IBPS Clerk Mains 2016 - Practice Quantitative Aptitude Questions (Application Sums)

IBPS Clerk/RRB Mains 2016 - Practice Quantitative Aptitude Questions (Application Sums)  Set-65:

Dear Readers, Important Practice Aptitude Questions for IBPS Clerk Mains and Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the examination can use this.

1). A started a business with a sum of Rs.14000. After 4 months, B entered with an amount of Rs. 12000 and A added another 2,000 in the business. After 6 months, C entered with Rs. 20000 and 'B' withdrew Rs. 2000 from the business. What will be C's share of profit out of a total profit of Rs. 94000 at the end of 2 years.

a)   Rs. 376000

b)   Rs. 204000

c)   Rs. 36000

d)   Rs. 18000

e)   Rs. 260000

2). The top of a 15 m. high tower makes an angle of elevation of 60∘ with the bottom of an electric pole and an angle of 30∘ with the top of the pole. What is the height of the pole?

a)   12 m

b)   10 m

c)   11 m

d)   5 m

e)   15 m

3). The product of ages of Harshit and Haritika is 240. If Hritika would have been twice her age she will be 4 years elder to Harshit. What is Haritika's age now?

a)   16 yrs

b)   24 years

c)   12 years

d)   10 years

e)   15 years

4). A rectangular plot has an area of 96 m². A 2 m. broad pathway is constructed around it and the new plot has to be carpeted. The cost of putting carpet is Rs. 42 per square m. what will be the total cost involved in carpetting?

a)   Rs. 4032

b)   Rs. 4200

c)   Rs. 4300

d)   Data inadequate

e)   None of these

5). A man starts walking daily, for the 1st day he walked 2 kms. Everyday he walks half of the distance of the previous day. What is the maximum total distance walked by him in life time?

a)   4 km.

b)   infinite

c)   2 ∞ km.

d)   120 km.

e)   Data inadequate

6). Taps A, B and C are connected to a water tank and the rate of flow of water from them is 42 liter/hr, 56 liter/hr and 48 liter/hr respectively. If tap A and B are filling the tank and C is emptying it and the tank gets filled in 16 hrs. What is the capacity of the tank?

a)   150 liter

b)   960 liter

c)   800 liter

d)   1200 liter

e)   500 liter

7). A square room has a side of 8 m. How many metres of a carpet 16 cm. wide, will be required to cover the floor of the room. If the cost of carpet is Rs.200/m. and labour charge is Rs. 10/m, find the cost of putting the carpet?

a)   400m, Rs. 84000

b)   400 m. , Rs. 80000

c)   200 m. Rs.84000

d)   200 m, Rs. 80000

e)   400 m. Rs.40000

8).What is the maximum volume of the cone that can be cut from a cube of edge 14 cm.?

a)   632.26 cm²

b)   756.14 cm³

c)   814.32 cm³

d)   718.66 cm²

e)   796.33 cm³

9). A room is 10 m long, 8 m broad and 4.5 m high. These are two doors with dimensions 2.5 m × 1.2 m, two windows of dimension 1.5 m × 1.6 m and two more windows of 1 m height and 1 m breadth. Find the area of wallpaper required to cover the room.

a)   152.6 m²

b)   162 m²

c)   149.2 m²

d)   146.2 m²

e)   150 m²

10). How many 6 letter words which begin with 'T' can be formed using the letters of the word EQUATION?

a)   2570

b)   2520

c)   2500

d)   2250

e)   2590

Solution Key:

1). C; Share of profit = Amount invested × time

A = (14000 × 4) + (16000 × 20) = 376000

B = (12000 × 2) + (10000 × 18) = 204000

C = (2000 × 18) = 360000

Ratio of Share = 376 : 204 : 360

:.  C’s share = (94000/940) × 360 = 36000

5). A; Sum of infinite series = a/c where a = 1^st term and

C = common ratio

6). C; Tank filled in one hour = (A + B) – C = (42 + 56) – 48 = 50 liter

So, total time = 16 hr, capacity= 16×50 = 800 liter

7). A; Area of floor = 8× 8 = 64 m² or 64× 100 × 100 cm²

Length of carpet required = (64×100×100)/16 = 400

Cost of carpetting = 400 (200 + 10) = Rs. 84000

8). D; Max. cone àheight of cone = diameter of cone

= edge of cube

:. h = 14 cm, r = 7 cm.

v = (1/3) × (22/7) × 7 ×7×14 = 718.66 cm³

9). C; Area of 4 walls 2 (l + b)× h = 2 (10+8) × 4.5 = 162 m²

Area of doors = 2 × 2.5 × 1.2 = 6 m²

Area of windows = 2× 1.5 × 1.6 = 4.8 m² + 2 × 1 × 1

Area to pe wall papered = 162 – (6 + 6.8) = 149.2 m²

10). B; EQUATION = 8 Letters

Letters in required word = 6 starting from ‘T’

So, ‘T’ will be arranged first and rest 5 has to be selected from 7 letters

:. Total = 7 × 6 × 5 × 4× 3 = 2520

More Practice Aptitude Questions for IBPS RRB/clerk 2016 -Click Here

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