Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-28):
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Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). 348÷29×10+126 = ? + 220
1). Answer: b)
? = 348 ÷ 29 x 10 + 126 - 220
= 12 × 10 + 126 - 220 = 120 + 126 - 220 = 246 - 220 = 26
2. (4×4)^3 ÷ (512÷8)^4 × (32×8)^4 = (2+2)^(?+4)? = 348 ÷ 29 x 10 + 126 - 220
= 12 × 10 + 126 - 220 = 120 + 126 - 220 = 246 - 220 = 26
2). Answer: b)
(2 + 2)^(?+ 4) = (4 × 4)^3 ÷ (512 ÷ 8)^4 x (32 × 8)^4 = (4)^(2 x 3) ÷ (4)^(3 x 4) × (4)^(4 x4)
= 4^(6 - 12 + 16) = 4^10
or, (4) ^(? + 4) = 4^10
or, ? + 4 = 10
?= 10 - 4 = 6
3. [(2√392) - 21] + (√8 - 7)^2 = (?)^2(2 + 2)^(?+ 4) = (4 × 4)^3 ÷ (512 ÷ 8)^4 x (32 × 8)^4 = (4)^(2 x 3) ÷ (4)^(3 x 4) × (4)^(4 x4)
= 4^(6 - 12 + 16) = 4^10
or, (4) ^(? + 4) = 4^10
or, ? + 4 = 10
?= 10 - 4 = 6
3). Answer: c)
[(2√392) - 21] + (√8 - 7)^2 = (?)^2
Or, (?)^2 = [2√(49×8) – 21+8+49-14√8
= 14√8 – 21 + 8 + 49 - 14√8 = 57-21 = 36
? = √(6×6) = 6
[(2√392) - 21] + (√8 - 7)^2 = (?)^2
Or, (?)^2 = [2√(49×8) – 21+8+49-14√8
= 14√8 – 21 + 8 + 49 - 14√8 = 57-21 = 36
? = √(6×6) = 6
4. 2 1/4 + 5 1/6 – 4 1/8 = ? + 1 1/12
4). Answer: e)
? = (2 + 5 – 4 – 1) + (1/4 + 1/6 – 1/8 – 1/12)
= 2 + (6 + 4 – 3 - 2) / 24 = 2 + 5/24 = 2 5/24
? = (2 + 5 – 4 – 1) + (1/4 + 1/6 – 1/8 – 1/12)
= 2 + (6 + 4 – 3 - 2) / 24 = 2 + 5/24 = 2 5/24
5). 76% of 1285 = 35% of 1256 + ?
5). Answer: d)
? = 76% of 1285 - 35% of 1256
= [(76x1285)/100] – [(35x1256)/100]
= 976.6 - 439.6 = 537
? = 76% of 1285 - 35% of 1256
= [(76x1285)/100] – [(35x1256)/100]
= 976.6 - 439.6 = 537
6. {√8+[-√49 + (√225)]} = (?)^2 – 21
6). Answer: b)
(?)2 = {√(8+[-√49 + (√225)])} + 21
= {√(8+[-√49 + 15])} + 21 = √(8 + 8) + 21
?2 = 4 + 21 = 25
? = √(5×5) = 5
(?)2 = {√(8+[-√49 + (√225)])} + 21
= {√(8+[-√49 + 15])} + 21 = √(8 + 8) + 21
?2 = 4 + 21 = 25
? = √(5×5) = 5
7. 2/7 of 5033 + 78% of 650 = (?)^2 + 181
7). Answer: a)
(?)^2 + 181 = (2/7) x 5033 + [(78x650) / 100] = 1438 + 507 = 1945
or, (?)^2 = 1945 - 181 = 1764
? = √1764 = 42
(?)^2 + 181 = (2/7) x 5033 + [(78x650) / 100] = 1438 + 507 = 1945
or, (?)^2 = 1945 - 181 = 1764
? = √1764 = 42
8. 4468 + 246.8 + 1468.28 – 6326.68 + 1248.6 = ?
8). Answer: b)
? = 4468 + 246.8 + 1468.28 - 6326.68 + 1248.6
= 7431.68 - 6326.68 = 1105
9. (17.4)^2 + (18.2)^2 – (12.8)^2 = ?? = 4468 + 246.8 + 1468.28 - 6326.68 + 1248.6
= 7431.68 - 6326.68 = 1105
9). Answer: a)
? = (17.4)^2 + (18.2)^2 - (12.8)^2 = 302.76 + 331.24 - 163.84
= 634 - 163.84 = 470.16
? = (17.4)^2 + (18.2)^2 - (12.8)^2 = 302.76 + 331.24 - 163.84
= 634 - 163.84 = 470.16
10. 32% of 480 + 5/7 of 1890 – 27% of 820 = ?
10). Answer: d)
? = [(32 x 480)/100] + (5/7)×1890 – (27×820)/100
= 153.6 + 1350 - 221.4 = 1282.2
? = [(32 x 480)/100] + (5/7)×1890 – (27×820)/100
= 153.6 + 1350 - 221.4 = 1282.2
Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11. (2914.01 ÷ 31.1) ÷ (1.99 ÷ 3.01) × 510.01 ÷ 169.99 = ?
11). Answer: b)
? = (2914.01 -:-- 31.1) ÷ (1.99 ÷ 3.01) x 510.01 ÷ 169.99
? = (2914 ÷ 31) ÷ (2/3) × (510/170)
= (2914/31) × (3/2) × (510/170) = (2914x3x3) / (31 × 2)
= 47 x 9 = 423
? = (2914.01 -:-- 31.1) ÷ (1.99 ÷ 3.01) x 510.01 ÷ 169.99
? = (2914 ÷ 31) ÷ (2/3) × (510/170)
= (2914/31) × (3/2) × (510/170) = (2914x3x3) / (31 × 2)
= 47 x 9 = 423
12. (4810 / √2310) × 22.678 + 130.13 = ?
12). Answer: d)
? = (4810 / √2310) × 22.678 + 130.13
= (4810/48) × 22.7 + 130
= 100 × 22.7 + 130 = 2270 + 130 = 2400
13. 11.25% of 175 + 8.72% of 763 + 38% of 380 = ?? = (4810 / √2310) × 22.678 + 130.13
= (4810/48) × 22.7 + 130
= 100 × 22.7 + 130 = 2270 + 130 = 2400
13). Answer: a)
? = [11.25 / 100] × 175 + (8.72 / 100)×763 + (38/100)×380
= 20 + 66 + 144 = 230
14.(26.89 × 168.98 + 4317 – 6336.98) / √230 = ?? = [11.25 / 100] × 175 + (8.72 / 100)×763 + (38/100)×380
= 20 + 66 + 144 = 230
14). Answer: c)
? = (26.89 x 168.98 + 4317- 6339.98) / √230
= (27 x 169 + 4317 – 6340) / √230
=( 4563 + 4317 – 6340) / 15
= (8880 – 6340) / 15 = 2540/15 = 167
15. √(1087.9996) + (5.1961)^2 = ? ÷ (2 / 10.7960)? = (26.89 x 168.98 + 4317- 6339.98) / √230
= (27 x 169 + 4317 – 6340) / √230
=( 4563 + 4317 – 6340) / 15
= (8880 – 6340) / 15 = 2540/15 = 167
15). Answer: e)
√(1087.9996) + (5.1961)2 = ? ÷ (2 / 10.7960)
? = [√(1089) + (5)2] × (2/11)
= (33 + 25) x (2/11) = (58 × 2) / 11 = 11
16. √3598.9 x [(10008.99)^2 / 10009.001] x 0.4987 = ?√(1087.9996) + (5.1961)2 = ? ÷ (2 / 10.7960)
? = [√(1089) + (5)2] × (2/11)
= (33 + 25) x (2/11) = (58 × 2) / 11 = 11
16). Answer: c)
? = √3598.9 x [(10008.99)2 / (10009.001)] x 0.4987
= √3600 x [(10009)2 / 10009] x 0.4987
= 60 x 10009 x 0.5 = 30 x 10009 = 300270
17. 39.05 x 14.95 - 27.99 x 10.12 = (36 + ?) × 5? = √3598.9 x [(10008.99)2 / (10009.001)] x 0.4987
= √3600 x [(10009)2 / 10009] x 0.4987
= 60 x 10009 x 0.5 = 30 x 10009 = 300270
17). Answer: a)
39.05 x 14.95 - 27.99 x 10.12 = (36 + ?)5
or, 39 x 15 - 28 x 10 = 180 + 5 x (?)
or, 5 x ? = 585 - 280 - 180 = 585 - 460 = 125
? = 125/5 = 25
18. 68.25 x 170 + 28 x 16.5 -125 x 16.5 = ?39.05 x 14.95 - 27.99 x 10.12 = (36 + ?)5
or, 39 x 15 - 28 x 10 = 180 + 5 x (?)
or, 5 x ? = 585 - 280 - 180 = 585 - 460 = 125
? = 125/5 = 25
18). Answer: c)
? = 68.25 x 170 + 28 x 16.5 - 125 x 16.5 = 11602.5 + 462 - 2062.5
= 12064.5 - 2062.5 = 10002 = 10000
? = 68.25 x 170 + 28 x 16.5 - 125 x 16.5 = 11602.5 + 462 - 2062.5
= 12064.5 - 2062.5 = 10002 = 10000
19. 487.532 +2849.029 - 675.48 = 743.095 +?
19).Answer: b)
? = 487.582 + 2849.029 - 675.48 - 743.095 = 488 + 2849 - 675 - 743
= 1919 = 1920
? = 487.582 + 2849.029 - 675.48 - 743.095 = 488 + 2849 - 675 - 743
= 1919 = 1920
20.142% of 3915 +2874 = 12600 -?
20). Answer: e)
? = 12600 - (142 / 100) x 3915 - 2874
= 12600 - 5560 - 2874 = 4166 = 4165
Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.? = 12600 - (142 / 100) x 3915 - 2874
= 12600 - 5560 - 2874 = 4166 = 4165
21. 4, 6, 24, 130, 924, ?
21). Answer: d)
The series is based on the following pattern:
*1 + 2, *3 + 6, *5 + 10, *7 + 14, *9 + 18
The series is based on the following pattern:
*1 + 2, *3 + 6, *5 + 10, *7 + 14, *9 + 18
22. 26, 13, 20, 51, 180, ?
22). Answer: a)
The series is based on the following pattern:
*0.5 + 0, *1.5 + 0.5, *2.5 + 1, *3.5 + 1.5, *4.5 + 2
The series is based on the following pattern:
*0.5 + 0, *1.5 + 0.5, *2.5 + 1, *3.5 + 1.5, *4.5 + 2
23. 15, 28, 87, 344, 1725, ?
23). Answer: c)
The series is based on the following pattern:
*2 – 2, *3 + 3, *4 – 4, *5 + 5, *6 – 6
24. 5, 6, 7.5, 9.75, ?, 18.4275The series is based on the following pattern:
*2 – 2, *3 + 3, *4 – 4, *5 + 5, *6 – 6
24). Answer: b)
The series is based on the following pattern:
*1.2, *1.25, *1.3, *1.35, *1.4
The series is based on the following pattern:
*1.2, *1.25, *1.3, *1.35, *1.4
25. 56, 60, 51, 67, 42, ?
25). Answer: e)
The series is based on the following pattern:
+ 2², – 3², + 4², – 5², + 6²
The series is based on the following pattern:
+ 2², – 3², + 4², – 5², + 6²
Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) x > y
b) x < y
c) x ≥ y
d) x ≤ y
e) x = y or relation cannot be established
II. 3y^2 – 11y + 6 = 0
26). Answer: e)
12x² – 5x – 3 = 0
12x² + 4x – 9x – 3 = 0
Gives x = -1/3, 3/4
3y² – 11y + 6 = 0
3y² – 9y – 2y + 6 = 0
Gives y = 2/3, 3
Clearly, the relation cannot be established
27). I. 6x^2 + 7x + 2 = 0,12x² – 5x – 3 = 0
12x² + 4x – 9x – 3 = 0
Gives x = -1/3, 3/4
3y² – 11y + 6 = 0
3y² – 9y – 2y + 6 = 0
Gives y = 2/3, 3
Clearly, the relation cannot be established
II. 15y^2 – 38y – 40 = 0
27). Answer: e)
6x² + 7x + 2 = 0
6x² + 4x + 3x + 2 = 0
Gives x = -2/3, -1/2
15y² – 38y – 40 = 0
15y² + 12y – 50y – 40 = 0
Gives y = -4/5, 10/3
Clearly, the relation cannot be established
28). I. 3x^2 – 25x + 52 = 0,6x² + 7x + 2 = 0
6x² + 4x + 3x + 2 = 0
Gives x = -2/3, -1/2
15y² – 38y – 40 = 0
15y² + 12y – 50y – 40 = 0
Gives y = -4/5, 10/3
Clearly, the relation cannot be established
II. 2y^2 – 7y + 3 = 0
28). Answer: a)
3x² – 25x + 52 = 0
3x² – 12x – 13x + 52 = 0
Gives x = 4, 13/3
2y² – 7y + 3 = 0
2y² – 6y – y + 3 = 0
So y = 1/2, 3
Clearly, x > y
29). I. x^2 = 1156,3x² – 25x + 52 = 0
3x² – 12x – 13x + 52 = 0
Gives x = 4, 13/3
2y² – 7y + 3 = 0
2y² – 6y – y + 3 = 0
So y = 1/2, 3
Clearly, x > y
II. y = √1156
29). Answer: d)
x² = 1156,
So x = -34, 34
y = √1156
So y = 34
Clearly, y≥x
30). I. x^2 – √3969 = √6561,x² = 1156,
So x = -34, 34
y = √1156
So y = 34
Clearly, y≥x
II. y^2 – √1296 = √4096
30). Answer: e)
x² – √3969 = √6561
x² – 63 = 81
x² = 144
So x = -12, 12
y² – √1296 = √4096
y² – 36 = 64
y² = 100
So y = -10, 10
Clearly, the relation cannot be established
x² – √3969 = √6561
x² – 63 = 81
x² = 144
So x = -12, 12
y² – √1296 = √4096
y² – 36 = 64
y² = 100
So y = -10, 10
Clearly, the relation cannot be established
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