Dear Readers, Important Practice Reasoning Questions with explanation for IBPS Exams 2017 was given here with explanation, candidates those who are preparing for Banking and all other Competitive exams can use this practice questions.
Direction (Q.1-5): Study the following information carefully and answer the questions given below.
$ 5 G A H 8 # 3 U S 9 Ω W 7 E J Ψ R % Q 1 L 2 I N ¥ 4 © 6 O B
1.If all the symbols are dropped from the above arrangement then which of the following will be thirteenth element from the right end of the given arrangement?
Question (1-5)
$ 5 G A H 8 # 3 U S 9 Ω W 7 E J Ψ R % Q 1 L 2 I N ¥ 4 © 6 O B
1). Answer: A
Let drop the all the symbols in the arrangement,
5 G A H 8 3 U S 9 W 7 E J R Q 1 L 2 I N 4 6 O B
Then, 13th element from the right end is ‘E’
$ 5 G A H 8 # 3 U S 9 Ω W 7 E J Ψ R % Q 1 L 2 I N ¥ 4 © 6 O B
1). Answer: A
Let drop the all the symbols in the arrangement,
5 G A H 8 3 U S 9 W 7 E J R Q 1 L 2 I N 4 6 O B
Then, 13th element from the right end is ‘E’
2. What should be in the place of question mark (?) in the following series based on the given arrangement?
38S ΩUE R7L ?
2). Answer: C
38S ΩUE R7L ?
Hence, the answer is ‘¥ 1 B’
38S ΩUE R7L ?
3. Which of the following is fourth to the right of the nineteenth element from the left end of the given arrangement?
3). Answer: D
Fourth to the right of the nineteenth element from the left end i.e. 19 + 4 = 23rd element from the left end = ‘2’
Fourth to the right of the nineteenth element from the left end i.e. 19 + 4 = 23rd element from the left end = ‘2’
4. How many such vowels are there in the arrangement each of which immediately followed by a consonant and also immediately not preceded by a number?
4). Answer: A
$ 5 G A H 8 # 3 U S 9 Ω W 7 E J Ψ R % Q 1 L 2 I N ¥ 4 © 6 O B
There is only one such a vowel.
$ 5 G A H 8 # 3 U S 9 Ω W 7 E J Ψ R % Q 1 L 2 I N ¥ 4 © 6 O B
There is only one such a vowel.
5. How many such numbers are there in the arrangement each of which immediately preceded by letter and immediately followed by symbol?
5). Answer: C
$ 5 G A H 8 # 3 U S 9 Ω W 7 E J Ψ R % Q 1 L 2 I N ¥ 4 © 6 O B
There are two such a numbers.
$ 5 G A H 8 # 3 U S 9 Ω W 7 E J Ψ R % Q 1 L 2 I N ¥ 4 © 6 O B
There are two such a numbers.
Direction (Q. 6-8): Following questions are based on the five numbers given below. Study the questions carefully and answer it.
457 743 614 298 329
6. If the positions of the first and the third digits in each of the above numbers are interchanged, which of the following will be the third highest number? </span>
Question (6-8):
457 743 614 298 329
6). Answer: D
Interchanging the first and third digits of the each numbers we get,
754 347 416 892 923
∴ the third highest number is ‘754’.
Hence, the corresponding number is 457.
457 743 614 298 329
6). Answer: D
Interchanging the first and third digits of the each numbers we get,
754 347 416 892 923
∴ the third highest number is ‘754’.
Hence, the corresponding number is 457.
7. If in each number, the digits are arranged in ascending order within the number, what will be the sum of the middle digits of the highest number and the second lowest number?
7). Answer: A
Ascending order of the digits,
457 347 146 289 239
The highest number is, 457
The second lowest number is 289
Hence, required sum = 5 + 8 = 13
Ascending order of the digits,
457 347 146 289 239
The highest number is, 457
The second lowest number is 289
Hence, required sum = 5 + 8 = 13
8. If the position of the second and the third digits in each of the above numbers are interchanged, which of the following will be the second highest number?
8). Answer: C
Interchanging the second and third digits of each numbers, we get
475 734 641 289 392
∴ the second highest number is, 641
Hence, the corresponding number is 614
Interchanging the second and third digits of each numbers, we get
475 734 641 289 392
∴ the second highest number is, 641
Hence, the corresponding number is 614
Direction (Q. 9-10): Following questions are based on the five numbers given below. Study the questions carefully and answer it.
729 867 308 652 460
9. If in each number, ‘one’ is added to every even digits and ‘two’ is subtracted from every odd digits and put ‘one’ for ‘zero’, then what is the difference between the middle digit of second number from right end and the last digit of second number from the left end?</span>
Question (9-10):
729 867 308 652 460
9). Answer: B
Adding to ‘one’ to the every even digits and subtracting ‘two’ from every odd digits, we get 537 975 119 733 571
The second number from the right end is 733
The second number from left end is 975
Hence, the required difference = 5 – 3 = 2
729 867 308 652 460
9). Answer: B
Adding to ‘one’ to the every even digits and subtracting ‘two’ from every odd digits, we get 537 975 119 733 571
The second number from the right end is 733
The second number from left end is 975
Hence, the required difference = 5 – 3 = 2
10. If in each number, the digits are arranged in descending order, what will be the sum of the middle digits of each of the numbers?
10). Answer: A
Descending order of the digits,
972 876 830 652 640
Hence, the required sum = 7 + 7 + 3 + 5 + 4 = 26
Descending order of the digits,
972 876 830 652 640
Hence, the required sum = 7 + 7 + 3 + 5 + 4 = 26
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