Special Quant Quiz for SSC CGL 2016

For the first time SSC examination will be held in Computer Based pattern and managing time will be one of the important factor while solving the questions. So in order to make students familiar with such a situations we are providing questions in a time based manner , which will help students to manage the time properly.

1. A is 2 1⁄3 times as fast as B. If A gives B a start of 80 m, how long should the race course be so that both of them reach at the same time?

170 m

150 m

140 m

160 m

Solution:

Sol 1(C): Speed of A : Speed of B = 7⁄3 : 1 = 7 : 3
It means, in a race of 7 m, A gains (7-3)=4 m
If A needs to gain 80 m, race should be of 7/4×80 = 140 m

2. A can run 224 metre in 28 seconds and B in 32 seconds. By what distance A beat B?

36 m

24 m

32 m

28 m

Solution: 2(D). Clearly, A beats B by 4 seconds

Now find out how much B will run in these 4 seconds
Speed of B =224/32=7 m/s
Distance covered by B in 4 seconds = Speed × time =7×4=28 m

3. In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:

21 m

28 m

26 m

29 m

Solution: 3(B) When A covers 100 m,  B covers (100-25)=75 m

When B covers 100 m, C covers (100-4)=96 m
=> When B covers 75 metre, C covers 96/100×75=72 m
i.e., When A covers 100 m, B covers 75 m and C covers 72 m
=> In a 100 m race, A beat C by (100-72)=28 m

4. A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is:

4.4 kmph

4.25 kmph

4.14 kmph

5.15 kmph

Solution: 4(c) speed of A = 5 kmph = 5×5/18=25/18m/s
Time taken by A to cover 100 m=distance/speed=100/(25/18) = 72 seconds
It is given that, A gives B a start of 8 m and still beats him by 8 seconds.
=> B takes (72+8)=80 seconds to cover (100-8)=92 metre
Speed of B =distance/time=92/80m/s=92/80×18/5 kmph = 4.14 kmph

5. The elevation of the summit of a mountain from its foot is 45°. After ascending 2 km towards the mountain upon an incline of 30°,the elevation changes to 60°. What is the approximate height of the mountain?

1.2 km

0.6 km

1.4 km

2.7 km

Solution:

6. An aero plane when 900 m high passes vertically above another aero plane at an instant when their angles of elevation at same observing point are 60° and 45° respectively. Approximately, how many meters higher is the one than the other?

381 m

169 m

254 m

211 m

Solution:

7.In how many different ways can the letters of word ‘PREVIOUS’ be arranged in such a way that the vowels always come together?

50400

4840

3260

2880

Solution: 7(D) Total letters are ‘8’ and No of vowels = 4
So total no of ways=5! * 4! = 2880

8. A square park is surrounded from outside by a path of 5 meters width. If the area of the path is 1700sq meters, then what is the area of the park?

3600sq m

4900sq m

5625sq m

6400sq m

Solution:

9. To Finish a work, B will take three times as long as A and C together and C will take twice as long as A and B together. If the three persons A, B and C together can finish the work in 20 days , then how long will A take to finish the work alone?

30 days

45 days

48 days

60 days

Solution:

9. (C) 3*B’s daily work= (A+C)’s daily work
4*B’s daily work = (A+B+C)’s daily work = 1/20
 B’s daily work = 1/80 2*C’s daily work = (A+B)’s daily work
 3*C’s daily work = (A+B+C)’s daily work = 1/20
C’s daily work= 1/60
A’s daily work= 1/20 - (1/80 + 1/60) = 1/48
A can finish the work in 48 days.

10.The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is:

15360

153600

30720

307200

Solution:

10(B) Perimeter = Distance covered in 8 min. =(12000/60x 8)m = 1600 m.
Let length = 3x metres and breadth = 2x metres.
Then, 2(3x + 2x) = 1600 or x = 160.
 Length = 480 m and Breadth = 320 m.
 Area = (480 x 320) m2 = 153600 m^2