Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-29)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-1)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-29):

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Direction (1-10): In the following number series, a wrong number is given. Find out that wrong number.
1). 2 11 38 197 1172 8227 65806

1) Ans.(d) The series is based on the following pattern:
11 = 2 × 3 + 5
38 = 11 × 4 - 6
197 = 38 × 5 + 7
1172 ≠ 197 × 6 - 8
1172 is wrong and it should be replaced by 197 × 6 - 8 = 1174

2. 16 19 21 30 46 71 107

2) Ans.(a)
The series is based on the following pattern:
107 - 71 = 36
71 - 46 = 25
46 - 30 = 16
30 - 21 = 9
21 - 19 = 2≠4
19 should be replaced by 17 for which 21 - 17 = 4

3. 7 9 16 25 41 68 107 173

3) Ans.(d)
The series is based on the following pattern:
16 = 9 + 7
25 = 16 + 9
41 = 25 + 16
68 ≠ 41 + 25
68 should be replaced by 66.

4. 4 2 3.5 7.5 26.25 118.125

4) Ans.(c)
The series is based on the following pattern: ×0.5,×1.5,×2.5,×3.5,×4.5
Obviously, 3.5 Is the wrong number which should be replaced by 3.

5). 16 4 2 1.5 1.75 1.875

5) Ans.(b)
The series is based on the following pattern: ×0.25,×0.5,×0.75,×1,×1.25
Obviously, 1.75 is the wrong number which should be replaced by 1.5.

Directions (6-10): What approximate value should come in place of the question mark (?) in the following questions?
6. 57% of 394 - 2.5% of 996 = ?

6) Ans.(c)
Sol. Approx value
= (50 + 7)% of 400-1/40×1000
= 200 + 28 - 25 = 203 ≈ 200
Since we have taken excess value in calculation, we will take less than the calculated value as the approximate value.

7. 96.996 × 9.669 + 0.96 = ?

7) Ans.(d)
Sol. Approx value = 97 × 9.7 = 940.9 ≈ 940

8. 3/5×1125/1228×7= ?

8) Ans.(d)
Sol. Approx value= 3/5×1125/1227×7= 3.85=4

9. (√339 ×25)÷30= ?

9) Ans.(b)
Sol. √339≈18
Then (18×25)÷30=450/30=15

10. (638 + 9709 - 216) ÷ 26 = ?

10) Ans.(e)
Sol. Approx value = (640 + 9700 - 200) ÷ 26
= 10140 ÷ 26 ≈ 390

11. 421 / 35 × 299.99 / 25.05 = ?^2

11). (?)^2 ≈ 420 / 35 × 300 / 25 = 12 × 300 / 25 = 12 × 12
? = √(12 × 12) = 12
Answer: d)

12. √(197) × 6.99 + 626.96 = ?

12). (?) ≈√(196) × 7 + 627 = 14 × 7 + 627 = 98 + 627 = 725
Answer: b)

13.19.99 × 15.98 + 224.98 + 125.02 = ?

13). ? = 19.99 × 15.98 + 224.98 + 125
≈ 20 × 16 + 225 + 125 = 320 + 225 + 125 = 670
Answer: c)

14.3214.99 + 285.02 + 600.02 – 4.01 = ?

14). ?≈ 3215 +285 +600 – 4 = 4100 – 4 ≈ 4100
Answer: b)

15. ?% of 1239.96 + 59.87% of 449.95 = 579.05

15). [(? × 1240) / 100] + [(60% of 450) / 100] ≈ 580
or, ? × 12.40 + 270 = 580
or. ? × 12.40 = 580 – 270 = 310
? = 310 / 12.40 = 25
Answer: c)

Directions (16-20): What should come in place of the question mark (?) in the following questions?
16. 475+64% of 950=900+?

16) Ans.(a)
475+64% of 950-900 = 475+608-900 = 183

17. (0.064)×(0.4)^7=(0.4)^?×(0.0256)^2

17) Ans.(b)
(0.064)×(0.4)^7=(0.4)^?×(0.0256)^2
(0.4)^3×(0.4)^7 〖/(0.4)〗^(4×2)=(0.4)^?
? = 3+7-8 = 2

18. 133.008×2.97-111.87+74.13=?

18) Ans.(c)
133.008×2.97-111.87+74.13 ≈ 357

19. 20% of 1/5 of 2250 = 50 + ?

19) Ans.(d)
? = 90 – 50 = 40

20. 9 + 0.99 + 9.09 + 99.09 + 90.09 =?

20) Ans.(a)
9 + 0.99 + 9.09 + 99.09 + 90.09 = 208.26

21. [ (16)^3 × (6)^2 ] / (4)^3 = ?^2

21). ?^2 = (16^3 × 6^2) / 4^3 = 4^6 × 6^2 / 4^3
4^3 × 6^2 = 8^2 × 6^2
? = 8 × 6 = 48
Answer: d)

22. √(2304)×√? = 2832

22). 48 ×√? = 2832
√? = 2832 / 48 = 59
? = 3481
Answer: a)

23. 345 / 23 / 5 = √√?

23). 345 / (23 × 5) = √√ ?
Or, √√? = 3
? = (3 × 3)^2 = 81
Answer: d)

24. 3√103823 = ? + 23

24). ? + 23 = 3√103823
= 3√(47 × 47 × 47)
Or, ? = 47 – 23 = 24
Answer: d)

25. 150% of 750 / 25 – 16 = ? % of 1015 / 35

25). 150% of 750 / 25 – 16 = ? % of 1015 / 35
Or, (? × 1015) / (35 × 100) = [(150 × 750) / (100 × 25)] - 16
Or, (?× 29) / 100 = 45 – 16 = 29
? = 100
Answer: e)

Directions (26-30): In the following questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer.
(a) If x ≥ y
(b) If x ≤ y
(c) If x < y
(d) If x > y
(e)If relationship between x and y cannot be established

26) I. x^2-3x-88=0
II. y^2+8y-48=0

26) Ans.(e)
Sol. x^2-3x-88=0
⇒x^2-11x+8x-88=0
⇒x(x-11)+8(x-11)=0
⇒ (x+8)(x-11)=0
⇒ x = -8 or 11
II. y^2+8y-48=0
⇒y^2+12y-4y-48=0
⇒y(y+12)-4(y+12)=0
⇒ (y-4)(y+12)=0
⇒ y = -12 or 4
Hence, it cannot be established.

27) I. 5x^2+29x+20=0
II. 25y^2+25y+6=0

27) Ans.(c)
Sol. I. 5x^2+29x+20=0
⇒ 5x^2+25x+4x+20=0
⇒ 5x(x+5)+4(x+5)=0
⇒ (5x+4)(x+5)=0
⇒ x=-5 or (-4)/5
II. 25y^2+25y+6=0
⇒ 25y^2+15y+10y+6=0
⇒5y(5y+3)+2(5y+3)=0
⇒ (5y+2)(5y+3)=0
⇒ y=(-3)/5 or (-2)/5
Hence, x < y

28) I. 2x^2-11x+12=0
II. 2y^2-19y+44=0

28) Ans.(b)
Sol. I. 2x^2-11x+12=0
⇒ 2x^2-8x-3x+12=0
⇒ 2x(x-4)-3(x-4)=0
⇒ (2x-3)(x-4)=0
⇒ x=4 or 3/2
II. 2y^2-19y+44=0
⇒ 2y^2-8y-11y+44=0
⇒ 2y(y-4)-11(y-4)=0
⇒ (y-4)(2y-11)=0
⇒ y = 4 or 11/2
Hence, x ≤ y

29) I. 3x^2+10x+8=0
II. 3y^2+7y+4=0

29) Ans.(b)
Sol. I. 3x^2+10x+8=0
⇒ 3x^2+6x+4x+8=0
⇒ 3x(x+2)+4(x+2)=0
⇒ (3x+4)(x+2)=0
⇒ x = -2 or (-4)/3
II. 3y^2+7y+4=0
⇒3y^2+3y+4y+4=0
⇒ 3y(y+1)+4(y+1)=0
⇒ (y+1)(3y+4)=0
⇒ y=-1 or (-4)/3
Hence, x ≤ y

30) I. 2x^2+21x+10=0
II. 3y^2+13y+14=0

30) Ans.(e)
Sol. I. 2x^2+21x+10=0
⇒ 2x^2+20x+x+10=0
⇒ 2x(x+10)+1(x+10)=0
⇒ (2x+1)(x+10)=0
⇒ x=(-1)/2 or -10
II. 3y^2+13y+14=0
⇒ 3y^2+6y+7y+14=0
⇒ 3y(y+2)+7(y+2)=0
⇒ (3y+7)(y+2)=0
⇒ y=-2 or y=(-7)/3
Hence, relationship between x and y cannot be established