Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-22):
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Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). 8.4% of 270 – 9.6% of 105 = ?% of 168
1). Answer: c)
? × 168/100 = 22.68 – 10.08 = 12.6
? = 12.6× 100 /168 = 7.5
2. √70.56 ÷ (70.56)^(-3/2) = (8.4)^?? × 168/100 = 22.68 – 10.08 = 12.6
? = 12.6× 100 /168 = 7.5
2). Answer: b)
√70.56 ÷ (70.56)^(-3/2)= (8.4)^?
8.4 ÷(8.4)^(2×(-3/2)) = (8.4)^?
or, (8.4)^? = 8.4^(1 + 3) = 8.4^4
? = 4
3. 17.5% of 1520 – 8.75% of 1200 = ?% of 2576√70.56 ÷ (70.56)^(-3/2)= (8.4)^?
8.4 ÷(8.4)^(2×(-3/2)) = (8.4)^?
or, (8.4)^? = 8.4^(1 + 3) = 8.4^4
? = 4
3). Answer: b)
?× 2576/100 = 17.5 ×1520/100 – 8.75× 1200/100
?× 2576/100 = (26600 – 10500) / 100
? = 16100 / 2576 = 6.25
?× 2576/100 = 17.5 ×1520/100 – 8.75× 1200/100
?× 2576/100 = (26600 – 10500) / 100
? = 16100 / 2576 = 6.25
4. 8 2/3 of 1263 + 4 5/9 of 1179 = ?× 9
4). Answer: e)
? × 9=26 / 3 × 1263 +41 / 9 × 1179
= 26 × 421 + 41 × 131 = 10946 + 5371
? =16317 / 9
? = 1813
? × 9=26 / 3 × 1263 +41 / 9 × 1179
= 26 × 421 + 41 × 131 = 10946 + 5371
? =16317 / 9
? = 1813
5).32% of 885 – 20% of 66 = 75% of ?
5). Answer: d)
75 ×? / 100 = 32× 885 / 100 – 20× 66 / 100
= 283.2 - 13.2 = 270
? = 270× 100 / 75 = 360
75 ×? / 100 = 32× 885 / 100 – 20× 66 / 100
= 283.2 - 13.2 = 270
? = 270× 100 / 75 = 360
6.144% of 75 – 48% of 150 + 4.8% of 2250 = 12.5% of ?
6). Answer: b)
12.5 ×? /100 = 144× 75 /100 – 48 ×150/100 + 4.8× 2250 / 100
= 108 - 72 + 108 = 144
? = 144× 100 / 12.5 = 1152
12.5 ×? /100 = 144× 75 /100 – 48 ×150/100 + 4.8× 2250 / 100
= 108 - 72 + 108 = 144
? = 144× 100 / 12.5 = 1152
7. 3/8 of 2/5 of 13/7 of 35% of 107800 = ?
7). Answer: b)
? = 3 / 8 × 2 / 5 × 13 / 7 × 35 /100 × 10780 = 10510.5
? = 3 / 8 × 2 / 5 × 13 / 7 × 35 /100 × 10780 = 10510.5
8. {√2 × (174)}^2 + {√2 ×(84)}^2 = ?
8). Answer: d)
? = 2 × (174)^2 + 2 × (84)^2 = 2{(174)^2 + (84)^2}
= (174 + 84)^2 + (174 - 84)^2 = (258)^2 + (90)^2
? = 66564 + 8100 = 74664
9. 3 2/3 + 1 3/4 - 6 1/2 + 3 2/7 = ?? = 2 × (174)^2 + 2 × (84)^2 = 2{(174)^2 + (84)^2}
= (174 + 84)^2 + (174 - 84)^2 = (258)^2 + (90)^2
? = 66564 + 8100 = 74664
9). Answer: c)
? = (3 + 1 + 3 - 6) + (2/3 + 3/4 + 2/7 – 1/2)
= 1 +((56 + 63 + 24 – 42) / 84)= 1 + 101/84
? = 217/84
? = (3 + 1 + 3 - 6) + (2/3 + 3/4 + 2/7 – 1/2)
= 1 +((56 + 63 + 24 – 42) / 84)= 1 + 101/84
? = 217/84
10. (1331)^(2/3) × (484)^(-1/2) ÷ (121)^(-1)= (11)^?÷ 2
10). Answer: b)
11^? ÷ 2 = (11^3 )^(2/3) × (22^2 )^ (-1/2) ÷ (11^2 )^(-1)
= (11)^2×(22)^-1× (11)^2
(11)^? / 2 = (11)^2×(11)^2 /(11 × 2) = (11)^3 / 2
? = 3
11^? ÷ 2 = (11^3 )^(2/3) × (22^2 )^ (-1/2) ÷ (11^2 )^(-1)
= (11)^2×(22)^-1× (11)^2
(11)^? / 2 = (11)^2×(11)^2 /(11 × 2) = (11)^3 / 2
? = 3
Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11. 33 1/3% of ∛1728 + 12.5% of 161.005 × 40%of 1099.97=?
11). Answer: d)
? = 331/3% of ∛1728 + 12.5% of161.005 × 40% of 1099.97
≈1/3 × 12 + 1/8 × 160× 2/5 × 1100
≈ 4 + 20 × 440 = 4 + 8800 = 8804
? = 331/3% of ∛1728 + 12.5% of161.005 × 40% of 1099.97
≈1/3 × 12 + 1/8 × 160× 2/5 × 1100
≈ 4 + 20 × 440 = 4 + 8800 = 8804
12. [(941192)^(1/3)- (110592)^(1/3) ]^2 = ?
12). Answer: d)
? = [(941192)^(1/3)–(110592)^(1/3)]^2
= (98 - 48)^2 = (50)^2 = 2500 ≈ 2501
13.85% of 225 + 32.98 × 6.003 = ?? = [(941192)^(1/3)–(110592)^(1/3)]^2
= (98 - 48)^2 = (50)^2 = 2500 ≈ 2501
13). Answer: c)
? = 85% of 225 + 32.98 × 6.003
≈85 / 100 × 225 + 33 × 6 = 191.25 + 198
? = 389.25 ≈ 389
14. 25% of √4096.00139 × 2/5 of (35)^2 – 2/3 of 39.01 = ?? = 85% of 225 + 32.98 × 6.003
≈85 / 100 × 225 + 33 × 6 = 191.25 + 198
? = 389.25 ≈ 389
14). Answer: c)
25% of √4096.00139 ×2/5 of (35)^2 – 2 /3 of 39.01
≈1/4 × 64 ×2/5 × 1225 – 2 / 3 × 39
= 16 × 2 × 225 - 26 = 7840 - 26 = 7814
15. 16 1/99 × 5 2/105 + ? = 90 98/9925% of √4096.00139 ×2/5 of (35)^2 – 2 /3 of 39.01
≈1/4 × 64 ×2/5 × 1225 – 2 / 3 × 39
= 16 × 2 × 225 - 26 = 7840 - 26 = 7814
15). Answer: d)
1585 / 99 × 527 / 105 + ? = 9008 / 99
or,? = 9008 / 99– 317 / 99 × 527 / 21
? =(189168 – 167059) / (99 × 21)
? = 22109 / 2079 = 10.63≈ 11
16.∛59322 ×(428 ÷11) = (?)^21585 / 99 × 527 / 105 + ? = 9008 / 99
or,? = 9008 / 99– 317 / 99 × 527 / 21
? =(189168 – 167059) / (99 × 21)
? = 22109 / 2079 = 10.63≈ 11
16). Answer: c)
(?)^2=∛59322 ×(428 ÷11)
= ∛(39× 39× 39) × 38.90
≈ 39 × 39 = (39)2
? = 39
17. 177.5% of 2480 + 63.002 × 19.995 - 61.899 = ?(?)^2=∛59322 ×(428 ÷11)
= ∛(39× 39× 39) × 38.90
≈ 39 × 39 = (39)2
? = 39
17). Answer: c)
? ≈177.5 ×2480 / 100 + 63× 20 – 62
≈ 4402 + 1260 - 62 = 5600
18. 7/16 × 8022.66 +11/20 × 6822.44 = ?? ≈177.5 ×2480 / 100 + 63× 20 – 62
≈ 4402 + 1260 - 62 = 5600
18). Answer: a)
? = 7/16 × 8022.66 + 11 / 20 × 6822.44
= 3509.91 + 3752.34 ≈ 7260
? = 7/16 × 8022.66 + 11 / 20 × 6822.44
= 3509.91 + 3752.34 ≈ 7260
19. 97975 ÷ 545 × ∛515 = ?
19). Answer: e)
?≈ 97975 / 545 ×∛515
≈ 179.77 × 8 ≈ 180 × 8 = 1440
?≈ 97975 / 545 ×∛515
≈ 179.77 × 8 ≈ 180 × 8 = 1440
20. 289.089 × 4.27 + 5.004 × 333.918 = ?
20). Answer: d)
? ≈290 × 4.25 + 5 × 334
= 1232.5 + 1670 ≈ 2900
Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.? ≈290 × 4.25 + 5 × 334
= 1232.5 + 1670 ≈ 2900
21. 24, 12, ?, 18 , 36, 90
21). Answer: b)
The series is × 0.5, ×1, × 1.5, × 2, × 2.5, ….
The series is × 0.5, ×1, × 1.5, × 2, × 2.5, ….
22. 7 , 20, 59, ? , 215 , 332
22). Answer: d)
The series is + (1 × 13), + (3 × 13), + (5 × 13), + (7 × 13),….
The series is + (1 × 13), + (3 × 13), + (5 × 13), + (7 × 13),….
23. ?, 17, 29, 59, 115, 205
23). Answer: c)
The series is 15 + 1 × 2 = 17,
17 + 3 × 4 =29,
24. 10, 30, 68, 130, ?, 350The series is 15 + 1 × 2 = 17,
17 + 3 × 4 =29,
29 + 5 × 6 = 59,
59 + 7 × 8 = 105,
105 + 9 × 10 = 205, ….
24). Answer: d)
The series is 2^3 + 2, 3^3 + 3 , 4^3 + 4 , 5^3 + 5, 6^3 + 6 , 7^3 + 7,…..
The series is 2^3 + 2, 3^3 + 3 , 4^3 + 4 , 5^3 + 5, 6^3 + 6 , 7^3 + 7,…..
25.170, 196, 248, ? , 560, 976
25). Answer: b)
The series is + 26, + 52, + 104, + 208, + 416,…
The series is + 26, + 52, + 104, + 208, + 416,…
Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) if x > y
b) if x < y
c) if x ≥ y
d) if x ≤ y
e) if x =y, or no relation can be established between x and y.
II.y^(1/3)×14=294÷y^(2/3)
26). Answer: b)
I.13x^2 = x × 247 × 1/x
Or, 13x^2=247
Or, x^2=19
∴x=±4.35
II. y^(1/3)×14= 294 / y^(2/3)
Or, y^(1/3+2/3) =294/14
Or, y=21
Hence x < y
27. I.8x^2-78x+169 =0I.13x^2 = x × 247 × 1/x
Or, 13x^2=247
Or, x^2=19
∴x=±4.35
II. y^(1/3)×14= 294 / y^(2/3)
Or, y^(1/3+2/3) =294/14
Or, y=21
Hence x < y
II.20y^2-117y+169 =0
27). Answer: c)
I.8x^2-78x+169=0
Or, 8x^2-52x-26x+169 =0
Or, 4x(2x-13)-13(2x-13)=0
∴x=13/2, 13/4
=6.5, 3.25
II.20y^2-117y+169 =0
Or, 20y^2-65y-52y+169 =0
Or, 5y(4y-13)-13(4y-13)=0
Or, y=13/5,13/4
∴y=2.6, 3.25
∴Hence x≥y
28. I.(169)^(1/2)x+√289=134I.8x^2-78x+169=0
Or, 8x^2-52x-26x+169 =0
Or, 4x(2x-13)-13(2x-13)=0
∴x=13/2, 13/4
=6.5, 3.25
II.20y^2-117y+169 =0
Or, 20y^2-65y-52y+169 =0
Or, 5y(4y-13)-13(4y-13)=0
Or, y=13/5,13/4
∴y=2.6, 3.25
∴Hence x≥y
II.(361)^(1/2)y^2-270=1269
28). Answer: c)
I. (169)^(1/2)x+√289=134
Or, 13x+17=134
Or, 13x=117
∴x=9
II. (361)^(1/2)y^2-270=1269
Or, 19y^2=1269+270
Or, y^2=81
∴y=±9
Hence, x≥y
29. I.x^2-14x +49=0I. (169)^(1/2)x+√289=134
Or, 13x+17=134
Or, 13x=117
∴x=9
II. (361)^(1/2)y^2-270=1269
Or, 19y^2=1269+270
Or, y^2=81
∴y=±9
Hence, x≥y
II.y^2-10y-56=0
29). Answer: e)
I. x^2-14x+49=0
Or, x^2-7x-7x+49=0
Or,(x-7)(x-7)=0
∴x=7, 7
II.y^2-10y-56=0
Or, y^2-14y+4y-56=0
Or,y(y-14)+4(y-14)=0
∴y=14,-4
Relation can’t be established.
30. I.8x^2+29x-12=0I. x^2-14x+49=0
Or, x^2-7x-7x+49=0
Or,(x-7)(x-7)=0
∴x=7, 7
II.y^2-10y-56=0
Or, y^2-14y+4y-56=0
Or,y(y-14)+4(y-14)=0
∴y=14,-4
Relation can’t be established.
II.3y^2+12y+9=0
30). Answer: e)
I. 8x^2+29x-12=0
Or, 8x^2+32x -3x-12=0
Or,8x(x+4)-3(x+4)=0
∴x=3/8,-4
II. 3y^2+12y+9=0
Or, 3y^2+3y+9y+9=0
Or, 3y(y+1)+9(y+1)=0
Or, y=-9/3,-1
y = -3,-1
Relationship can’t be established.
I. 8x^2+29x-12=0
Or, 8x^2+32x -3x-12=0
Or,8x(x+4)-3(x+4)=0
∴x=3/8,-4
II. 3y^2+12y+9=0
Or, 3y^2+3y+9y+9=0
Or, 3y(y+1)+9(y+1)=0
Or, y=-9/3,-1
y = -3,-1
Relationship can’t be established.
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