Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.
Directions (1-5): Study the pie charts carefully to answer the questions that follow. Percent wise distribution of players (Male and Female) and female players who play five different sports-
Note- Some values are missing, you have to calculate these values as per given data.
Q1. What is the approximate average number of female players who play football, Hockey and Lawn Tennis together?
620
333
230
630
340
Q2. What is the difference between the number of the male players who play football and the number of male players who play Cricket? 94
84
216
240
184
Solution:
Number of males who play Football = 714 – 260 = 454
Number of males who play Cricket = 1470 – 800 = 670
Difference = 670 – 454 =216
Number of males who play Cricket = 1470 – 800 = 670
Difference = 670 – 454 =216
Q3. What is the respective ratio of the number of male players who play cricket and number of female players who play Hockey?
20 : 7
4 : 21
20 : 3
3 : 20
None of these
Q4. What is the total number of female players who play football, cricket and Hockey together? 1224
1334
1424
1564
1360
Solution:
Total number of females who plays Football, Cricket and Hockey = 260 + 800 + 300
= 1360
= 1360
Q5. Number of female players who play Lawn Tennis is approximately what per cent more than the total number of players who play Hockey?
4%
5%
4.8%
5.5%
6.5%
Directions (6-10): Read the following graph carefully and answer the questions given below: The line graph shows the percentage distribution of total number of students who got placed successfully in campus placement after their graduation from six different universities while the table provides their female to male ratio. Total placed students are 42500 and 44000 in 2015 and 2016 respectively.
Q6. Total number of females placed from University B in 2015 are what percent of total males placed from University C in same year ?
54.8%
55%
58.8%
60%
62.5%
Q7. Find the difference between total females placed from D in both years and that of from E in both years. 7040
7470
7740
7570
7077
Q8. What is the ratio of male students from F in 2015 and that of from C in 2015 who got placement ? 3 : 4
3 : 1
4 : 3
1 : 3
1 : 6
Q9. Find the average number of placed students from all universities except D in 2015. 6790
6970
6975
7690
9670
Q10. Female students placed from E in 2015 are what percent less than that of from A in 2016 ? 25%
20%
15%
12%
None of the above
Directions (11 - 15)∶ Given below the pie chart shows percentage distribution of viewers of a Tv channel in five different villages (A, B, C, D & E) and table shows number of viewers who subscribed the channel. Read the data carefully and answer the questions. Note – Total viewers = Total subscriber + Total unsubscribe
Q11. Total unsubscribed viewers from B & E together is what percent more than total unsubscribed viewers from C?
50%
55%
45%
40%
42%
Q12. If total male unsubscribed viewers in D is 5:12
25:54
54:7
25:36
54:25
Q13. Find the total unsubscribed viewers in B & C and total subscribed viewers in E together? 825
475
655
745
780
Q14. Out of total viewers in village C , 170
180
210
190
250
Q15. Find the difference between the total number of subscribed viewers from C and D together and the total number of subscribed viewers from A and E together. 280
390
425
250
350
Solution:
Total subscribed viewers from village C and D together = 440+350 = 790
Total subscribed viewers from village A and E together = 220 + 180 = 400
Required difference = 790 – 400 = 390
Total subscribed viewers from village A and E together = 220 + 180 = 400
Required difference = 790 – 400 = 390

No comments:
Post a Comment