IBPS Clerk/RRB Mains 2016 - Practice Quantitative Aptitude Questions (Arithmetic Questions) Set-67:
Dear Readers, Important Practice Aptitude Questions for IBPS Clerk Mains and Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the examination can use this.
1). Each side of an equilateral triangle is increased by 20%. The percentage increase in its area is-
a) 44%
b) 42%
c) 40%
d) 46%
e) None of these
2).The length of a rectangular plot is 15 metres. If the cost of cultivating the plot at Rs. 13.20 per metres2 is Rs.5346. Find the breadth of plot.
a) 23 m.
b) 25 m.
c) 27 m.
d) 29 m.
e) 30 m.
3). A cistern is constructed to hold 300 litres, and the base of the cistern is one square meter. What is the depth of the cistern? (A cubic metre is equal to 1000 litres.)
a) 35 cm.
b) 30 cm.
c) 40 cm.
d) 45 cm.
e) None of these
4). How many cubic metres of the earth must be dug out to sink a well 22 m. deep. If the cost of plastering the inner surface of the wall at Rs. 23.5 per square meter is Rs. 22748.
a) 8338 m3
b) 3838 m3
c) 3883 m3
d) 3388 m3
e) None of these
5). Find the slant height of a cone whose volume is equal to 3080 m3 and the diameter of whose base is 28 m. (Ans. in approx. value)
a) 18.5 m
b) 20.5 m
c) 23.5 m
d) 26.5 m
e) 29.5 m
6). The probability that a leap year selected at random will contain either 53 Monday or 53 Tuesday is-
a) 1/7
b) 2/7
c) 3/7
d) 4/7
e) None of these
7). A book contains 1000 pages. A page is chosen at random. The probability that the sum of the digits of the marked number on the page is equal to 9.
a) 19/200
b) 17/200
c) 13/200
d) 11/200
e) None of these
8). You are given a box with 30 cards in it. 10 of these cards have letter 'B' printed on them. the other ten have the letter "S" printed on them, and other ten have the letter 'C' printed on them. If you pick up 3 cards at random and keep them. in same order, the probability of making the word 'BSC' is-
a) 25/609
b) 25/690
c) 28/290
d) 25/87
e) None of these
9). If the difference between CI and SI on a certain sum of money for 3 years at 8% per annum is Rs. 308, find the sum.
a) Rs. 15562
b) Rs. 16255
c) Rs. 15625
d) Rs. 16525
e) None of these
10). The simple interest on sum of money will be Rs. 200 after 4 years. In next 8 years principal becomes tripled. What will be the total interest at the end of the 12 year?
a) Rs. 1200
b) Rs. 1400
c) Rs. 800
d) Rs. 1000
e) None of these
1). Area of equilateral triangle = (√3)x2/4
2 x 20+ (202 /100 ) =44% .
Answer: a)
2). Total Area = 5346/13.2 = 405 m2
breadth = (405/15)=27m
Answer: c)
3). 1 sq. m x depth = 300/1000=3/10
or, depth = 3/10 m = (3/10)x 100 = 30cm.
Answer: b)
4). Inner Surface area= 22748/23.8 = 968 sq. m.
2 πrh=968 22 or, 2x 22/7x r x 22= 968
Or, = (968 x 7 ) /(2 x 22 x 22) =7m.
Volume of the earth dugout = volume of the well
=(22 /7) x7x 22 = 3388 cum.
Answer: d)
5). Volumeof cone = 1/3πr2h
(1/3) x (22 /7) x14x14xh=3080
h = (3080x3 x7) / (14 x 1 4 x 22) = 15m.
Slant height (t) = √(142 x 152) = √1(96 x 225)
=√421m = 20.5m
Answer: b)
6). In a leap year 366 day
or, 52 week and 2 days. these 2 days will be
I. Sunday and Monday
2. Monday and Tuesday
3. Tuesday - Wednesday
4. Wednesday - Thursday
5. Thursday - Friday
6. Friday-Saturday
7. Saturday-Sunday
Required Probability = (3/7)
Answer: c)
7). The number of numbers whose sum is 9 is
one digit number =1
Two digit number =9
Three digit number =9 + 8 + 7+ …… + I
(9x10)/2 = 45
Required probability = (1+9+45)/1000 = 55/1000 = 11/200
Answer: d)
8). Required probability= (10/30) x (10/29) x (10/28) = 25/609
Answer: a)
9). Sum= [Difference x (100)2 ] /[ r2 (300+r) ]
= (308x100x100 x 100) / ( 64x308) = Rs. 15625
Answer: c)
10). SI = (PTR )/100
200 = (p x r x 4) / 100
Or, 4 Pr = 200 x 100
SI = (3P x r x 8) / 100 = (3 x 2 x 4 x Pr) / 100
= (6 x 200 x 100) / 1000 = Rs.1200
Total Interest = Rs. 1200+ Rs. 200 = Rs. 1400
Answer: b)
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