Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-33):
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Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). 4(2/3)+6(7/5)-11(5/3)+3(4/7) = ?
1). Answer: b)
(14/3)+(37/5)-(38/3)+(25/7) = (490+777-1330+375)/105
= 312/105 = 2(102/105)
2). (4/7)×2126÷11.4+26% of 520(14/3)+(37/5)-(38/3)+(25/7) = (490+777-1330+375)/105
= 312/105 = 2(102/105)
2). Answer: b)
? = 0.57×2126÷11.4+26% of 520
? = 0.57×2126÷11.4+135.2
= 0.57×186.5+135.2
= 106.3+135.2 = 241.5
3). 15.006×?×25.985 = 56745? = 0.57×2126÷11.4+26% of 520
? = 0.57×2126÷11.4+135.2
= 0.57×186.5+135.2
= 106.3+135.2 = 241.5
3). Answer: b)
15.006×?×25.985 = 56745
389.93×? = 56745
? = 56745/389.93
? = 145.53
4). (50)3 ÷ (25)2 + 2466 = ?15.006×?×25.985 = 56745
389.93×? = 56745
? = 56745/389.93
? = 145.53
4). Answer: a)
(50×50×50)/(25×25) = 200
200+2466 = 2666
5). [(5.6/7.8 ×9.8/2.88) ÷ (34.2/6 × 20/4.5) ] % of 2345 = ?(50×50×50)/(25×25) = 200
200+2466 = 2666
5). Answer: e)
? = (5.6×9.8×6×4.5)/(7.8×2.88×34.2×20)% of 2345
? = (0.09643/100) ×2345 = 2.26
6). 1006.7+12328.98-5644.64 = 12543 - ?? = (5.6×9.8×6×4.5)/(7.8×2.88×34.2×20)% of 2345
? = (0.09643/100) ×2345 = 2.26
6). Answer: c)
13335.68-5644.64 = 12543 - ?
7691.04 = 12543 - ?
? = 4851.96
7). 45% of 2345 + 56% of 765 – 12% of 789 ×75% of 433 + ? = 013335.68-5644.64 = 12543 - ?
7691.04 = 12543 - ?
? = 4851.96
7). Answer: a)
0 = ? + 1055.25 + 428.4 – 94.68 × 324.75
0 = ? + 1055.25 + 428.4 –30747.33
? = 29263.68
8). (124÷23) + (56×76) – (45÷ 2.4) = ?0 = ? + 1055.25 + 428.4 – 94.68 × 324.75
0 = ? + 1055.25 + 428.4 –30747.33
? = 29263.68
8). Answer: d)
? = 5.39 + 4256 – 18.75
? = 4261.39 – 18.75 = 4242.64
9). (7.84)1/2 × (47.61)1/2 – 92161/2 = ?? = 5.39 + 4256 – 18.75
? = 4261.39 – 18.75 = 4242.64
9). Answer: c)
= 2.8 ×6.9 – 96
= 19.32 – 96
= – 76.68
10). 46% of ? = 46916= 2.8 ×6.9 – 96
= 19.32 – 96
= – 76.68
10). Answer: b)
(46/100) × ? = 46916
? = (46916×100)/46 = 101991.3
Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?(46/100) × ? = 46916
? = (46916×100)/46 = 101991.3
11). 108 × 107 × 96 = ?
11). Answer: d)
108 × 107 × 96 = ?
? = 1109376
Nearest value in options is 1109380
12). 8(2/7) + 30% of 60 + 10(5/9) = ?108 × 107 × 96 = ?
? = 1109376
Nearest value in options is 1109380
12). Answer: c)
8(2/7) + 30% of 60 + 10(5/9) = ?
? = 58/7 + 18 + 95/9
? ≈ 8 + 18 + 11 = 37
13). 8.94% of 540 – 9.2% of 324 = ?8(2/7) + 30% of 60 + 10(5/9) = ?
? = 58/7 + 18 + 95/9
? ≈ 8 + 18 + 11 = 37
13). Answer: c)
8.94% of 540 – 9.2% of 324 = ?
? ≈ 8.9 × 5.4 – 9 × 3.2 = 19.26
Nearest value in options is 19
14). 23(2/15) x 16 (8/9) +8(1/3) = ?8.94% of 540 – 9.2% of 324 = ?
? ≈ 8.9 × 5.4 – 9 × 3.2 = 19.26
Nearest value in options is 19
14). Answer: a)
? = 23(2/15) x 16 (8/9) +8(1/3)
? = 347/15 × 152/9 + 25/3
? ≈ 391 + 8 = 399
15). √224 x 12.05 + ³√342 x 4 = ?? = 23(2/15) x 16 (8/9) +8(1/3)
? = 347/15 × 152/9 + 25/3
? ≈ 391 + 8 = 399
15). Answer: c)
? = √224 x 12.05 + ³√342 x 4
? ≈ 15 * 12 + 7 * 4
? = 180 + 28 = 208
16).√(1230) + √(4230) = ?? = √224 x 12.05 + ³√342 x 4
? ≈ 15 * 12 + 7 * 4
? = 180 + 28 = 208
16). Answer: c)
√(1230) + √(4230) ≈ √(1225) + √(4225) = 35 + 65 = 100
17). 7 (3/11) × 626 – 7(1/3) = ?√(1230) + √(4230) ≈ √(1225) + √(4225) = 35 + 65 = 100
17). Answer: b)
7(3/11) × 626 – 7(1/3)
[(80 ×626) / 11] – 7(1/3) = 4552 – 7 = 4545
18). 49% of 5051 – (3/7) of 999 = ?7(3/11) × 626 – 7(1/3)
[(80 ×626) / 11] – 7(1/3) = 4552 – 7 = 4545
18). Answer: b)
[(49 × 5051) / 100] – (3/7) × 999 = 2475 – 430 = 2045
19). 4329 / 19 + 6464 / 13 = ?[(49 × 5051) / 100] – (3/7) × 999 = 2475 – 430 = 2045
19). Answer: a)
(4329 / 19) + (6464 / 13) = 228 + 497 = 725
20). (4.012)3 + (29.997)2 = ?(4329 / 19) + (6464 / 13) = 228 + 497 = 725
20). Answer: b)
(4)^3 + (30)^2 = 64 + 900 = 964
Direction (21 – 25): What will come in place of (?) in following Number series following a certain pattern?(4)^3 + (30)^2 = 64 + 900 = 964
21).375, 75, 30, 18, ?, 14.4
21). Answer: d)
The series is × 0.2, × 0.4, × 0.6, × 0.8, × 1.0
22). 25, 89, 332, 588, 713, ?The series is × 0.2, × 0.4, × 0.6, × 0.8, × 1.0
22). Answer: c)
The series is 25 + 2^6, 89 + 3^5, 332 + 4^4, 588 + 5^3, 713 + 6^2
23). 18, 36, 62, 96, 138, ?The series is 25 + 2^6, 89 + 3^5, 332 + 4^4, 588 + 5^3, 713 + 6^2
23). Answer: e)
The difference of difference of the series is 8.
18 + 18 = 36
36 + (18+8) = 36 + 26 = 62
62 + (26+8) = 62 + 34 = 96
96 + (34+8) = 96 + 42 = 138
138 + (42+8) = 188
24). 16, 24, 60, 210, 945, ?The difference of difference of the series is 8.
18 + 18 = 36
36 + (18+8) = 36 + 26 = 62
62 + (26+8) = 62 + 34 = 96
96 + (34+8) = 96 + 42 = 138
138 + (42+8) = 188
24). Answer: a)
The series is 16×1.5, 24×2.5, 60×3.5, 210×4.5, 945×5.5
25).8, 18, 86, 308, 828, ?The series is 16×1.5, 24×2.5, 60×3.5, 210×4.5, 945×5.5
25). Answer: d)
The series is,
8 + (2^3 + 2) = 18,
18 + (4^3 + 4) = 86,
86 + (6^3 + 6) = 308,
308 + (8^3 + 8) = 828,
828 + (10^3 + 10) = 1838
The series is,
8 + (2^3 + 2) = 18,
18 + (4^3 + 4) = 86,
86 + (6^3 + 6) = 308,
308 + (8^3 + 8) = 828,
828 + (10^3 + 10) = 1838
Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) If X > Y
b) If X < Y
c) If X ≥ Y
d) If X ≤ Y
e) If X = Y or cannot be established
26). I. 3x^2 – 4x – 15 = 0,
II. 3y^2 + 11y + 10 = 0
26). Answer: c)
3x^2 – 4x – 15 = 0
27). I. 3x^2 + 17x + 24 = 0,3x^2 – 4x – 15 = 0
3x^2 – 9x + 5x – 15 = 0
Gives x = -5/3, 3
3y^2 + 11y + 10 = 0
3y^2 + 6y + 5y + 10 = 0
Gives y = -2, -5/3
Hence, x ≥ y
II. 3y^2 – 4y – 32 =
27). Answer: d)
3x^2 + 17x + 24 = 0
Gives x = -3, -8/3
3y^2 – 4y – 32 = 0
3y^2 – 12y + 8y – 32 = 0
Gives y = -8/3, 4
Hence, x ≤ y
28). I. 3x^2 – 2x – 16 = 0,3x^2 + 17x + 24 = 0
Gives x = -3, -8/3
3y^2 – 4y – 32 = 0
3y^2 – 12y + 8y – 32 = 0
Gives y = -8/3, 4
Hence, x ≤ y
II. 3y^2 – 20y + 32 = 0
28). Answer: d)
3x^2 – 2x – 16 = 0
Gives x = -2, 8/3
3y^2 – 20y + 32 = 0
3y^2 – 20y + 32 = 0
Gives y = 8/3, 4
Therefore x ≤ y
29). I. 2x^2 + 5x – 12 = 0,3x^2 – 2x – 16 = 0
Gives x = -2, 8/3
3y^2 – 20y + 32 = 0
3y^2 – 20y + 32 = 0
Gives y = 8/3, 4
Therefore x ≤ y
II. 4y^2 – 19y – 30 = 0
29). Answer: e)
30). I. 2x^2 – 17x + 36 = 0,2x2 + 5x – 12 = 0
2x^2 + 8x – 3x – 12 = 0
Gives x = -4, 3/2
4y^2 – 19y – 30 = 0
4y^2 – 24y + 5y – 30 = 0
Gives y= -5/4, 6
Therefore, the relation cannot be establishe
II. 3y^2 – 2y – 8 = 0
30). Answer: a)
2x^2 – 17x + 36 = 0
2x^2 – 8x – 9x + 36 = 0
Gives x = 4, 9/2
3y^2 – 2y – 8 = 0
3y^2 – 6y + 4y – 8 = 0
Gives y= -4/3, 2
Therefore, x > y
2x^2 – 17x + 36 = 0
2x^2 – 8x – 9x + 36 = 0
Gives x = 4, 9/2
3y^2 – 2y – 8 = 0
3y^2 – 6y + 4y – 8 = 0
Gives y= -4/3, 2
Therefore, x > y
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