Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-7)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-7):

Dear Readers, Nowadays most of the aspirants are facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.

Here in Scoring Part we are providing 10 Questions in simplification, 10 Questions in Approximation, 5 Questions in number Series and 5 Questions in Quadratic Equations, total 30 questions in 20 Minutes. By practicing these questions regularly you can increase your calculation speed and it will help you to increase your score.

Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). (139.93 × 24.102) - (27.89 × 7.53) = ?

1). Answer: d)
? ≈ (140 × 24) - (28 × 7.5)
= 3360 - 210 = 3150

2. (3248% of 55.055) ÷ 27.98 = ?

2). Answer: c)
? ≈ (3248 × 55 / 100) ÷ 28
? = 3248 × 55 / 2800
? = 63.8 ≈ 64

3. √10600 × ³√19680 = ?

3). Answer: a)
(103)^2 = 10609
√10600 ≈103
(27)^3 = 19683
Since, ³√19680 ≈ 27
? ≈ 103 × 27 = 2781 ≈ 2780

4. 6844 ÷ √3360 + 255.65 ÷ 7.98 = ?

4). Answer: c)
(58)^2 = 3364
Therefore, √3360 ≈ 58
? = 6844 / 58 + 256 / 8
? = 118 + 32 = 150

5. (248% of 17855) ÷ 23.98 = ?

5). Answer: e)
? ≈ (248 × 17855/100) ÷ 24
? = 44280.4 / 24 ≈ 1845

6. (48.048 ÷ 11.911) × √? = 112.012

6). Answer: b)
√? ≈ 112 / (48 ÷ 12)
√? = 112/4 = 28
? = 28^2 = 784

7. 4140.04 ÷ 36.06 + 55 × (8.998)^2 = ?

7). Answer: a)
? ≈ 4140/36 + 55 × (9)^2
? = 115 + 4455 = 4570

8. 32.48% of 1808 + 22.94% of 1508 = ?

8). Answer: c)
? ≈ 32.5 × 1800 / 100 + 23 × 1500 / 100
= 585 + 345 = 930

9. 3√10650 = ?

9). Answer: d)
(22)^3 = 10648
Therefore, 3√10650 ≈ 22

10. (10)^7.3 ÷ (100)^4.15 × (1000)^2 + 99999 = ? × 10^5

10). Answer: b)
? × 10^5 = (10)^7.3 ÷ (10^2)^4.15 × (10^3)^2 + 99999
? × 10^5= (10)^7.3 ÷ (10)^8.3 × (10)^6 + 99999
? × 10^5= (10)^(7.3 – 8.3 + 6) + 99999
? × 10^5 = (10)5 + 99999 ≈ (10)^5 + (10)^5
? × 10^5 = 2 × 10^5
? = 2

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11.(2197)^-2 ÷ (28561)^-3 = 169 × (13)^?

11). Answer: c)
(13^3)^-2 ÷ (13^4)^-3 = 169 × (13)^?
(13)^-6 ÷ (13)-12 = 169 × (13)^?
(13)^-6+12 = 169 × (13)^?
(13)^6 = 169 × (13)^?
169 × (13)^4 = 169 × (13)^?
? = 4

12. 7/12 of 5/21 of 1/23 of 48% of 28980 = ?

12). Answer: a)
? = (7 × 5 × 48 × 28980) / (12 × 21 × 23 × 100)
? = 84

13. {14641 ÷ 11} × 3.5 = ?

13). Answer: d)
? = (14641 / 11) × 3.5
? = 1331 × 3.5
? = 4658.5

14. (28)^4.9 × (7)^0.1 × (2)^0.2 ÷ {(7)^-2.5 × (2)^-5} = (28)^?

14). Answer: b)
28^? = (28)^4.9 × (7)^0.1 × (4)^0.1 ÷ (7^-2.5 × 4^-2.5)
28)? = (28))4.9 × (28))0.1 ÷ (28))-2.5
28)? = (28)^(4.5+0.1+2.5)
? = 7.1

15.(28.5% of 144) × 25 = ? × 6

15). Answer: a)
6 × ? = (28.5 × 144 / 100) × 25
6 × ? = 41.04 × 25 = 1026
? = 1026 / 6 = 171

16. (8)^7.2 ÷ (512)^1.6 × (4096)^-1.2 ÷ (32768)^-1 = (8)^?

16). Answer: b)
8^? = (8)^7.2 ÷ (8^3)^1.6 × (8^4)^-1.2 ÷ (8^5)^-1
8^? = (8)^7.2 ÷ 8^4.8 × 8^-4.8 ÷ 8^- 5
8^? = (8)^(7.2-4.8-4.8+5) = (8)^2.6
? = 2.6

17. 45.5% of 960 + 13.5% of 320 = ?% of 3000

17). Answer: c)
3000 ×? / 100 = 45.5 × 9.6 + 13.5 × 3.2
3000 ×? / 100 = 436.8 + 43.2 = 480
? = 480 × 100 / 3000 = 16

18. {(13824)2/3 ÷ 16} × 7.5 = ?

18). Answer: c)
? = {(24^3)^2/3 ÷ 16) × 7.5
? = {(24)^2 ÷ 16} × 7.5
? = 36 × 7.5 = 270

19. {6^3.6 ÷ (36)^- 4.2 }^1/4 = √?

19). Answer: d)
√? = {6^3.6 ÷ (6^2)^-4.2}^1/4
√? = {6^3.6 ÷ 6^-8.4)^1/4 = (6^(3.6 + 8.4)}^1/4
√? = {6^12}^1/4 = 6^3 = 216
or ? = (216)^2 = 46656

20. ³√12167 × √24025 = ?

20). Answer: c)
? = ³√12167 × √24025
? = 23 × 155 = 3565

Direction (21 – 25): What value should come in place of the question mark (?) in the following number series?
21). 24, 28 , 19 , 35 , 10 , ?

21). Answer: c)
The series is,
24 + 2^2 = 24 + 4 = 28;
28 – 3^2 = 28 - 9 = 19;
19 + 4^2 = 19 + 16 = 35;
35 – 5^2 = 35 - 25 = 10;
10 + 6^2 = 10 + 36 = 46

22. 14 , 6 , 4 , 4, 8 , ?

22). Answer: a)
The series is,
14 x 1 - 8 = 6;
6 x 2 - 8 = 4;
4 x 3 - 8 = 4;
4 x 4 - 8 = 8;
8 x 5 - 8 = 32

23. 14, 25, 47, 91, ?, 355

23). Answer: c)
The series is,
14 x 2 - 3 = 25;
25 x 2 - 3 = 47;
47 x 2 - 3 = 91;
91 x 2 - 3 = 179;

24. 11, 24, 44, 70, 101, ?

24). Answer: a)
The difference of difference of the series is, +7, +6, +5, +4, ….

25. 18, 8, 6, 8, 24, ?

25). Answer: d)
The series is,
18 x 0.5 - 1 = 8;
8 x 1- 2 = 6;
6 x 2 - 4 = 8;
8 x 4 - 8 = 24;
24 x 8 - 16 = 176

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) if x >y
b) if x≥y
c) if x< y
d) if x≤y
e) if x = y or no relation can be established between x and y.

26. I. 9x^2 - 41x+46=0
II. 12y^2 + 43y+ 38 = 0

26). Answer: a)
I 9x^2 - 41x + 46 = 0
or, 9x^2 - 18x - 23x + 46 = 0
or, 9x(x - 2) - 23(x - 2) = 0
or, (9x - 23) (x - 2) =0
x = 23/9, 2
II. 12y^2 + 43y + 38 =0
or, 12y^2 + 24y + 19y + 38 = 0
or, 12y(y + 2) + 19(y + 2) = 0
or, (12y + 19) (y+ 2) = 0
y = - 19/12, - 2
Therefore x > y

27.I. 6x^2 + 13x - 169 =0
II. y^2 + 8y - 65 = 0

27). Answer: e)
I.6x^2 + I3x - 169 = 0
or, 6x^2 - 26x + 39x - 169 =0
or, 2x(3x - 13) + 13(3x - 13) = 0
or, (2x + 13) (3x - 13) = 0
x = -13/2, 13/3
II. y^2 + 8y - 65 = 0
or, y^2 + 13y - 5y - 65 = 0
or, y(y + 13) - 5(y + 13) = 0
or, (y - 5) (y + 13) = 0.
y = 5, -13
Therefore relation can't be established between x and y

28. I. 3x + 5y = 4
II. 6x - 7y= 25

28). Answer: a)
I. 3x + 5y = 4
II. 6x – 7y = 25
Solving equation (I) and (II), we get
(I) × 2 ---- 6x + 10y = 8
(II) ----- 6x – 7y = 25
By subtracting (I) × 2 – (II),
17y = -17
y = -1 and x =3,
Therefore x > y

29. I. x^2 - 5x + 4 = 0
II. y^2 + 11y – 12 = 0

29). Answer: b)
I. x^2 - 5x + 4 = 0
or, x^2 – 4x – x + 4 = 0
or, x(x - 4) – 1(x -4) = 0
or, (x -1) (x - 4) = 0
x = 1, 4
Il.y^2 + 11y - 12= 0
or, y^2 + 12y – y -12 = 0
or, y(y + 12) – 1(y + 12) = 0 or, (y - 1) (y + 12) = 0
y = 1, -12
Therefore, x ≥ y

30.I. 8x^2 + 50x + 57 = 0
II. 6y^2 – y – 57 = 0

30). Answer: e)
I. 8x^2 + 50x + 57 = 0
or, 8x^2 + 12x + 38x +57=0
or, 4x(2x + 3) + 19(2x + 3) = 0
or, (4x + 19) (2x + 3) = 0
x = -19/4, -3/2
II.6y^2 – y - 57=0
or, 6y^2 + 18y - 19y - 57 = 0
or, 6y(y + 3) - 19(y + 3) = 0
or, (6y - 19) (y + 3) = 0
y= 19/6, -3
Therefore relation can't be established.

       

Do you feel that you are weak in English Section?

Here we are creating a pathway to win the English Section in upcoming IBPS Exams 2017

Let's block ads! (Why?)

- http://feedproxy.google.com/~r/blogspot/VyQLQ/~3/Oxy8G0LNcXk/crack-ibps-exam-2017-quantitative-aptitude-scoring-part-7.html