All Important Aptitude Shortcuts and Mind Tricks for Problems on Ages:
Dear Readers, All Important Aptitude Shortcuts methods and tricks for Age Related Problems was given below. Candidates those who are preparing for Upcoming IBPS PO/Clerk 2017 and other competitive Exams can use this shortcut.
Age Aptitude Tricks
1) The ratio of Asha and Sushma are in ratio 3:4 after 8 year the ratio of their ages will be 7:8. What is difference in years between their ages?
8 years × (difference 8-7) / (7×4) – (8×3)
= 8 × 1 / 28-24
Difference =8/4 = 2
2) 10 years ago ration of ages of A and B was 3 : 1 and after 10 years the ratio of their ages become 2 : 1 find the sum of present ages?
Given total years 10 and 10 so we take 20 years
20×1 / 1 = 20
A B
10 years ago 3×20 : 1 × 20
Present age 60+10 : 20+10
Sum = 100 years
3) 5 years ago ratio of age A and B are 5 : 8 and after 5 years it will become 5 : 9 find present age?
1). Ratio between the ages of mother and her daughter 4 years ago was 19 : 6. If difference between ages of mother and daughter is 28 years what will be the ratio of their present age?
2). 3 years ago A was 4 times as old as B. after 18 years A age will exceed B’s age by 12 years. The ratio of present ages of A and B is?
3). Divya got married 6 years ago. Today her age is 1 ¼ times her age at the time of marriage. His son age is 1/10 times her age. Age of her son is.
1). Five years ago the sum of the ages of father and son was 60 years. The ratio present ages is 4 : 1 present age of father is.
Present age of F + S = 60 + 10 = 70
F : S
4 : 1 ( present age)
Present age of F = 14 × 4 = 56 years
1). Sum of ages of father and son is 46 years. Seven years ago the product of their ages was 4 times the father age at that time. Find present age of father and son?
(F-7) ×(S-7) = 4 × (F –7)
S = 11 years (present)
F = 35 years (present)
1). Ratio of Arjun and Bhuvan age is 3 : 5. Ratio of Bhuvan and Cibi is 2 : 3. If Arjun is two fifth of Cibi what is Arjun’s age?
No one’s age is given it can’t be determined
1). The Average of 8 men is increased by 2 years when two of them whose ages are 21 and 23 are replaced by Two new men. The average of two new men is?
Thus in numerator there must be changed of 16 to change average age by 2
Increase 2 years = 8 × 2 = 16
Two men = 21 + 23 = 44
= 16 +44 = 60
Average 60/2 = 30 years
2). The average age of family of 10 members is 20 years. If the age of youngest member of the family is 10 years then the average of the member of family just before the birth of youngest member was approximately?
Here number is not constant and notion of time too
Thus total age = 20 × 10 = 200
10 years ago = 200 (10 ×10)
Average = 100/9
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