Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-15):
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Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). 24.5% of 48 + 8.4% of 125 = ?% of 139.125
1). Answer: c)
? × 139.125 / 100 = 24.5 × 48 / 100 + 8.4 × 125 / 100
? × 139.125 / 100 = 11.76 + 10.5
? = 22.26 × 100 / 139.125 = 16
2. (24.84 ÷ ?) / (0.2 × 0.03) = 300? × 139.125 / 100 = 24.5 × 48 / 100 + 8.4 × 125 / 100
? × 139.125 / 100 = 11.76 + 10.5
? = 22.26 × 100 / 139.125 = 16
2). Answer: b)
24.84 / ? = 300 × 0.2 × 0.03 = 1.8
? = 24.84 / 1.8 = 13.8
3. 8/13 of 7/3 of 12.5% of 13728 = 320% of ?24.84 / ? = 300 × 0.2 × 0.03 = 1.8
? = 24.84 / 1.8 = 13.8
3). Answer: d)
320 × ? / 100 = 8 × 7 × 12.5 × 13728 / (13 × 3 × 100) = 2464
? = 2464 × 100 / 320 = 770
320 × ? / 100 = 8 × 7 × 12.5 × 13728 / (13 × 3 × 100) = 2464
? = 2464 × 100 / 320 = 770
4. (1296)^3.8 × (216)^(-4) ÷ 1 / 7776 = (36)^?
4). Answer: b)
(6^4)^3.8 × (6^3)^(–4) ÷ 1 / (6)^5 = (36)^?
(6)^15.2 × (6)^(-12) (6)^(–5) = (36)^?
(36)^? = (6)^(15.2 - 12 + 5) = (6)^8.2 = (36)^4.1
? = 4.1
(6^4)^3.8 × (6^3)^(–4) ÷ 1 / (6)^5 = (36)^?
(6)^15.2 × (6)^(-12) (6)^(–5) = (36)^?
(36)^? = (6)^(15.2 - 12 + 5) = (6)^8.2 = (36)^4.1
? = 4.1
5). √6084 ÷ ³√2197 = ³√?
5). Answer: c)
³√? = 78 ÷ 13 = 6
? = (6)^3 = 216
³√? = 78 ÷ 13 = 6
? = (6)^3 = 216
6. (1089)^2.8 ÷ (33)^(-3.4) × 1/35937 = (1089)^?
6). Answer: c)
(33^2)^2.8 ÷ (33)^(-3.4) × 1/ (33)^3 = 1089^?
or, (33)^5.6 ÷ (33)^(-3.4) × (33)^(-3) = (1089)^?
or, (33)^(5.6 + 3.4 – 3) = (1089)^?
or, (33)^6 = (1089)^?
or, (1089)^3 = 1089^?
? = 3
(33^2)^2.8 ÷ (33)^(-3.4) × 1/ (33)^3 = 1089^?
or, (33)^5.6 ÷ (33)^(-3.4) × (33)^(-3) = (1089)^?
or, (33)^(5.6 + 3.4 – 3) = (1089)^?
or, (33)^6 = (1089)^?
or, (1089)^3 = 1089^?
? = 3
7. 1.4641 ÷ 0.0011 = ?
7). Answer: d)
? = 1.4641 / 0.0011
? = 14641 / 11 = 1331
? = 1.4641 / 0.0011
? = 14641 / 11 = 1331
8. 3.6% of 180 + 2.4% of 555 = ?% of 49.5
8). Answer: a)
? × 49.5 / 100 = 3.6 × 180 / 100 + 2.4 × 555 / 100
? × 49.5 / 100 = 6.48 + 13.32 = 19.8
? = 19.8 × 100 / 49.5 = 40
9. 7/9 of 4/3 of 78% of 4950 = ?? × 49.5 / 100 = 3.6 × 180 / 100 + 2.4 × 555 / 100
? × 49.5 / 100 = 6.48 + 13.32 = 19.8
? = 19.8 × 100 / 49.5 = 40
9). Answer: a)
? = 7 × 4 × 78 × 4950 /(9 × 3 × 100)
? = 4004
? = 7 × 4 × 78 × 4950 /(9 × 3 × 100)
? = 4004
10. 7.25 × 244 – 2.75 × 148 = 1.2 × ?
10). Answer: b)
? = (7.25 × 244 – 2.75 × 148) / 1.2
? = (1769 – 407) / 1.2
? = 1362 / 1.2 = 1135
? = (7.25 × 244 – 2.75 × 148) / 1.2
? = (1769 – 407) / 1.2
? = 1362 / 1.2 = 1135
Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11.16.5% of 1399.921 + 114.78% of 1211 = ?
11). Answer: e)
? ≈ 16.5 × 1400 / 100 + 115 × 1200 / 100
? = 231 + 1380
? = 1611 ≈ 1610
? ≈ 16.5 × 1400 / 100 + 115 × 1200 / 100
? = 231 + 1380
? = 1611 ≈ 1610
12. √1220 × 16.06 + √4897 = ?
12). Answer: c)
√1220 ≈ 35
√4897 ≈ 70
? ≈ 35 × 16 + 70 = 560 + 70
? = 630
13. 18.08 × 11.898 + 22.922 × 14.94 = ?√1220 ≈ 35
√4897 ≈ 70
? ≈ 35 × 16 + 70 = 560 + 70
? = 630
13). Answer: b)
? ≈ 18 × 12 + 23 × 15 = 216 + 345
? = 561 ≈ 560
14. (2284.85 ÷ 4.985 +17.126) ÷ 6.06 = ?? ≈ 18 × 12 + 23 × 15 = 216 + 345
? = 561 ≈ 560
14). Answer: e)
? ≈ (2285 ÷ 5 + I7) ÷ 6
? = (457 + 17) ÷ 6 = 79
15. (445905 ÷ 981) + (1618 ÷ 64.8) = ?? ≈ (2285 ÷ 5 + I7) ÷ 6
? = (457 + 17) ÷ 6 = 79
15). Answer: d)
? ≈ (445900 ÷ 980) + (1625 ÷ 65)
? = 455 + 25 = 480
16. {(5.75)^2 × 4.996} ÷ 11.04 = ?? ≈ (445900 ÷ 980) + (1625 ÷ 65)
? = 455 + 25 = 480
16). Answer: b)
? ≈ 33 × 5 / 11 = 15
17. 85% of 489.96 + 73% of 849.98 = ?? ≈ 33 × 5 / 11 = 15
17). Answer: c)
? ≈ 85 × 490 / 100 + 73 × 850 / 100
? = 416.5 + 620.5
? = 1037 ≈ 1035
18. 24.03 × 18.96 - 7.25 × 43.98 + 12.98 = ?? ≈ 85 × 490 / 100 + 73 × 850 / 100
? = 416.5 + 620.5
? = 1037 ≈ 1035
18). Answer: a)
? ≈ 24 × 19 - 7.25 × 44 + 13
? = 456 - 319 + 13 = 150
? ≈ 24 × 19 - 7.25 × 44 + 13
? = 456 - 319 + 13 = 150
19. (644.96 ÷ 14.95 +1.98) × 15.966 = ?
19). Answer: b)
? ≈ {(645 ÷ 15) + 2} × 16 = 720
? ≈ {(645 ÷ 15) + 2} × 16 = 720
20.22.22 × 33.3 × 0.44 = ?
20). Answer: d)
? = 22.22 × 33.3 × 0.44 = 325.567
? ≈ 325
Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.21. 1953.125, 781.25, 312.5, 125, ?, 20? = 22.22 × 33.3 × 0.44 = 325.567
? ≈ 325
21). Answer: c)
The series is,
1953.125/2.5=781.25
781.25/2.5=312.5
312.5/2.5=125
125/2.5=50
50/2.5=20
The series is,
1953.125/2.5=781.25
781.25/2.5=312.5
312.5/2.5=125
125/2.5=50
50/2.5=20
22. 81, 87, 162, 504, 1992, 9990, ?
22). Answer: d)
The difference between numbers is x 1+6 , x 2-12, x 3+18 ,x 4-24 ,x 5+30 , x 6-36
The difference between numbers is x 1+6 , x 2-12, x 3+18 ,x 4-24 ,x 5+30 , x 6-36
23. 49, 72, 118, ?, 394, 762, 1498
23). Answer: c)
The difference between numbers is +23 , +46 , +92 , +184 , +368 ,+736
24. 142, 143, 156, 193, 272, 417, ?The difference between numbers is +23 , +46 , +92 , +184 , +368 ,+736
24). Answer: b)
The difference between numbers is +1³+0 , +2³+5 ,+3³+10 , +4³+15 , +5³+20 ,+6³+25
The difference between numbers is +1³+0 , +2³+5 ,+3³+10 , +4³+15 , +5³+20 ,+6³+25
25. 118, 122, 140, 188, 288, 468, ?
25). Answer: c)
The difference between numbers is +2³-2², +3³-3², +4³-4², +5³-5², +6³-6², +7³-7²
The difference between numbers is +2³-2², +3³-3², +4³-4², +5³-5², +6³-6², +7³-7²
Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) If x < y
b) If x ≥ y
c) If x > y
d) If x ≤ y
e) Relationship between x and y cannot be established
II. 7y^2 – 61y – 18 = 0
26). Answer: e)
I. 9x^2 - 51x - 18 = 0
x = – (54/9) , 3/9
x = 6, -(1/3)
II. 7y^2 – 61y – 18 = 0
y = - (63/7), (2/7)
y = 9, - (2/7)
Hence relation can’t be established.
I. 9x^2 - 51x - 18 = 0
x = – (54/9) , 3/9
x = 6, -(1/3)
II. 7y^2 – 61y – 18 = 0
y = - (63/7), (2/7)
y = 9, - (2/7)
Hence relation can’t be established.
27.I. 4x^2 - 3x - 27 = 0
II. 6y^2 – 83y + 27 = 0
27). Answer: e)
I. 4x^2 - 3x - 27 = 0
x = -(12/4), (9/4)
x = 3, -(9/4)
II. 6y^2 – 83y + 27 = 0
y = (81/6) , (2/6)
y = (27/2), (1/3)
Hence no relation can be established.
28. I. 21x - 4y = 140I. 4x^2 - 3x - 27 = 0
x = -(12/4), (9/4)
x = 3, -(9/4)
II. 6y^2 – 83y + 27 = 0
y = (81/6) , (2/6)
y = (27/2), (1/3)
Hence no relation can be established.
II. 9x – 8y = 148
28). Answer: c)
21x – 4y = 140 …(i)
9x – 8y = 148 …(ii)
Solving eqn (i) and (ii) we get
[ 42x – 8y = 280 ] – [ 9x – 8y = 148]
33x = 132
x = 4
Putting the value of x in equation (i), we get
84 – 4y = 140
Or, -4y = 56
Y = -(56/4) = -14
Hence x > y
29. I. 3^(x-y) = 24321x – 4y = 140 …(i)
9x – 8y = 148 …(ii)
Solving eqn (i) and (ii) we get
[ 42x – 8y = 280 ] – [ 9x – 8y = 148]
33x = 132
x = 4
Putting the value of x in equation (i), we get
84 – 4y = 140
Or, -4y = 56
Y = -(56/4) = -14
Hence x > y
II. 3^(x+y) = 27
29). Answer: c)
I. 3^(x-y) = 243
3^(x-y) = 3^5
x – y = 5 …(i)
II. 3^(x+y) = 27
3^(x+y) = 3^3
x + y = 3 …(ii)
By adding (i) and (ii), we get
(x – y = 5) + (x + y = 3)
2x = 8
x = 8/2 = 4
Putting the value of x in equation (i), we get
4 – y = 5
or, -y = 5 – 4 = 1
or , y = -1
Hence x > y
30. I. 8x^2+ 27x+ 22 = 0I. 3^(x-y) = 243
3^(x-y) = 3^5
x – y = 5 …(i)
II. 3^(x+y) = 27
3^(x+y) = 3^3
x + y = 3 …(ii)
By adding (i) and (ii), we get
(x – y = 5) + (x + y = 3)
2x = 8
x = 8/2 = 4
Putting the value of x in equation (i), we get
4 – y = 5
or, -y = 5 – 4 = 1
or , y = -1
Hence x > y
II. 4y^2 – 25y -56 = 0
30). Answer: e)
I. 8x^2+ 27x+ 22 = 0
x = (16/8), (11/8)
x = -2, -(11/8)
II. 4y^2 – 25y -56 = 0
y = - (32/4), (7/4)
y = 8, -(7/4)
Hence no relation can be established.
I. 8x^2+ 27x+ 22 = 0
x = (16/8), (11/8)
x = -2, -(11/8)
II. 4y^2 – 25y -56 = 0
y = - (32/4), (7/4)
y = 8, -(7/4)
Hence no relation can be established.
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