Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-40)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-40):

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Direction (1-10): What approximate value should come in place of question mark (?) in the following questions?
1). (5 / 6) × [(2 / 9) ÷ (4 / 9)] ÷ (6 / 7) = ?

1) Answer: C
? = (5 / 6) × [(2 / 9) ÷ (4 / 9)] ÷ (6 / 7)
= (5 / 6) × [ 1 / 2 ] × (7 / 6) = (35 / 72)
= 0.486 ≈ 0.49

2). 15% of 62.5 + 10% of 4.80 = ?

2) Answer: C
? = [(15 × 62.5) / 100] + [(10 × 4.80) / 100]
= 9.375 + 0.48 = 9.855 ≈ 10

3). 543.28 ÷ 55 = ?

3) Answer: C
? = 543.28 / 55 = 9.8778 = 10

4). [(3 / 0.8) × (11 / 0.2)] ÷ [(28 / 3) × (21 / 5)] = ?

4) Answer: B
?= (33 / 0.16) × [5 / (28 × 7)] = (165 / 31.36)
= 5.26 ≈ 5

5). (1.1)^2 + (3.2)^2 + (3.0)^2 = ?

5) Answer: A
? = 1.21 + 10.24 + 9 = 20.45 ≈ 20

6). (7895641 ÷ 2795 ÷ 123) × 345 ÷ 456 = ?

6). Answer: A
? = (7895641 ÷ 2795 ÷ 123) × 345 ÷ 456
≈ 23 × 0.75 ≈ 17

7). 3945 + 150 × 40 – 35.5 = ?

7). Answer: D
? = 3945 + 150 × 40 - 35.5
≈ 9945 – 35.5 = 9909.5 ≈ 9900

8). (63)^2 × 3.545 = ?

8). Answer: A
? = (63)^2 × 3.545
= 3969 × 3.545
= 14070.10 ≈ 14070

9). 3.5 × 0.07 ÷ (1.7)^2 = ?

9). Answer: C
? = 3.5 × 0.07 ÷ (1.7)^2
= 3.5 × 0.07 ÷ 2.89
= 3.5 × 0.024
= 0.84 ≈ 1

10). 64% of 159.96 + 72% of 65.005 + (1.4)^2 – (0.4)^2 = ?

10). Answer: C
? = 64% of 159.96 + 72% of 65.005 + (1.4)^2 – (0.4)^2
≈ 64% of 160 + 72% of 65 + (1.4)^2 – (0.4)^2
≈ 102.4 + 46.8 + 1.96 – 0.16
≈ 151 .16 – 0.16 = 151

Direction (11-20): What value should come in place of question mark (?) in the following questions?
11). 1250 / ? = ? / 450

11). Answer: A
(?)^2 = 1250 × 450 = 562500
? = 750

12). 65% of 75 + 35% of 25 = ? % of 460

12). Answer: D
48.7 + 8.75 = (460 / 100) × ?
57.5 = 4.6 × ?
? = 12.5

13). ∛148877 = 30 + ?

13). Answer: E
∛148877 = ∛(53)2 = 53
? = 53 – 30 = 23

14). [12(3 / 5) – 5(2 / 5)] / 5(3 / 70) = ?

14). Answer: C
[12(3 / 5) – 5(2 / 5)] / 5(3 / 70) = ?
= 7(1 / 5) / 5(3 / 70)
= (36 / 5) / (353 / 70)
= (36 / 5) × (70 / 353)
= 504 / 353 = 1(151 / 353)

15). 1805 / 19 + 65 = 200 + ?

15). Answer: B
1805 / 19 + 65 = 200 + ?
95 + 65 = 200 + ?
160 = 200 + ?
? = -40

16). 16.23 × 12.9 + 17.32 = ?

16). Answer: C
? = 16.23 × 12.9 + 17.32
= 209.367 + 17.32
= 226.687

17). 998711 – 362 – 74563 – 8526 – 66156 = ?

17). Answer: A
? = 998711 – (362 + 74563 + 8526 + 66156)
= 998711 – 149607 = 849104

18). 32% of 860 × ? = 61920

18). Answer: E
860 × (32 / 100) × ? = 61920
Or, ? = (61920 × 100) / (860 × 32) = 225

19). [ (6)^3 × (9)^2 ] / 18 = ?

19). Answer: B
[ (6)^3 × (9)2 ] / 18 = ?
? = (216 × 81) / 18 = 972

20). 7410 + ? – 3652 – 1479 = 11820

20). Answer: D
7410 + ? – 3652 – 1479 = 11820
Or, ? + 7410 – 5131 = 11820
Or, ? + 2279 = 11820
Or, ? =11820 – 2279 = 9541

Direction (21 – 25): What will come in place of (?) in the following number series.
21). 14, 8, 6, 6, 7, ?

21). Answer: C
The series is,
14 / 2 + 1 = 8
8 / 2 + 2 = 6
6 / 2 + 3 = 6,….

22). 6, 13, 20, 65, 256, ?

22). Answer: A
The series is,
6 * 1 + 7 = 13
13 * 2 – 6 = 20
20 * 3 + 5 = 65….

23). 24, 28, 40, ?, 88, 124

23). Answer: B
The series is,
24 + 4*1 = 28
28 + 4*3 = 40
40 + 4*5 = 60…..

24). 15, 8, 7, 16, 60, ?

24). Answer: B
The series is,
15 * 0.5 + 0.5 = 8
8 * 1 – 1 = 7
7 * 2 + 2 = 16;
16 * 4 – 4 = 60…

25). 19, 23, 40, 70, 113, ?

25). Answer: B
The difference of difference of the series is, 13 (17 – 4 = 13; 30 – 17 = 13….)
23 – 19 = 4
40 – 23 = 17
70 – 40 = 30….

Direction (26-30): In each of these questions, two equations are given. You have to solve both the equations and given answer:
26). X^2 – 18x + 72= 0, 5y^2 – 18y + 9 = 0

26). Answer: A
X^2 – 18x + 72= 0
(x-12)(x-6) = 0
Gives x = 6, 12
5y^2 – 18y + 9 = 0
5y^2 – 15y – 3y + 9 = 0
Gives y = 3/5, 3
Hence, x > y

27). X^2 = 4, 3y^2 – 4y – 4 = 0

27). Answer: E
X^2 = 4
Gives x = 2 , -2
3y^2 – 4y – 4 = 0
3y^2 – 6y + 2y – 4 = 0
Gives y = -2/3, 2
Hence, relation cannot be established.

28). 6x^2 – 5x – 6 = 0, 2y^2 – 13y + 20 = 0

28). Answer: B
6x^2 – 5x – 6 = 0
6x^2 – 9x + 4x – 6 = 0
Gives x = -2/3, 3/2
2y^2 – 13y + 20 = 0
2y^2 – 8y – 5y +20 = 0
Gives y = 4, 5/2
Therefore x < y

29). 2x^2 – 5x = 0, 2y^2 + 7y – 4 = 0

29). Answer: E
2x^2 – 5x = 0
x(2x-5) = 0
Gives x = 0, 5/2
2y^2 + 7y – 4 = 0
Gives y = -4, 1/2
Therefore, relation cannot be established.

30). 2x^2 + 5x + 2= 0, 2y^2 + 19y + 45 = 0

30). Answer: A
2x^2 + 5x + 2= 0
2x^2 + 4x + x + 2= 0
Gives x = -1/2, -2
2y^2 + 19y + 45 = 0
2y^2 + 10y + 9y + 45 = 0
Gives y= -5, -9/2
Therefore, y < x

       

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