Dear Readers, Important Practice Aptitude Questions for NICL AO & RBI Grade B 2017 Exams was given here with Solutions. Aspirants those who are preparing for Bank exams & all other Competitive examination can use this material.
Directions (Q. 1-5): Study the following information carefully to answer the questions In a schoolhas 3000 students, out of which 600 students like only Footballsports.
450 students like only Cricketsports and 400 students like only Hockeysports.
The number of students liking all the 3 sports is 150.Students likingFootball as well
as Cricketsports are 200. 300 students likeFootball as well as Hockeysports and 400students likeCricket as well as Hockeysports.
1. Find the number of students liking Hockey sports?
1).
Number of students liking Hockey sports
= 400 + 150 + 300 + 400
= 1250
Answer is: B 2.Find the number of Students notliking anysports?
2).
Number of students notliking anysports
= 3000 – (450 + 200 + 400 + 150 + 300 + 400 + 600)
= 3000 – 2500
= 500
Answer is: C
3. How many students like only one sports?
3).
Number of students like only one sport
= 450 + 600 + 400
= 1450
Answer is: E
4.How many students like at least 2 sports?
4).
Required number of students
= 200 + 300 + 400 + 150
= 1050
Answer is: A
5.Find the difference between number of students likingCricket as well as Footballsports and the number of studentslikingFootball as well as Hockeysports?
5).
Required difference
= 300 – 200
= 100
Answer is: D
Directions (Q. 6-10): Study the following information carefully and answer the question given below
There are a certain number of candidate appeared for the bank examination
conducted by three different organisations IBPS, SBI and RBI. All of the candidates
have cleared at least one bank examination. 32.5 % students cleared IBPS's
examination, 42.5 % students cleared SBI examination and 54.5 % students cleared RBI examination.
9 % students cleared only IBPS and SBI examination, 6 % students cleared only SBI and RBI examination and
7.5 % students cleared only IBPS and RBI examination.
If total number of students in the group is 800 then answer the following questions.
6. How many students are there who have cleared at most one exam conducted by these three organisations?
6).
X + K = 260 – (72 + 60) = 128 –––––– (I)
Y + K = 340 – (72 + 48) = 220 ––––––– (II)
Z + K = 436 – (48 + 60) = 328 –––––––(III)
X + Y + Z + K = 800 – (72 + 60 + 48) = 800 – 180 = 620
Now, equation (I) + (II) + (III) – equation (IV) gives
K = 28
2K = 56,
X = 100
Y = 192
Z = 300
Required number of students
= 100+ 192 + 300
= 592
Answer is: E
7. How many students cleared all three banks examination?
7).
X + K = 260 – (72 + 60) = 128 –––––– (I)
Y + K = 340 – (72 + 48) = 220 ––––––– (II)
Z + K = 436 – (48 + 60) = 328 –––––––(III)
X + Y + Z + K = 800 – (72 + 60 + 48) = 800 – 180 = 620
Now, equation (I) + (II) + (III) – equation (IV) gives
K = 28
2K = 56,
X = 100
Y = 192
Z = 300
Number of students who cleared all the three bank exams
= 28
Answer is: B
8. What is the percentage of students who cleared the exam conducted by SBI but couldn't clear the exam conducted by RBI?
8).
X + K = 260 – (72 + 60) = 128 –––––– (I)
Y + K = 340 – (72 + 48) = 220 ––––––– (II)
Z + K = 436 – (48 + 60) = 328 –––––––(III)
X + Y + Z + K = 800 – (72 + 60 + 48) = 800 – 180 = 620
Now, equation (I) + (II) + (III) – equation (IV) gives
K = 28
2K = 56,
X = 100
Y = 192
Z = 300
Required %
= 264/800 × 100
= 33%
Answer is: D
9. What is the percentage of students who cleared the only examination conducted by IBPS?
9).
X + K = 260 – (72 + 60) = 128 –––––– (I)
Y + K = 340 – (72 + 48) = 220 ––––––– (II)
Z + K = 436 – (48 + 60) = 328 –––––––(III)
X + Y + Z + K = 800 – (72 + 60 + 48) = 800 – 180 = 620
Now, equation (I) + (II) + (III) – equation (IV) gives
K = 28
2K = 56,
X = 100
Y = 192
Z = 300
Required %
= 100/800 × 100
= 12.5%
Answer is: C
10.How many students are there who cleared examinations conducted by at least two organisations?
10).
X + K = 260 – (72 + 60) = 128 –––––– (I)
Y + K = 340 – (72 + 48) = 220 ––––––– (II)
Z + K = 436 – (48 + 60) = 328 –––––––(III)
X + Y + Z + K = 800 – (72 + 60 + 48) = 800 – 180 = 620
Now, equation (I) + (II) + (III) – equation (IV) gives
K = 28
2K = 56,
X = 100
Y = 192
Z = 300
Required number of students
= 72 + 48 + 60 + 28
= 208
Answer is: A
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