Hello Aspirants,
WHAT IS NORMALIZATION IN SCORE? WHY IS IT NEEDED?
SSC CGL 2018 Notification attributes Normalization in score attained by candidates. This practice by SSC is highly commendable for the sake of parity in exam selection procedure. Previously, Normalization in Score was a unison demand by aspirants as Exam level in different shifts often seem to be varied. Some aspirants with hard luck happen to fall for difficult question set in Exam whereas some other aspirants get an easy level Question Set comparatively. Therefore, this brings a disparity and cause muddling in mindset of candidates in final exam merit thus begetting a dissatisfaction and impiety in the Commission. Where a number of aspirants are already aware of Normalization process, there seem to be a good number of aspirants for whom normalization in score is almost a ‘never heard before term’. To enlighten these aspirants with part and parcel details regarding Normalization Process in a particular Exam, SSCADDA is all set once again to elucidate your doubts in the most convenient way.
Many a time aspirants come out with this question that they happened to appear for the shift in which question set was of difficult level, either it being Quantitative Aptitude Section where question might be more lengthy and calculative in some particular shifts, or General Awareness Section where candidates might find most of the questions invincible or English Language Section where some shifts might bring out a typical and intricated questions, and in such case are not those candidates at a disadvantage over those candidates who luckily got an easier level Paper Set and thus prone to failure. In such a scenario normalization of marks is the most effective tool to clear any dispute between the difficulty levels of papers. Because it is near to impossible that all Exam Shifts Paper Sets would belong to an identical level and nature of questions. The organization may add a mark or two in the total score of the candidate if the paper of his shift was very difficult in comparison to other shifts or may deduct a mark or two in the reverse scenario subject to their rules, formula, and guidelines for normalization.
The normalization process is based on a formula and based on a few other parameters decided by the authority, the Exam organizing committee derives the formula for calculating the normalized marks for the multi-session papers. For different exam pattern, there is a different formula for normalization of marks. To bring transparency, win faith of candidates, maintain the sanctity of Commission and conduct a fair competition, Normalization in Score is a remedy.
To make you understand the normalization process in the simplest way. We assume three shifts of CGL exam on any given day. Taking sample marks of 5 different candidates in the account, watch out for below explanation.
Now suppose, candidates of shift-1 get 80, 85, 90, 95 and 100 marks.
Candidates of shift-2 get 110, 115, 120, 125 and 130 marks.
Candidates of shift-3 get 90, 95, 100, 105, 110 marks.
Owing to different level of Exam Shifts, difference in the marks of candidates are observable. Now we find the MEAN equal to 90 marks in the first Shift and proceeding ahead the same way for Second Shift, we get mean equal to 120 marks. So, the difference in the MEAN of shift-1 and shift-2 is 30. If we add 30 marks to the marks of the first shift candidates, the new normalized marks will be (80+30=110), (85+30=115), (90+30=120), (95+30=125) and (100+30=130) which is now equivalent to shift-2 marks. Hence, shift-1 and shift-2 marks are equal now.
In the same way, we can normalize the marks of the second shift and third shift candidates. In the second shift, MEAN of the marks is 120, and in the third shift, MEAN of the marks will be 100, so the difference in the MEAN marks is 20, if we add 20 to the marks of shift -3 candidates, we get (90+20=110), (95+20=115), (100+20=120), (105+20=125) and (110+20=130)
Now it is easy to perceive that marks of the shift-2 and shift-3 candidates are equal (normalized). So far it is the simplest way to understand the normalization in a brief way. This method is called MEAN method. We hope this helps you to understand the process of normalization in competitive exams and expunge your doubts regarding Normalization in Score to an extensive level.
Many a time aspirants come out with this question that they happened to appear for the shift in which question set was of difficult level, either it being Quantitative Aptitude Section where question might be more lengthy and calculative in some particular shifts, or General Awareness Section where candidates might find most of the questions invincible or English Language Section where some shifts might bring out a typical and intricated questions, and in such case are not those candidates at a disadvantage over those candidates who luckily got an easier level Paper Set and thus prone to failure. In such a scenario normalization of marks is the most effective tool to clear any dispute between the difficulty levels of papers. Because it is near to impossible that all Exam Shifts Paper Sets would belong to an identical level and nature of questions. The organization may add a mark or two in the total score of the candidate if the paper of his shift was very difficult in comparison to other shifts or may deduct a mark or two in the reverse scenario subject to their rules, formula, and guidelines for normalization.
The normalization process is based on a formula and based on a few other parameters decided by the authority, the Exam organizing committee derives the formula for calculating the normalized marks for the multi-session papers. For different exam pattern, there is a different formula for normalization of marks. To bring transparency, win faith of candidates, maintain the sanctity of Commission and conduct a fair competition, Normalization in Score is a remedy.
To make you understand the normalization process in the simplest way. We assume three shifts of CGL exam on any given day. Taking sample marks of 5 different candidates in the account, watch out for below explanation.
| S. No. | Candidate-1 | Candidate-2 | Candidate-3 | Candidate-4 | Candidate-5 |
|---|---|---|---|---|---|
| Shift-1 | 80 | 85 | 90 | 95 | 100 |
| Shift-2 | 110 | 115 | 120 | 125 | 130 |
| Shift-3 | 90 | 95 | 100 | 105 | 110 |
Now suppose, candidates of shift-1 get 80, 85, 90, 95 and 100 marks.
Candidates of shift-2 get 110, 115, 120, 125 and 130 marks.
Candidates of shift-3 get 90, 95, 100, 105, 110 marks.
Owing to different level of Exam Shifts, difference in the marks of candidates are observable. Now we find the MEAN equal to 90 marks in the first Shift and proceeding ahead the same way for Second Shift, we get mean equal to 120 marks. So, the difference in the MEAN of shift-1 and shift-2 is 30. If we add 30 marks to the marks of the first shift candidates, the new normalized marks will be (80+30=110), (85+30=115), (90+30=120), (95+30=125) and (100+30=130) which is now equivalent to shift-2 marks. Hence, shift-1 and shift-2 marks are equal now.
In the same way, we can normalize the marks of the second shift and third shift candidates. In the second shift, MEAN of the marks is 120, and in the third shift, MEAN of the marks will be 100, so the difference in the MEAN marks is 20, if we add 20 to the marks of shift -3 candidates, we get (90+20=110), (95+20=115), (100+20=120), (105+20=125) and (110+20=130)
Now it is easy to perceive that marks of the shift-2 and shift-3 candidates are equal (normalized). So far it is the simplest way to understand the normalization in a brief way. This method is called MEAN method. We hope this helps you to understand the process of normalization in competitive exams and expunge your doubts regarding Normalization in Score to an extensive level.
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