Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-18):
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Direction (1-10): What value should come in place of question mark (?) in the following questions?
1).(2401)^(3/4) ÷ 1/343 ÷ (49)^(7/2) = (7)^?
1). Answer: b)
(7^4)^(3/4) ÷ 7^(-3) ÷ 7^7 = 7^?
or, 7^3 ÷ 7^(-3) ÷ 7^7 = 7^?
or, 7^(3+3-7) = 7^?
or, 7^(-1) = 7^?
? = - 1
2. 28.2% of 125 + 7.8% of 175 = 20% of ?(7^4)^(3/4) ÷ 7^(-3) ÷ 7^7 = 7^?
or, 7^3 ÷ 7^(-3) ÷ 7^7 = 7^?
or, 7^(3+3-7) = 7^?
or, 7^(-1) = 7^?
? = - 1
2). Answer: c)
? × 20 / 100 = 28.2 × 125 / 100 + 7.8 × 175 / 100
? × 20 / 100 = 35.25 + 13.65 = 48.9
? = 5 × 48.9 = 244.5
3. ³√17576 × 676 ÷ ³√(2197)^3 = (4096)^(?/8)? × 20 / 100 = 28.2 × 125 / 100 + 7.8 × 175 / 100
? × 20 / 100 = 35.25 + 13.65 = 48.9
? = 5 × 48.9 = 244.5
3). Answer: a)
(263)^(1/3) × (26)² ÷ 2197 = (4096)^(?/8)
26 × (26)² ÷ (13)³ = (4096)^(?/8)
(26/13)³ = (4096)^(?/8)
Let ? = x
8^1 = (4096)^(x/8) = 8^(4x/8) = 8^(x/2)
1 = x/2
x=2
(263)^(1/3) × (26)² ÷ 2197 = (4096)^(?/8)
26 × (26)² ÷ (13)³ = (4096)^(?/8)
(26/13)³ = (4096)^(?/8)
Let ? = x
8^1 = (4096)^(x/8) = 8^(4x/8) = 8^(x/2)
1 = x/2
x=2
4. 252252 ÷ ? = 63 × 77
4). Answer: e)
252252 ÷ ? = 63 × 77
? = 252252 / (63 × 77)
? = 252252/4851 = 52
252252 ÷ ? = 63 × 77
? = 252252 / (63 × 77)
? = 252252/4851 = 52
5). 125% of 225% of 7 / 6 of 4128 = ?
5). Answer: c)
? = 125 × 225 × 7 × 4128 / (100 × 100 × 6) = 13545
? = 125 × 225 × 7 × 4128 / (100 × 100 × 6) = 13545
6. 7.12% of 8500 - 3.6% of 5500 = 1.6% of?
6). Answer: e)
? = {(7.12 × 8500 /100) – (3.6 × 5500 /100)} × 100/1.6
? = (605.2 -198) × 100 /1.6
? = 407.2 ×100 /1.6 = 25450
? = {(7.12 × 8500 /100) – (3.6 × 5500 /100)} × 100/1.6
? = (605.2 -198) × 100 /1.6
? = 407.2 ×100 /1.6 = 25450
7. 13/17 of 12/19 of 47% of 40375 = ? × 6
7). Answer: b)
? = 13 × 12 × 47 × 40375 / (17 × 19 × 100 × 6)
? = 1527.5
? = 13 × 12 × 47 × 40375 / (17 × 19 × 100 × 6)
? = 1527.5
8. 4608 / ? = ? / 5202
8). Answer: d)
(?)² = 4608 × 5202
? = √(16 ×17 × 18)2 = 16 × 17 × 18 = 4896
9. (142.8 ÷ 2.4) × 7.5 ÷ 0.15 = ?(?)² = 4608 × 5202
? = √(16 ×17 × 18)2 = 16 × 17 × 18 = 4896
9). Answer: c)
? = 59.5 × 7.5 ÷ 0.15 = 2975
? = 59.5 × 7.5 ÷ 0.15 = 2975
10. (7.2)^3.2 × 1 / (7.2)^1.6 ÷ (51.84)^(-1.8) × (51.84)^(-1.2) = (7.2)^?
10). Answer: b)
(7.2)^? = (7.2)^(3.2) × (7.2)^(-1.6) ÷ (7.2)^(-3.6) × (7.2)^(-2.4)
(7.2)^? = (7.2)^(3.2 - 1.6 + 3.6 - 2.4) = (7.2)^(2.8)
? = 2.8
(7.2)^? = (7.2)^(3.2) × (7.2)^(-1.6) ÷ (7.2)^(-3.6) × (7.2)^(-2.4)
(7.2)^? = (7.2)^(3.2 - 1.6 + 3.6 - 2.4) = (7.2)^(2.8)
? = 2.8
Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11. 127% of 75 + 28% of 277 = ?
11). Answer: b)
? = 127 × 75 / 100 + 28 × 277 / 100
? = 95.25 + 77.56
? = 172.81 ≈ 173
? = 127 × 75 / 100 + 28 × 277 / 100
? = 95.25 + 77.56
? = 172.81 ≈ 173
12. ((0.18)^2 + (1.6)2)) / 0.08 = ?
12). Answer: c)
? ≈ (0.0324 + 2.56) / 0.08
? = 2.5924 / 0.08
? = 32.4 ≈ 32
13. (59.842 ÷ 1.982) × 6.97 - 17.77 × 3.2 = ?? ≈ (0.0324 + 2.56) / 0.08
? = 2.5924 / 0.08
? = 32.4 ≈ 32
13). Answer: d)
? ≈ (60 ÷ 2) × 7 - 18 × 3
? = 210 - 54 = 156 ≈ 155
14. ³√1330000 = ?? ≈ (60 ÷ 2) × 7 - 18 × 3
? = 210 - 54 = 156 ≈ 155
14). Answer: b)
(110)³ = 1331000 ≈ 1330000
15. {(7878 + 333 + 632) - (11.9 × 2.1 × 7.09)} × 2.532 = ?(110)³ = 1331000 ≈ 1330000
15). Answer: c)
? ≈ {8843 -(12 × 2 × 7)} × 2.5
? = (8843 - 168) × 2.5 = 8675 × 2.5
? = 21687.5 ≈ 21700
16. 159 × 16 × ? = 20300? ≈ {8843 -(12 × 2 × 7)} × 2.5
? = (8843 - 168) × 2.5 = 8675 × 2.5
? = 21687.5 ≈ 21700
16). Answer: b)
? = 20300 / (159 × 16)
? = 7.979 ≈ 8
17. (141.98 × 72.02) ÷ √1300 = ?? = 20300 / (159 × 16)
? = 7.979 ≈ 8
17). Answer: c)
? = 142 × 72 /36
? = 284 ≈ 285
18. 2.81% of 1724.98 + 1.739% of 555.05 = ?? = 142 × 72 /36
? = 284 ≈ 285
18). Answer: c)
? ≈ 2.8 × 1725 / 100 + 1.74 × 555 / 100
? = 48.3 + 9.657 = 57.957 ≈ 58
? ≈ 2.8 × 1725 / 100 + 1.74 × 555 / 100
? = 48.3 + 9.657 = 57.957 ≈ 58
19. (1369.876 + 18.98 × 19.98) ÷ 24.96 = ?
19). Answer: a)
? ≈ (1370 + 19 × 20) / 25
? = (1370 + 380) / 25
? = 1750 / 25 = 70
? ≈ (1370 + 19 × 20) / 25
? = (1370 + 380) / 25
? = 1750 / 25 = 70
20.(7391.9 ÷ √1935) + (17.98 × 4.49) = ?
20). Answer: c)
? ≈ 7392 / 44 + 18 × 4.5
? = 168 + 81 = 249 ≈ 250
Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.21. 1730, 1242, 856, 560, ?? ≈ 7392 / 44 + 18 × 4.5
? = 168 + 81 = 249 ≈ 250
21). Answer: b)
The series is,
(10³ +9³) + 1 = 1730
(9³ +8³) + 1 = 1242
(8³ +7³) + 1 = 856
(7³ +6³) + 1 = 560
(6³ +5³) + 1 = 342
The series is,
(10³ +9³) + 1 = 1730
(9³ +8³) + 1 = 1242
(8³ +7³) + 1 = 856
(7³ +6³) + 1 = 560
(6³ +5³) + 1 = 342
22. 10648, 9261, 15625, 9261, ?
22). Answer: e)
The series is,
(2³ x 11³) = 10648
(3³ x 7³) = 9261
(5³ x 5³) = 15625
(7³ x 3³) = 9261
(11³ x 2³) = 10648
The series is,
(2³ x 11³) = 10648
(3³ x 7³) = 9261
(5³ x 5³) = 15625
(7³ x 3³) = 9261
(11³ x 2³) = 10648
23. 999, 973, 875, 657, ?
23). Answer: d)
The series is 1000 - 1³, 1000 - 3³, 1000 - 5³,1000 - 7³, 1000 - 9³
24. 157, 284, 375, ?, 473The series is 1000 - 1³, 1000 - 3³, 1000 - 5³,1000 - 7³, 1000 - 9³
24). Answer: a)
The series is, 500 – 7³, 500 – 6³, 500 – 5³, 500 – 4³, 500 – 3³
The series is, 500 – 7³, 500 – 6³, 500 – 5³, 500 – 4³, 500 – 3³
25. 1, 9, 35, 91, ?, 341
25). Answer: c)
The series is, 0³+1³, 1³+2³, 2³+3³, 3³+4³, 4³+5³, 5³+6³
The series is, 0³+1³, 1³+2³, 2³+3³, 3³+4³, 4³+5³, 5³+6³
Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or no relation can be established between x and y.
II. y^2 + 6y + 8 =0
26). Answer: c)
I. x² + 18x + 72 = 0
or, x² + 12x + 6x + 72 =0
or, x(x + 12) + 6(x + 12) = 0
x = -6, -12
II. y² + 6y + 8 =0
or, y² + 4y + 2y + 8 =0
or, y(y + 4) + 2(y + 4) = 0
y = -2, -4
Hence x < y
I. x² + 18x + 72 = 0
or, x² + 12x + 6x + 72 =0
or, x(x + 12) + 6(x + 12) = 0
x = -6, -12
II. y² + 6y + 8 =0
or, y² + 4y + 2y + 8 =0
or, y(y + 4) + 2(y + 4) = 0
y = -2, -4
Hence x < y
27.I. 8x^2 – 22x + 15 = 0
II. 3y^2 – 13y + 14 = 0
27). Answer: c)
I. 8x² – 22x + 15 = 0
or, 8x² - 12x - 10x + 15 = 0
or, 4x(2x - 3) - 5(2x - 3) = 0
or, (4x - 5) (2x - 3) = 0
x = 5/4, 3/2
II. 3y² – 13y + 14 = 0
or, 3y² - 6y - 7y + 14 =0
or, 3y(y - 2) - 7(y - 2) = 0
or, (3y - 7) (y - 2) = 0
y = 7/3, 2
Hence x < y
28. I. 9x^2 – 26x + 16 = 0I. 8x² – 22x + 15 = 0
or, 8x² - 12x - 10x + 15 = 0
or, 4x(2x - 3) - 5(2x - 3) = 0
or, (4x - 5) (2x - 3) = 0
x = 5/4, 3/2
II. 3y² – 13y + 14 = 0
or, 3y² - 6y - 7y + 14 =0
or, 3y(y - 2) - 7(y - 2) = 0
or, (3y - 7) (y - 2) = 0
y = 7/3, 2
Hence x < y
II. 3y^2 – 16y + 20 = 0
28). Answer: d)
I. 9x² – 26x + 16 = 0
or, 9x² - 18x - 8x + 16 = 0
or, 9x(x - 2) - 8(x - 2) = 0
or, (9x - 8) (x - 2) = 0
x = 8/9, 2
II. 3y² – 16y + 20 = 0
or, 3y² - 6y - 10y + 20 =0
or, 3y(y - 2) - 10(y - 2) = 0
or, (3y - 10) (y - 2) = 0
y = 2, 10/3
Hence x ≤ y
29. I. 10x^2 – 17x + 7 = 0I. 9x² – 26x + 16 = 0
or, 9x² - 18x - 8x + 16 = 0
or, 9x(x - 2) - 8(x - 2) = 0
or, (9x - 8) (x - 2) = 0
x = 8/9, 2
II. 3y² – 16y + 20 = 0
or, 3y² - 6y - 10y + 20 =0
or, 3y(y - 2) - 10(y - 2) = 0
or, (3y - 10) (y - 2) = 0
y = 2, 10/3
Hence x ≤ y
II. 15y^2 – 19y + 6 = 0
29). Answer: a)
I. 10x² – 17x + 7 = 0
or, 10x² - 10x - 7x + 7 = 0
or, 10x(x - 1) - 7(x - 1) = 0
or, (10x - 7) (x - 1) = 0
x = 7/10, 1
II. 15y² – 19y + 6 = 0
or, 15y² - 10y - 9y + 6 =0
or, 5y(3y - 2) – (3y - 2) = 0
or, (3y - 2) (5y - 3) = 0
y = 3/5, 2/3
Hence x > y
30. I. 12x^2 + 19x + 5 = 0I. 10x² – 17x + 7 = 0
or, 10x² - 10x - 7x + 7 = 0
or, 10x(x - 1) - 7(x - 1) = 0
or, (10x - 7) (x - 1) = 0
x = 7/10, 1
II. 15y² – 19y + 6 = 0
or, 15y² - 10y - 9y + 6 =0
or, 5y(3y - 2) – (3y - 2) = 0
or, (3y - 2) (5y - 3) = 0
y = 3/5, 2/3
Hence x > y
II. 5y^2 + 16y + 3 = 0
30). Answer: e)
I. 12x² + 19x + 5 = 0
or, 12x² + 4x + 15x + 5 =0
or, 4x(3x + 1) + 5(3x + 1) = 0
or, (4x + 5) (3x + 1) = 0
x = -5/4, -1/3
II. 5y² + 16y + 3 = 0
or,5y² + 15y + y + 3 =0
or, 5y(y + 3) + 1(y + 3) = 0
or, (5y + 1) (y + 3) = 0
y = -1/5, -3
Hence no relationship can be established.
I. 12x² + 19x + 5 = 0
or, 12x² + 4x + 15x + 5 =0
or, 4x(3x + 1) + 5(3x + 1) = 0
or, (4x + 5) (3x + 1) = 0
x = -5/4, -1/3
II. 5y² + 16y + 3 = 0
or,5y² + 15y + y + 3 =0
or, 5y(y + 3) + 1(y + 3) = 0
or, (5y + 1) (y + 3) = 0
y = -1/5, -3
Hence no relationship can be established.
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