IPPB Scale I & IBPS SO 2017 - Practice Quantitative Aptitude Questions (Application Problems)

January 20, 2017    

IPPB Scale I & IBPS SO 2017 - Practice Quantitative Aptitude Questions (Number Series & Quadratic Equation) Answers Updated
IPPB Scale I & IBPS SO 2017 - Practice Quantitative Aptitude Questions (Application Problems)  Set-89:
Dear Readers, Important Practice Aptitude Questions for IPPB & IBPS SO Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the examination can use this.
1).  A cycle is sold at a profit of 15%. If both the cost price and selling price is decreased by  Rs. 200 the profit would be 5% more what is the original cost price of cycle ?
a)    Rs.  1200
b)    Rs. 1000
c)    Rs. 800
d)    Rs. 600
e)    None of these
2). A person lends  Rs. 4200  to 'A' for 3 years and Rs.  6500 to 'B' for 7 years. If the person gets  Rs.  8134 as interest then what is the rate of interest per annum ?
a)    6%
b)    8%
c)    10%
d)    12%
e)    14%
3). A sum amounts to  Rs. 98010 in 2 years and to  Rs.  107811 in 3 years compounded annually. What is the sum ?
a)    Rs. 81000
b)    Rs.  84000
c)    Rs.  87000
d)    Rs.  90000
e)    Rs.  94000
4). How many different words can be formed with the letters of the word ''BREAKING". So that the words begin with 'B' and end with 'G' ?
a)    120
b)    720
c)    5040
d)    2520
e)    1440
5). A bag contains 9 white and 7 black balls. Three balls are drawn at random. Find the probability that all the three balls are black ?
a)    1/8
b)    1/12
c)    1/16
d)    1/21
e)    None of these
6). 'A' can do a piece of work in 72 days and 'B' can do the same work in 45 days. They work together for 8 days and then 'A' left the job. In how many days 'B' will finish the remaining work ?
a)    24 days
b)    28 days
c)    30 days
d)    32 days
e)    36 days
7). A man purchased two cycles for  Rs.  10000, He sold the first cycle at 18% profit and second cycle at 10% loss. In the whole process he gained Rs. 36. What is the cost price of two cycles ?
a)    Rs. 3900, Rs. 6100
b)    Rs. 3800, Rs. 6200
c)    Rs. 3700, Rs. 6300
d)    Rs. 3600, Rs. 6400
e)    None of these
8). Population of a city is 8 lakh. If the annual birth rate and death rates of the city are 6.3% and 1. 8% respectively then what will be the population of city after two years ?
a)    873620
b)    864860
c)    858640
d)    886410
e)    897580
9). Two men and 5 women earn Rs.  4250 in 17 days. If 7 men and 8 women earn Rs.  6281 in 11 days then in how many days 6 men and 9 women will earn Rs. 8928 ?
a)    12 days
b)    14 days
c)    16 days
d)    18 days
e)    None of these
10). A train covered a certain distance at uniform speed. If the train would have been 12 km/hr. faster,  it would have taken 15 hrs. less and if the train were slower by 12 km/hr. it would have taken 25 hours more. What is the length of the journey?
a)    2400 km.
b)    2700 km.
c)    3000 km.
d)    3200 km.
e)    3600 km.
1). C)  Let the original cost price is ‘x’,  so selling price is
115x/100 = 23x/20
Now CP = x – 200, S.P. = (23x/20) - 200
Profit =  (23x/20) – 200 – (x - 200) = (23x/20) – x = 3x/20
% profit = (3x/20) × [1/ (x - 200)] × 100 = 20
[3x / (x-200)] = 4
3 x = 4 x – 800
2). E)  Let the rate of interest is r% p.a.
[(4200 × r × 3) /100] + [(6500 × r × 7) / 100] = 8134
126 r + 455 r = 8134
r = 8134/581 = 14% p.a
3). A)Let the principal is ‘P’ and rate of interest is ‘r’
P [1+ (r/100)]3 = 107811         ………….(I)
P [1+ (r/100)]2 = 98010           ………….(II)
Dividing equn (I) by (II)
1 + (r/100) = 107811/98010
r/100 = 9801/98010
r = 980100/98010 = 10% p.a.
P = [1+ (10/100)]2 = 98010
P = (98010 × 100) / 121 = 81000
4). B)  B G
Now 6 letters are left for six different place
Req. No. of wages = 6p6 = 6! = 720
5). C)n (s) =  16C3 = 560
n (E) = Number of ways of selecting 3 balls out of 7 = 7C3  = 7!/3! 4! = 35
P (E) = 35/560 = 1/16
6). D)(A + B)’s 1 days work = (1/72) + (1/45)
= (5+8)/360 = 13/360
(A + B)’s 8 days work = (13 × 8) / 360 = 13/45
Remaining work = 1 – (13/45) = 32/45
B finish 1 work in 45 days
B will finish (32/45) work in 45×(32/45) = 32 days.
7). C)Let the cost price of first and second cycle are ‘x’ & ‘y’ respectively
x + y = 10000   ....................... (I)
x × (18/100)  – y × (10/100) = 36
9 x – 5 y = 1800  .......................... (II)
Equn (I) × 5 + equan (II)
5 x + 5 y = 50000
9 x – 5 y = 1800
___________
14           =  51800
8). A)  Net rate of increase in population = 6.3 – 1.8 = 4.5%
Req. population = 800000 × 1.045×1.045 = 8736.20
9). C)  Let daily earning of a man is ‘x’ and woman is ‘y’
2 x + 5 y =  (4250/17)  = 250    ...................... (I)
7 x + 8 y =  (6281/11) = 571 ...................... (II)
Solving eqn. (I) & (II) x = 45, y = 32
6 x + 9 y = 270 + 288 = 558
No. of days = 8928/558 = 16
10). E)  Let the speed is ‘x’ kmh -1  and actual time = ‘y’ hrs.
distance = xy
x y = (x + 12) (y – 15)
x y = x y – 15 x + 12 y – 180
4 y – 5 x = 60   ............................ (I)
again x y = (x – 12) (y + 25)
xy = xy + 25 x – 12 y – 300
12 y – 25 x = – 300  ........................... (II)
Solving equn. (I) and (II) x = 48  and y = 75

distance = xy = 48 × 75 = 3600 km.
More Practice Aptitude Questions for IBPS SO/IPPB 2016 -Click Here

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IPPB Scale I & IBPS SO 2017 - Practice Quantitative Aptitude Questions (Application Problems) 4.5 5 Yateendra sahu January 20, 2017 IPPB Scale I & IBPS SO 2017 - Practice Quantitative Aptitude Questions (Application Problems)  Set-89 : Dear Readers, Import...


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