Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-17)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-17):

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Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). √? =(153 × 46) ÷ 18

1). Answer: c)
√? = 153 × 46 / 18 = 391
? = (391)^2 = 152881

2. (3834 ÷ 27) × (3920 ÷ 112) = ?

2). Answer: e)
? = 3834 / 27 × 3920 / 112 = 142 × 35 = 4970

3. 2.8% of 1220 + 7.4% of 780 = ?

3). Answer: b)
? = 2.8 × 1220 / 100 + 7.4 × 780 / 100
? = 34.16 + 57.72 = 91.88

4. 0.6 × 2.8 × 3.5 ÷ 0.0049 = ?

4). Answer: d)
? = 0.6 × 2.8 × 3.5 / 0.0049
? = 5.88 / 0.0049 = 1200

5). 30% of √15625 + 70% of ³√3375 = ?

5). Answer: a)
? = 30/100 × 125 + 70 /100 × 15
? = 37.5 + 10.5 = 48

6. (125 ÷ 0.5) ÷ 0.5 = 80% of?

6). Answer: e)
80 / 100 × ? = (125 ÷ 0.5) ÷ 0.5
80/100 × ? = 250 ÷ 0.5 = 500
? = 500 × 100 /80 = 625

7. √√194481 = ?

7). Answer: c)
√√194481 = √441 = 21

8. 8.5 / 0.25 + 4.4 / 0.2 = ?% of 80

8). Answer: c)
8.5 / 0.25 + 4.4 / 0.2 = 80 × ? / 100
or, 8.5 × 4 + 4.4 × 5 = 4 × ? / 5
? = (34 + 22) × 5 / 4 = 70

9. 3/5 of 4/7 of 9/11 of 21175 = 2^2 × 3^3 × ?

9). Answer: e)
? = 3 × 4 × 9 × 21175 / (5 × 7 × 11 × 2^2 × 3^3)
? = 21175 / (5 × 7 × 11)
? = 21175 / 385 = 55

10. [³√(√83521)]^(3/2) = ?

10). Answer: b)
? = [³√(√83521)]^(3/2)
? = [³√289]^(3/2)
? = [(289)^(1/3)]^(3/2)
? = [(289)^(1/2)
? = 17

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11. 68% of 1288 + 26% of 734 - 215 = ?

11). Answer: d)
? = 68 × 1288 / 100 + 26 × 734 / 100 – 215
? = 875.84 + 190.84 - 215
? ≈ 876 + 191 - 215 = 852 ≈ 850

12. (32.05)^2 - (18.9)^2 - (11.9)^2 = ?

12). Answer: b)
? = (32.05)^2 - (18.9)^2 - (11.9)^2
? ≈ 1027 - 357 - 144 = 526 ≈ 530

13. 6578 ÷ 67 × 15 = ? × 6

13). Answer: b)
? = 6578 × 15 / (67 × 6)
? = 245.44 ≈ 250

14. 679 / 45 ÷ 23 / 2130 × 126 / 169 = ?

14). Answer: e)
? ≈ 680 / 45 × 2130 / 23 × 126 / 170
? = 1043.35 ≈ 1040

15. √5687 × √1245 ÷ √689 = ? ÷ 13

15). Answer: c)
√5687 × √1245 ÷ √689 = ? ÷ 13
? = √5687 × √1245 × 13 / √689
? = 75.4 × 35.2 × 13 / 26.2
? = 1316.9 ≈ 1320

16. 339% of 705.62 + 136% of 1329 = ?

16). Answer: c)
? ≈ 340 × 705 / 100 + 136 × 1330 / 100
? = 2397 + 1808.8 = 4205.8 ≈ 4200

17. 29.78 × 14.12 + 40.65 × 11.79 = ?

17). Answer: b)
? ≈ 30 × 14 + 40 × 12 = 420 + 480 = 900

18. 570.80 × 9.09 × ? = 230855

18). Answer: a)
? ≈ 230855 / (570 × 9) = 45

19. 33.33 × 333.3 = ?

19). Answer: c)
? = 33.33 × 333.3
? = 3333 × 3333 / 1000
= 11108.889 ≈ 11110

20. 1.71% of 1606 + 0.705% of 1005 = ?

20). Answer: d)
? ≈ 1.7 × 1600/100 + 0.7 × 1000 /100
? = 27.2 + 7
? = 34.2 ≈ 34

Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.21. 6, 1338, 3074, 5298, ?

21). Answer: d)
The difference between numbers is, +1³+11³ , +2³+12³ ,+3³+13³ , +4³+14³

22. 2199, 868, 139, 14, ?

22). Answer: e)
The difference between numbers is - 11³ , - 9³ , - 5³ , +1³ , ….
(i.e. the difference between the numbers is 2 [11-9], 4 [9-5], 6 [1-(-5)] ,…..)

23. 3, 36, 153, 408, ?

23). Answer: a)
The series is,
(1³ +1³) + 1 = 3
(2³ +3³) + 1 = 36
(3³ +5³) + 1 = 153
(4³ +7³) + 1 = 408
(5³ +9³) + 1 = 855

24. 10, 36, 92, 190, 342, ?

24). Answer: b)
The series is,
(1³ +2³) + 1 = 10
(2³ +3³) + 1 = 36
(3³ +4³) + 1 = 92
(4³ +5³) + 1 = 190
(5³ +6³) + 1 = 342
(6³ +7³) + 1 = 560

25. 2, 65, 730, 4097,?

25). Answer: c)
The series is,
(1³ x 1³) + 1 = 2
(2³ x 2³) + 1 = 65
(3³ x 3³) + 1 = 730
(4³ x 4³) + 1 = 4097
(5³ x 5³) +1 = 15626

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) if x < y
b) if x ≤ y
c) if x = y
d) if x > y
e) if x ≥ y

26. I. 16x^2 + 20x + 6 = 0
II. 10y^2 + 38y + 24 = 0

26). Answer: d)
I. 16x^2 + 20x + 6 = 0
or, 16x^2 +12x+8x+6 = 0
or, 4x(4x+3)+y(4x+3)=0
or, (4x + 3)(4x + 2) = 0
x = -(3/4) or –(1/2)
II. 10y^2 +38y+24 = 0
or, 5y^2 +19y+12 = 0
or, 5y^2+15y+4y+12=0
or, (5y + 4) (y + 3) = o
y = -(4/5) or -3
Hence, x> y

27. I. 18x^2 + 18x + 4 = 0
II. 12y^2 + 29y + 14 = 0

27). Answer: e)
I. 18x^2 +18x + 4 = 0
or, 9x^2 +9x+2 =0
or, 9x^2+6x+3x+2 =0
or, 3x (3x +2) + 1(3x + 2) = 0
x = -(1/3) or –(2/3)
II. 12y^2 +29y+14=0
or, 12y^2 +21y+8y+14 = 0
or, 3y(4y 7) + 2(4y + 7) =0
or, (3y + 2) (4y + 7) = 0
y= -(2/3) or –(7/4)
Hence, x ≥ y

28. I. 8x^2 + 6x = 5
II. 12y^2 – 22y + 8 = 0

28). Answer: b)
I. 8x^2+6x-5=0
or,2x(4x+5)-1( 4x+5) = 0
or, (2x-1)(4x+5) = 0
x = (1/2) or –(5/4)
II.12y^2 -22y+8=0
or, 12y^2 – 16y – 6y + 8 = 0
or, 4y(3y - 4) – 2 (3y -4) = 0
or, (4y - 2) (3y- 4) = 0
y = (1/2) or (4/3)
Hence, x ≤ y

29. I. 17x^2 + 48x = 9
II. 13y^2 = 32y – 12

29). Answer: a)
I. 17x^2 + 48x – 9 = 0
or, 17x^2 + 51x – 3x – 9 = 0
or, (17x -3)(x+3) = 0
x = (3/17) or -3
II. 13y^2 – 32y + 12 = 0
Or, 13y^2 – 26y – 6y + 12 = 0
Or, (13y - 6)(y -2) = 0
Y = (6/13) or 2
Hence x < y.

30. I. 4x + 7y = 209
II. 12x - 14y = -38

30). Answer: c)
I. 4x + 7y = 209
Or, 8x+14y=418 …(i)
II. 12x - 14y = -38
From (i) and (ii), we get
20x = 380
x = 19
putting value of x in equation (i),
we get y = 19
x = y