Practice Quantitative Aptitude Questions For IBPS 2017 Exams (Application Sums)

July 13, 2017 Share Like Labels: ig

Practice Quantitative Aptitude Questions For IBPS 2017 Exams (Application Sums):

Dear Readers, Important Practice Aptitude Questions for IBPS Exams 2017 was given here with Solutions. Aspirants those who are preparing for the Bank Examination and other Competitive Examination can use this material.

Directions (Q. 1-10):
1).A starts a business with a capital of Rs. 85,000. B joins in the business with Rs.42500 after some time. For how much period does B join, if the profits at the end of the year are divided in the ratio of 3 : 1?

1). Let B joins for x months.
Then A:B = 85000×12 : x× 42500 = 3 : 1
= 850×12 : 425x= 3 : 1
= 850×12/ 425x = 3/1 = 3
= 850×4 /425x = 1
= 2×4/x = 1
= x = 8
Answer is: E

2). A can do a particular work in 6 days. B can do the same work in 8 days. A and B signed to do it for Rs. 3200. They completed the work in 3 days with the help of C. How much is to be paid to C?

2). Amount of work A can do in 1 day = 1/6
Amount of work B can do in 1 day = 1/8
Amount of work A + B can do in 1 day = 1/6 + 1/8 = 7/24
Amount of work A + B + C can do = 1/3
Amount of work C can do in 1 day = 1/3 - 7/24 = 1/24
Work A can do in 1 day: work B can do in 1 day: work C can do in 1 day
= 1/6 : 1/8 : 1/24 = 4 : 3 : 1
Amount to be paid to C = 3200 × (1/8) = 400
Answer is: D

3). Two trains are moving in opposite directions with speed of 60 km/hr and 90 km/hr respectively. Their lengths are 1.10 km and 0.9 km respectively. the slower train cross the faster train in _______ seconds

3). Relative speed = 60+90 = 150 km/hr (Since both trains are moving in opposite directions)
Total distance = 1.1+.9 = 2km
Time = 2/150 hr = 1/75 hr
= 3600/75 seconds
= 1200/25
= 240/5
= 48 seconds
Answer is: B

4). Aarthi's age is 1/6th of her father's age. Aarthi's father's age will be twice the age of Gokul's age after 10 years. If Gokul's eighth birthday was celebrated two years before, then what is Aarthi's present age.

4). Consider Aarthi's present age = x
Then her father's age = 6x
Given that Aarthi's father's age will be twice the age of Gokul's age after 10 years
= Gokul's age after 10 years = ½(6x + 10) = 3x + 5
Also given that Gokul's eighth birthday was celebrated two years before =>
Gokul's age after 10 years = 8 + 12 = 20
= 3x + 5 = 20
= x = 15/3 = 5
= Aarthi's present age = 5 years
Answer is: C

5). A boat can travel with a speed of 22 km/hr in still water. If the speed of the stream is 5 km/hr, find the time taken by the boat to go 54 km downstream

5). Speed of the boat in still water = 22 km/hr
Speed of the stream = 5 km/hr
Speed downstream = (22+5) = 27 km/hr
Distance travelled downstream = 54 km
Time taken = distance/speed=54/27
= 2 hours
Answer is: D

6). The ratio between two number is 3:4, if each number be increased by 9, the ratio becomes 18:23 find the sum of the number

6). Let the two numbers be 3x and 4x.
When they are increased by 9 they become 3x + 9 and 4x + 9.
It is given that the ratio is 18:23
Thus, (3x + 9)/(4x + 9) = 18:23
23(3x + 9) = 18(4x + 9)
69x + 207 = 72x + 162
69x – 72x = 162- 207
-3x = -45
x = 15
Thus two numbers are 3x15 = 45 and 4 x 15 = 60
And the sum is 60+45 = 105
Answer is: B

7). The incomes of A of B are in the ratio 3:2 and their expenditure are in the ratio 5:3 if each saves rupees 2000, what is the income of B?

7). Let the income be 3x and 2x. It is given that the saving of each is Rs. 2000.
Then, their expenditures are 3x – 2000 and 2x – 2000
Again, (3x – 2000)/(2x – 2000) = 5/3
=> 3(3x – 2000) = 5(2x – 2000)
=> 9x – 6000 = 10x – 10000
=> 9x -10x = -10000+ 6000
=> -x = -4000
=> x = 4000
Therefore, their salaries are 3 x 4000 = 12000
and 2 x 4000 = 8000
Answer is: D

8). A mixture contains milk and water in the ratio of 3:2. If 4 litre of water is added to the mixture, milk and water in the mixture become equal find the quantities of milk and water in the mixture.

8). Let quantities of milk and water in the mixture be 3x and 2x. Then if 4 litres of water is added to the mixture the ratio of milk and water become 1:1.
It can be written as (3x): (2x + 4) = 1/1
Thus, 3x = 2x +4
x = 4
Therefore, the milk in the mixture is 4x3 = 12 litres and quantity of water
= 4x2
= 8 litres
Answer is: A

9). A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished?

9). Work done by A in one day = 1/5 and work done by B in one day = 1/7
They are working alternately.
Therefore, Work done in first two day = (1/5 + 1/7) = 12/35
Work done in first four day = 24/35
Work done in first 5 days = 24/35 + 1/5 = 31/35
Remaining work = 4/35
Day it will take B to complete = 4/35/1/7 = 4/5 of the day.
Therefore Total days taken = 5 + 4/5 = 29/5 days
Answer is: D

10). 6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days.

10). Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b
Work done by 6 men and 8 women in 1 day = 1/10
=> 6m + 8b = 1/10
=> 60m + 80b = 1 --- (1)
Work done by 26 men and 48 women in 1 day = 1/2
=> 26m + 48b = 1/2
=> 52m + 96b = 1--- (2)
Solving equation 1 and equation 2, We get m = 1/100 and b = 1/200
Work done by 15 men and 20 women in 1 day
= 15/100 + 20/200 =1/4
=> Time taken by 15 men and 20 women in doing the work = 4 days
Answer is: A