Tricks to solve Percentage Problems - PDF

July 29, 2015    

Percentage is a fraction whose denominator is always 100. x percentage is represented by x%.

To express x% as a fraction : 

x% = x/100
Thus 10% = 10/100 (means 10 parts out of 100 parts)
= 1/10 (means 1 part out of 10 parts)

To express x/y as a percentage :

We know that x/y  = (x/y× 100 )
Thus 1/4 = ( 1/4 ×100 )% = 25%
and 0.8 = ( 8/10 ×100 )% = 80%

If the price of a commodity increases by R%, then reduction in consumption as not to increase the expenditure is-

[ R/(100+R)×100 ] %

If the price of a commodity decreases by R%, then the increase in consumption as not to decrease the expenditure is -

[ R/(100-R)×100 ] %

Result on Population : 

Let the population of a town be P now and suppose increases the rate of R% per annum, then :
  1. Population after n years = P ( 1+ R/100 )n 
  2. Population  n years ago = P /( 1+ R/100 )n 

Result on Depreciation : 

Let the present value of a machine be P. Suppose depreciates at the rate of R% per annum Then :
1. Value of the machine after n Years 
 = P ( 1- R/100 )n 
2. Value of the machine n years ago
P /( 1- R/100 )n 
  • If A is R% more than B, then B is less than A by
[ R/(100+R)×100 ]%
If A is R% less than B, then B is more than A by
[ R/(100-R)×100 ]%
  • Net % change = x + y + xy/100

Some Observation

#1 

If 20% candidate failed in an exam then observations are
  • 80% represent passed in exam
  • 100% represent total appeared in exam
  • (80%-20%) = 60% represent difference between passed and failed candidate in exam
percentage

#2

 If a number is increased by 25% then observations are 
  • 100% represent the old number
  • 125% represent the new number.

percentage concept

#3

 Remember that Base in the given sentence (Question) is always 100%
Eg. Income of Ram is increased by 20% 
In this sentence 
100% - represent the income of Ram
20% - represent increment
120% - represent new income of Ram.

Remember it :

1/3 = 33 1/3%
1/6 = 162/3%
1/7 = 142/7%
1/8 = 121/2%
1/9 = 111/3%
1/10 = 10%
1/11 = 91/11%
1/10 = 81/3%
1/13% = 79/13%
percentage problems
6.25% = 1/16
125% = 5/4
150% = 3/2
350% = 7/2

Examples

#1 

Q. If the difference between 62% of a number and 3/5th of that number is 36. what is the number ?
Let the number be x.
Then x × 62% - x × 3/5 = 36
x ×62% -x V 60% = 36 (60% = 3/5)
x ×2% = 36
x ×2/100 =36
x = 36 ×100/2 = 1800
Q. 40% of Ram's income Rs. 1200 Then Find 
  1. 75% of Ram's income ?
  2. 1/4 part of Ram's income ?
  3. 1/3 part of Ram's income ?
Sol :
40% = 1200 Rs.
75% = 1200/40 ×75 = 2250 Rs.

Trick : 1200 / 40  × 75 = Rs. 2250/-

40% of income = Rs. 1200
Then 1/4 part (i.e. 25% ) of Ram's
income = 1200/40 ×25 
= Rs. 750/- Ans
40% of Ram's income
= Rs. 1200
i.e. 2/5 part of Ram's income
= Rs. 1200
Then total income of Ram 
= Rs. 1200 ×5/2
1/3 part of Ram's income
= Rs. 1200  × 5/2  × 1/3 
= Rs. 1000 Ans.
1200/2/5  × 1/3
= 1200/2 × 5/3 = 1000

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Tricks to solve Percentage Problems - PDF 4.5 5 Yateendra sahu July 29, 2015 Percentage is a fraction whose denominator is always 100. x percentage is represented by x%. To express x% as a fraction :  x% = x /100 ...


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