Crack IBPS Exam 2017 - Reasoning Ability Scoring Part (Day-6):
Dear Readers, Nowadays most of the aspirants are facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.
Here in Scoring Part we are providing 15 Questions in Puzzles, Sitting Arrangements, 5 Questions in (Inequality, Coding, Alphanumeric, and Syllogism), and total 20 questions in 20 Minutes. By practicing these questions regularly you can increase your calculation speed and it will help you to increase your score.
Attempt Reasoning Ability Scoring Part (Day-1)
Attempt Reasoning Ability Scoring Part (Day-2)
Attempt Reasoning Ability Scoring Part (Day-3)
Attempt Reasoning Ability Scoring Part (Day-4)
Attempt Reasoning Ability Scoring Part (Day-5)
Directions(1 - 5): Study the following information carefully and answer the questions given below. Six lecturers - Adhira, Aloka, Aashi, Aashriya, Adhika, and Adhita will go to six different colleges namely CCET, PEC, DCE, UIET, Thapar University and NIT Jalandhar (not necessarily in the same order) to give guest lectures. They take lectures on Machine Design, Manufacturing Process, Theory of Machines, Thermodynamics, Material Design and Fluid Mechanics. They take lectures from Monday to Saturday (not necessarily in the same order).
• Adhira gives guest lecture in UIET either in Machine Design or Fluid Mechanics.
• Adhika did not give lecture on Fluid Mechanics
• Aashi takes lecture on Tuesday and she is not an expert in Machine Design or Theory of Machines.
• The lecturer who takes guest lecture on Thermodynamics went on Saturday and neither in CCET nor in PEC.
• Adhita delivers her lecture on Manufacturing Process in NIT Jalandhar but not on Wednesday.
• Adhika delivers a guest lecture at DCE and takes lecture one day before Adhita
• On first day of the week, Aloka gives guest lecture in PEC.
• The lecturer who delivers the lecture on Thursday is not an expert in Theory of Machines or Machine Design.
• The lecturer who delivers the lecture on Thursday is not Adhita.
1.Where did Aashriya gave her lecture?
2. Theory of Machines was taught on which day?
2). Answer is: A)
3. Which of the following combination is correct?
3). Answer is: B)
4.Who gave the lecture between Tuesday and Thursday?
4). Answer is: C)
5. Which subject’s lecture was given between that of theory of Machines and Machine Design?5). Answer is: D)
Directions (6-10): Study the following information carefully and answer the given questions.Eight Delegates: A, B, C, D, E, F, G and H are seated around a round table facing the centre. All of them can speak some languages: French, Japanese, English, German, Italian, Sanskrit, Hindi and Portuguese. A delegate knows at least 2 languages and a maximum of three languages. Any language can be spoken by a maximum of 3 delegates. The neighbouring delegates have only one common language in order to communicate with each other. Only neighbours communicate with each other. Not more than 3 people in a sequence can speak the same language.
• A speaks 3 languages French, Japanese and English. A and H are the only 2 persons speaking French.
• A is seated opposite to the one who does not speak English.
• G converses with C in Hindi and with B in Italian.
• B and D converse in English and D is to the right of B.
• E speaks only Portuguese and Sanskrit and is seated opposite to the one who speaks German, English and Sanskrit.
• A is seated between F and H.
• F speaks 2 languages, German being one of them. Apart from F only one other person can speak German.
• Not more than 2 delegates can speak Japanese, Italian, Portuguese and Hindi.
• C does not speak Sanskrit.
• Only 2 delegates knows three languages.
6. What is the position of F with respect to the one who speaks Sanskrit, English and German?
7. Who is the person other than E who speaks Portuguese?
7). Answer is: C)
8. Which of the following language is spoken by F?8). Answer is: C)
9.Which of the following delegates speaks Sanskrit?9). Answer is: A)
10.Which of the following is correct combination of delegate: Languages?
10). Answer is: C)
Directions (11-15): Study the following information carefully and answer the given questions: Padhu, Padma, Padhran ,Pahal , Padmanaban, Prem and Prema are seven students studying in three different institutes - A, B and C. There are three girls among the seven students who study in each of the three institutes. There are atleast two students in each college. Two of the seven students study BCA, two study Medicine and one each studies Aviation Technology, Journalism and MBA. Padhran studies in the same college as Padhu, who studies MBA in college B. No girl studies Journalism or MBA. Padmanaban studies BCA in college A and his brother Prem studies Aviation Technology in college C. Pahal studies Journalism in the same college as Padma. Neither Padhran nor Prema studies BCA. The girl who studies BCA does not study in college C.11.Which of the following pairs of students study Medicine?
11).
Answer: E)
12. In which college does Padma study?
Padhran (-)
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Journalism
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Padmanaban (+)
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12). Answer is: A)
13. In which college do three of them study?
13). Answer is: A)
14.What is the field of study of Prema?
14). Answer is: D)
15. Which of the following three represents girls?15). Answer: B)
Directions (Q.16-20): In each question three statements followed by three conclusions numbered I, II and III have been given. You have to take the given statements to be true even if they seem to be at variance with commonly known facts and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.16. Statements:
Some chillies are potatoes.
No chilli is a tomato.
All potatoes are gingers.
Conclusions:
I. All gingers being chillies is a possibility.
II. At least some tomatoes are not chillies.
III. Some potatoes are not tomatoes.
16).Some chillies are potatoes (I) + All potatoes are gingers (A) = I + A = I = Some chillies are gingers (I). Thus the given possibility between gingers and chillies exists. Hence conclusion I follows.
Again, No chilli is a tomato (E) -> conversion -> No tomato is a chilli (E). Hence conclusion II follows.
Some chillies are potatoes (I) -> conversion -> Some potatoes are chillies (I) + No chilli is a tomato (E) = I + E = O = Some potatoes are not tomatoes (O). Hence conclusion III follows.
Answer: C)
17. Statements:Again, No chilli is a tomato (E) -> conversion -> No tomato is a chilli (E). Hence conclusion II follows.
Some chillies are potatoes (I) -> conversion -> Some potatoes are chillies (I) + No chilli is a tomato (E) = I + E = O = Some potatoes are not tomatoes (O). Hence conclusion III follows.
Answer: C)
All violets are slates.
No wallet is a slate.
Some violins are violets.
Conclusions:
I. Some violins are not wallets.
II. All violets being wallets is a possibility.
III. All slates being violins is a possibility.
17).Some violins are violets (I) + All violets are slates (A) = I + A = I = Some violins are slates (I) + (No wallet is a slate (E) conversion ->) No slate is a wallet (E) I + E = O = Some violins are not wallets. Hence conclusion I follows.
All violets are slates (A) + (No wallet is a slate (E) -> conversion ->) No slate is a wallet (E) = A + E = E = No violet is a wallet. Hence conclusion II does not follow. Some violins are slates. Hence, conclusion III follows.
Answer: E)
Directions (Q.18-19):Statements:All violets are slates (A) + (No wallet is a slate (E) -> conversion ->) No slate is a wallet (E) = A + E = E = No violet is a wallet. Hence conclusion II does not follow. Some violins are slates. Hence, conclusion III follows.
Answer: E)
All dialogues are voices.
Some speeches are dialogues.
No word is a speech.
18. Conclusions:
I. Some voices are not words.
II. All words being dialogues is a possibility.
III. No speech is a word.
18). Some speeches are dialogues(I) + All dialogues are voices (A) = I + A = I = Some speeches are voices (I) -> conversion -> Some voices are speeches (I) + (No word is a speech (E) -> conversion -> No speech is a word (E) = I + E = O = Some voices are not words. Hence conclusion I follows.
Some speeches are dialogues -> conversion -> Some dialogues are speeches (I) + (No word is a speech ->conversion ->) No speech is a word (E) = I + E = O = Some dialogues are not words. Hence conclusion II follows.
No word is a speech (E) -> conversion -> No speech is a word (E). Hence conclusion III follows.
Answer: e)
19. Conclusions:Some speeches are dialogues -> conversion -> Some dialogues are speeches (I) + (No word is a speech ->conversion ->) No speech is a word (E) = I + E = O = Some dialogues are not words. Hence conclusion II follows.
No word is a speech (E) -> conversion -> No speech is a word (E). Hence conclusion III follows.
Answer: e)
I. Some words are not dialogues.
II. Some voices are speeches.
III. Some dialogues are speeches.
19).Some speeches are dialogues (I) -> conversion -> Some dialogues are speeches (I) + No speech is a word (E) = I + E = O = Some dialogues are not words (O) -> conversion -> No conversion. Hence conclusion I does not follow. Some speeches are dialogues (I) +All dialogues are voices (A) = I + A = I = Some speeches are voices (I) -> conversion -> Some voices are speeches (I). Hence conclusion II follows.
Some speeches are dialogues (I) -> conversion -> Some dialogues are speeches (I). Hence conclusion III follows.
Answer: A)
Some speeches are dialogues (I) -> conversion -> Some dialogues are speeches (I). Hence conclusion III follows.
Answer: A)
20.Statements:
Some streets are cities.
All towns are markets.
No city is a market.
Conclusions:
I. No market is a city.
II. All markets being streets is a possibility.
III. No town is a city.
20). No city is a market (E) ->conversion -> No market is a city (E). Hence conclusion I follows.
Some streets are cities (I) + No city is a market (E) = I + E = O = Some streets are not markets. Hence conclusion II follows.
All towns are markets (A) + (No city is a market (E) -> conversion ->) No market is a city (E) = A + E = E = No town is a city (E). Hence conclusion III follows.
Answer is: D)
Some streets are cities (I) + No city is a market (E) = I + E = O = Some streets are not markets. Hence conclusion II follows.
All towns are markets (A) + (No city is a market (E) -> conversion ->) No market is a city (E) = A + E = E = No town is a city (E). Hence conclusion III follows.
Answer is: D)
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