, 43750
23). Answer: c) The series is x 5, x 5, x 5, ……
24. 13, 13, 65, 585, 7605, 129285,?24). Answer: d)
The sequence in the series is x 1, x 5, x 9, x 13, x 17, x 21, ...
[Here, the difference between the multiplier is 4. i.e. 5 -1, 9 - 5, 13 - 9, 17 – 13,…]
The sequence in the series is x 1, x 5, x 9, x 13, x 17, x 21, ...
[Here, the difference between the multiplier is 4. i.e. 5 -1, 9 - 5, 13 - 9, 17 – 13,…]
25. 1, 16, 81, 256, 625, 1296, ?
25). Answer: b)
The series is, 1^4, 2^4, 3^4, 4^4, 5^4, 6^4, 7^4 (= 2401)
The series is, 1^4, 2^4, 3^4, 4^4, 5^4, 6^4, 7^4 (= 2401)
Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) If p is greater than q.
b) If p is smaller than q.
c) If p is equal to q.
d) If p is either equal to or greater than q.
e) If p is either equal to or smaller than q.
II. 20q^2 + 9q = - 1
26).Answer: b)
I. 6p^2+5p+1=0
(3p+1)(2p+1)=0
p = -1/3,-1/2
II. 20q^2+9q+1=0
(4q+1)(5q+1)=0
q = -1/4, -1/5
∴p < q
I. 6p^2+5p+1=0
(3p+1)(2p+1)=0
p = -1/3,-1/2
II. 20q^2+9q+1=0
(4q+1)(5q+1)=0
q = -1/4, -1/5
∴p < q
27.I. 3p^2 + 2p – 1 = 0
II. 2q^2 + 7q + 6 = 0
27). Answer: a)
I. 3p2+2p-1=0
(3p-1)(p+1)=0
p = 1/3, -1
II. 2q^2+7q+6=0
(2q+3)(q+2)=0
q = -3/2, -2
∴p > q
28. I. 3p^2 + 15p = - 18I. 3p2+2p-1=0
(3p-1)(p+1)=0
p = 1/3, -1
II. 2q^2+7q+6=0
(2q+3)(q+2)=0
q = -3/2, -2
∴p > q
II. q^2 + 7q + 12 = 0
28). Answer: d)
I. 3p^2+15p+18=0
(3p+6)(p+3)=0
p = - 2, - 3
II. q^2+7q+12=0
(q+4)(q+3)=0
q = - 3, - 4
∴p ≥ q
29. I. p = √4 /√9I. 3p^2+15p+18=0
(3p+6)(p+3)=0
p = - 2, - 3
II. q^2+7q+12=0
(q+4)(q+3)=0
q = - 3, - 4
∴p ≥ q
II. 9q^2 - 12q + 4 = 0
29). Answer: c)
I. p = √4 / √9 = 2/3
II. 9q^2-12q+4=0
(3q-2)^2=0
q = 2/3, 2/3
∴p = q
30.I. p^2 + 13p + 42 = 0I. p = √4 / √9 = 2/3
II. 9q^2-12q+4=0
(3q-2)^2=0
q = 2/3, 2/3
∴p = q
II. q^2 = 36
30). AAnswer: e)
P^2+13p+42=0
(p+7)(p+6)=0
p = - 6, - 7
II. q^2 = 36
q = ±6
∴p ≤ q
P^2+13p+42=0
(p+7)(p+6)=0
p = - 6, - 7
II. q^2 = 36
q = ±6
∴p ≤ q
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