Study the following pie-charts carefully and answer the following questions
The following pie-chart show the number of students appearing GATE Examination From different states .
1. Number of students appearing from B state in 2016 was , What per cent of that from F state F in 2015 ?
2. The total number of students appearing from B & C together in 2015 is approximately equal to that from which of the following pairs of states in 2016 ?
3.If there were 30000 students appearing in the examination from Hyderabad in 2016,and 35000 students appearing from Chennai in 2016, find the percentage of students students not from the Hyderabad and Chennai in 2016.
4.What is the per cent students appearing from state A,C and F in 2015 , same states in 2016 ?
5. If number of students appearing examination in 2014 is 20% more than students appearing in 2015 , Find the number of students appearing examination from state B in 2014 ?
4.Data Insufficient
5.None of the above
Answers and Solutions :
No.of students appearing from B state in 2016 = 20*240000/100 = 48000
No.of students appearing from F state in 2015 = 20*250000/100 = 50000
Percentage = 48000*100/50000 = 96%
Students appearing from B and C in 2015 = (18+12)*250000/100 = 75000
Go through options verification check one by one
You will find option C is approximately equal to 75000
Students from Hyderabad and Chennai in 2016= 30000+35000=650000
Total number of students in 2016 = 240000
Students not from Chennai and Hyderabad = 240000-65000= 175000
Percentage = 175000*100/240000 = 72.91
Students appearing from A,C,and F in 2016 = (13+18+23)*240000/100= 129600
Students appearing from A,C and F in 2015 = (19+12+20)*250000/100 = 127500
Percentage = 127500/129600 * 100 = 98.37
Students appearing examination is 20% more than the students appearing examination in 2015 = 300000
But F state details in 2014 not given
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