Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-31)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-31):

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Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). (0.04)² ÷ (0.008) * (0.2)⁶ = (0.2)^?

1). Answer: a)
(0.04)² ÷ (0.008) * (0.2)⁶ = (0.2)^?
= 0.2^1 * 0.2⁶ = (0.2)^7

2. 13.141 + 31.417 – 27.118 + 15.247-14.214 = ?

2). Answer: b)
13.141 + 31.417 – 27.118 + 15.247-14.214 = ?
59.805 – 41.332 = 18.473

3. 36 * 14 – 49 * 784÷112

3). Answer: d)
36*14 – 49*784÷112
504 – 343 = 161

4. √676 * 12 – 864 ÷ 36 = ? + 61

4). Answer: b)
√676 * 12 – 864÷36 = ? + 61
x = 227

5). 468 ÷ 39*15 + 166 = (?)³ + 130

5). Answer: b)
12 * 15 + 166 = (?)³ + 130
(?)³ = 216
? = 6

6. 185% of 600 + 25% of 240 = ?% of 1000

6). Answer: c)
185% of 600 + 25% of 240 = ?% of 1000
1110 + 60 = x% of 1000
x = 1170/10 = 117

7. 2/3 of 7/5 of 75% of 640 = ?

7). Answer: b)
2/3 of 7/5 of 75% of 640 = 2/3 * 7/5 * 75/100 * 640 = 64 * 7 = 448

8. 15.4 * 14.5 * x = 2798.75

8). Answer: d)
15.4 * 14.5 * x = 2798.75
x = 2798.75/223.3 = 12.5

9. 7344 + (5.4)² + √? = 7437.16

9). Answer: c)
7344 + (5.4)² + √? = 7437.16
√? = 7408 – 7344 = 64 => ? = 4096

10. 567 ÷ (10.8 * 2.5) ÷ 3 = ?

10). Answer: b)
567 ÷ (10.8 * 2.5) ÷ 3 = ?
? = 567 ÷ (27) ÷ 3 = 7

What approximate value should come in place of question mark (?) in the following questions?
11. 21.003 × 39.998 – 209.91 = 126 × ?

11). Answer: a)
21 × 40 – 210 = 126 × ?
630 = 126 × ?
? = 5 (approx)

12. 1440.0003 ÷ 23.999 × 2.5 × 3 = ?

12). Answer: a)
1440 ÷ 24 × 2.5 × 3 = ?
60 × 2.5 × 3 = 450 (approx)

13. 3995.009 – 290.999 – 129.989 × 2 = ?

13). Answer: b)
3995 – 291 – 130 × 2 = ?
? = 3444
= 3445 (approx)

14. (15)² + (19.99)² + (24.001)² = ?

14). Answer: b)
(15)² + (20)² + (24)² = 225 + 400 + 576 = 1200 (approx)

15. (99999 ÷ 999 ÷ 9) × 99.99 = ?

15). Answer: e)
(99999 ÷ 999 ÷ 9) × 99.99 = 11.12 × 100 = 1110 (approx.)

16. 6575 / 17.98 × 42.03 / 6.87 = ?

16). Answer: a)
6575 / 18 × 42 / 7 = (6575 / 18) × (42 / 7) = 365 × 6 = 2190

17. 12.002 × 15.005 – 8.895 × 6.965 = ?

17). Answer : b)
12 × 15 – 9 × 7 = 180 – 63 = 117

18. 12.664 × 22.009 × 17.932 = ?

18). Answer : c)
13 × 22 × 18 = 5148

19. 16.978 + 27.007 + 36.984 – 12.969 – 9.003 = ?

19). Answer : d)
17 + 27 + 37 – 13 – 9 = 81 – 22 = 59

20. 18% of 602 + 27.8% of 450 = ?

20). Answer : a)
[(18 × 600) / 1000] + [(28 × 450) / 100] = 108 + 126 = 234

Direction (21 – 25): What will come in place of question mark (?) in the following number series?
21. 698, 554, 454, 390, 354, ?

21). Answer: a)
The series is -12^2 -10^2, -8^2,…..

22. 5, 7, 10, 36, 136, ?

22). Answer: c)
The series is * 1 + 2, * 2 – 4, * 3 + 6,…..

23. 2, 11, 46, ?, 286

23). Answer: a)
The series is
2 * 5 + 1 = 11;
11 * 4 + 2 = 46;
46 * 3 + 3 = 141, ….
.

24. 3, 10, 32, ?, 460, 2315

24). Answer: e)
The series is,
3 * 1 + 7 * 1 = 10
10 * 2 + 6 * 2 = 32
32 * 3 + 5 * 3 = 111,…..

25. 6072, ?, 200, 48, 14, 5

25). Answer: b)
The series is, -12 / 6, -10 / 5, -8 / 4, ……

Directions (26-30): In the following questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer.
a) If X > Y
b) If X < Y
c) If X ≥ Y
d) If X ≤ Y
e) If X = Y or cannot be established
26) I. X² – 3X + 2= 0
II. 9Y² – 9Y + 2 = 0

26). Answer: a)
(x-1)(x-2) = 0
X=1,2
(3y-1)(3y-2) = 0
Y =1/2,1/3
Hence, x > y

27). I. X² – 6X + 8= 0
II.Y² – 8Y + 15 = 0

27). Answer: e)
(x-4)(x-2) = 0
X=4,2
(y-5)(y-3) = 0
Y=5,3
Therefore, the relation cannot be established

28). I. 2X² – 3X – 2= 0
II. 6Y² + 7Y + 2 = 0

28). Answer: c)
(x-2)(2x+1) = 0
X = 2,-1/2
(3y+2)(2y+1) = 0
y = -2/3,-1/2
Therefore X ≥ Y

29). I. 2X² + 7X + 6= 0
II. 2Y² + Y – 3 = 0

29). Answer: d)
(x+2)(2x+3) = 0
X= -2,-3/2
(2y+3)(y-1) = 0
Y=1,-3/2
Therefore, y ≥ x

30). I. 6X² + 11X + 3= 0
II. 3Y² – 2Y – 1 = 0

30). Answer: d)
(3x+1)(2x+3) = 0
X= -1/3, -3/2
(y-1)(3y+1) = 0
Y = 1,-1/3
Therefore, y ≥ x

       

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