Dear Readers, Important Practice Aptitude Questions for SBI Clerk & IBPS Exams 2017 was given here with Solutions. Aspirants those who are preparing for the Bank Examination and other Competitive Examination can use this material.
1). Let N = 3276000.
3.What was the total number of illiterate people in A.P. and M.P. in 2001?
4.What was the number of males in U.P. in the year 2001?
5.If in the year 2001, there was an increase of 10% in the population of U.P. and 12% in the population of M.P. compared to the previous year, and then what was the ratio of populations of U.P. and M.P. in 2000?
Direction (Q. 6-10): Read the following information carefully to answer the questions given below.
6). Directions (6-10):
7).Required ratio = 18 : 26 = 9 : 13
8). Required ratio = 5 : 4
9.By what percent is the number of boys in Information technology more than the number of girls in software engineering department?
10.What is the ratio of boys and girls enrolled in Software engineering department only?
Direction (Q. 1-5): Study the following chart the table and answer the questions given below.
1.What will be the percentage of total number of males in U.P., M.P. and Goa together to the total population of all the given states?
1). Let N = 3276000.
Number of males in U.P =(3/5) of (15% of N)= (3/5) × (15/100) × N = 9×(N/100)
Number of males in M.P = [3/4 of (20% of N)] = (3/4) × (20/100)×N = 15×(N/100)
Number of males in Goa = [(3/8) of (12% of N)] = (3/8) × (12/100) ×N = 4.5×(N/100)
Total number of males in these three states = (9+15+4.5) × (N/100)
= 28.5 × (N/100)
Required Percentage = {[28.5 × (N/100)] / N × 100}% = 28.5%
Answer: C 2. What is the ratio of the number of females in Tamilnadu to the number of females in Delhi?
2). Required ratio = [(4/7)of (9% of 3276000)] / [(3/5) of (8% of 3276000)]
= [(4/7) × 9] / [(3/5) × 8] = (4/7) × 9 × (5/3) × (1/8)
= 15/14 = 15:14
Answer: D
= [(4/7) × 9] / [(3/5) × 8] = (4/7) × 9 × (5/3) × (1/8)
= 15/14 = 15:14
Answer: D
3.What was the total number of illiterate people in A.P. and M.P. in 2001?
3).No. of illiterate people in A.P. = [(7/9) of (25% of 3276000)] = 637000
No. of illiterate people in M.P. = [(4/5) of (20% of 3276000)] = 524160
Total number = 637000 + 524160 = 1161160
Answer : D
No. of illiterate people in M.P. = [(4/5) of (20% of 3276000)] = 524160
Total number = 637000 + 524160 = 1161160
Answer : D
4.What was the number of males in U.P. in the year 2001?
4). Number of males in U.P. = [(3/5) of (15% of 3276000)]
= (3/5) × (15/100) × 3726000 = 294840.
Answer : E
= (3/5) × (15/100) × 3726000 = 294840.
Answer : E
5.If in the year 2001, there was an increase of 10% in the population of U.P. and 12% in the population of M.P. compared to the previous year, and then what was the ratio of populations of U.P. and M.P. in 2000?
5).Let X be the population of U.P. in 2000. Then,
Population of U.P. in 2001 = 110% of X = (110/100) × X
Also, let Y be the population of M.P. in 2000. Then,
Population of M.P. in 2001 = 112% of Y = (112/100) × Y
Ratio of populations of U.P. and M.P. in 2001 = [(110/100) × X] / [(112/100) × Y] = 110X / 112Y
From the pie-chart, this ratio is (15/20).
110X/112Y = 15/20 = X/Y = (15/20) × (112/110) = 42/55
Thus, ratio of populations of U.P. and M.P. in 2000 = X :Y = 42:55
Answer: A
Population of U.P. in 2001 = 110% of X = (110/100) × X
Also, let Y be the population of M.P. in 2000. Then,
Population of M.P. in 2001 = 112% of Y = (112/100) × Y
Ratio of populations of U.P. and M.P. in 2001 = [(110/100) × X] / [(112/100) × Y] = 110X / 112Y
From the pie-chart, this ratio is (15/20).
110X/112Y = 15/20 = X/Y = (15/20) × (112/110) = 42/55
Thus, ratio of populations of U.P. and M.P. in 2000 = X :Y = 42:55
Answer: A
Direction (Q. 6-10): Read the following information carefully to answer the questions given below.
In a college, 150 students of M.Tech. are enrolled. The ratio of boy and girls is 7: 8 respectively. There are three department namely Information Technology, Software engineering, Network Management. In Information Technology department there are 50% girls of their total number and the boys are 40% of their total number. In software engineering department, girls are 30% of their total number while boys are 30% of their total number. Network management department has girls, 20% of their total number and boys 30% of their total number. 7 boys and 9 girls are in Information Technology and Software engineering both. 6 boys and 7 girls are in Software engineering and Network management both. 5 boys and 8 girls are in Network management and Information Technology both. 2 boys and 3 girls are enrolled in all the three departments.
6.What percentages of students are enrolled in all three departments?
6). Directions (6-10):
Boys = (7/15)×150 = 70
Girls = 150 – 70 =80
Required percentage= (5/150) ×100 = 10/3 = 3 1/3%=3.3%
Answer: A
7.What is the respective ratio of boys and girls only in Information technology department?
7).Required ratio = 18 : 26 = 9 : 13
Answer: B
8.What is the ratio of number of boys in Information technology and Network management both and that of girls in and Network management only?
8). Required ratio = 5 : 4
Answer: C
9.By what percent is the number of boys in Information technology more than the number of girls in software engineering department?
9).Required percentage = [(28-24)/24] × 100 = (4/24) × 100
= (50/3) = 16 2/3%
Answer: D
= (50/3) = 16 2/3%
Answer: D
10.What is the ratio of boys and girls enrolled in Software engineering department only?
10). Required ratio = 10 : 11
Answer: A
Answer: A
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