SBI PO/IBPS RRB 2016-Aptitude Questions (Data Interpretation)

July 6, 2016    

SBI PO/IBPS RRB 2016-Aptitude Questions (Data Interpretation) Set-7:
Dear Readers, Important Practice Aptitude Questions for Upcoming SBI PO/IBPS RRB Exams was given here with Solutions. Aspirants those who are preparing for the examination can use this.
Directions (Q. 1-5): Following graph shows the production at different plants (A, B, C, D) of Torrent Ltd for four years. Ordinate is production figures in ’000 MTs.
(i) Capacity utilization = Production × 100 / Capacity
(ii) Production is undertaken uniformly during the year.
(iii) Capacity of four plants (in ’000 MTs) in 1996 is as follows: A = 222, B = 160, C = 180, D = 190
(iv) Raw material availability at the plants in 1996 is to produce following quantities (’000 MTs):
A = 123, B = 148, C = 185, D = 198
1).Which plant has the highest capacity utilization in 1996?
e)   None of these
2).Plant D operated only for 8 months in 1993. What would have been the capacity utilization in 1993 if the plant had run for the entire year? [Total capacity of D in 1993 = 190000 MTs]
a)   60%
b)   50.67%
c)   40%
d)   70%
e)   65%
3).If plant C operated at 60% capacity utilization in 1993 and 80% in 1994, what was the capacity addition during that period?
e)   Nil
4).What is the maximum possible production, taking into account raw material availability constraint in 1996?
a)   A-222, B-160, C-180, D-190
b)   A-123, B-148, C-185, D-198
c)   A-123, B-148, C-180, D-190
d)   A-123, B-148, C-180, D-198
e)   A-125, B-150, C-180, D-198
5).In 1996 bonus is to be given to employees of the plant which produces at least 25% of total company production and which achieves capacity utilization of more than that achieved by the whole company. Which plants received the bonus in 1996?
a)   C & D
b)   B, C & D
e)   None of these
Directions (Q. 6-9): Refer to the tables below:
The following tables give information related to fertilisers (nitrogen and phosphate).
(lac tonnes)
Cap. Util.(%)
Phosphates
(lac tonnes)
Cap. Util. (%)
1996-97 (Est.)
Fertilizer consumption (lac tonnes)
6).By what percentage was consumption of fertilizers greater than the production of fertilizers in the year 1992-93?
e)   None of these
7).What was the increase in total production capacity of phosphate fertilizers between 1991-97?
a)   1.5 lac tonnes
b)   2 lac tonnes
c)   2.5 lac tonnes
d)   1 lac tonnes
e)   None of these
8).Total fertilizer production in 1995-96 was what percentage of total fertilizer consumption (approximately)?
c)   77.5
d)   78.5
e)   None of these
9).Between 1990-96, production of nitrogen fertilizer was what percentage of total consumption of fertilizers?
Answers:                    
1). c) 2). a) 3). b) 4). c) 5). e) 6). c) 7). b) 8). d) 9). e) 
1).Capacity utilization for the plants is
A = 75 × 100/222 = 33.8%
B = 135 × 100/160 = 85%
C = 145 × 100/180 = 80%
D = 170 × 100/190 = 90%
Answer: c)
2).Plant D produced 75 (’000 MTs) in 1993 in 8 months. If the plant had been operative throughout the year it would have produced 12 × 75/8 = 112.5 (’000 MTs)
The capacity utilization = 112.5 × 100 / 190 = 60%
Answer: a)
% Capacity Utiz.
Total capacity
85×100/60=140
124×100/80=156.25
Answer: b)
4).Using both the constraints: Capacity of four plants: A = 222, B = 160, C = 180, D = 190; and Raw material availability at the plants in 1996 is to produce following quantities (’000MTs): A = 123, B = 148, C = 185, D = 198. Hence minimum value between Capacity and Raw material availability is the maximum production possible. Hence answer option is (3).
Answer: c)
Capacity considering Constraints
Actual production
% Utilization
25% of total
Only B & D satisfy the given condition.
Answer: e)
6).For 1992-93:
Production = 74.30 + 23.06 = 97.36
Consumption = 121.55
 Percentage lead of consumption over production = 121.55 - 97.36 / 97.36 × 100 = 25%
Answer: c)
7).Production capacity in 1991 = Production / Capacity utilisation =20.51 / 0.7450 = 28
Production capacity in 1997 = 26.8 / 0.91 = 30
Hence increase in capacity = 30 – 28 = 2.
Answer: b)
8).Total fertilizers production in 1995-96 = 87.77 + 25.58 = 113.35
Total consumption in 1995-96 = 144.36
Required percentage = 113.35 / 144.30 × 100 = 78.5%
Answer: d)
9).Production of nitrogen fertilizers from 1990-96
= 69.93 + 73.01 + 74.3 + 72.31 + 79.45 + 87.77 = 456.77
Consumption of fertilizers from 1990-96
= 125.46 + 127.28 + 121.55 + 123.66 + 135.64 + 144.3 = 777.89
Required percentage = Production / Consumption × 100 = 456.77 / 777.84 × 100 = 60%
Answer: e)

 

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SBI PO/IBPS RRB 2016-Aptitude Questions (Data Interpretation) 4.5 5 Yateendra sahu July 6, 2016 SBI PO/IBPS RRB 2016-Aptitude Questions (Data Interpretation) Set-7 : Dear Readers, Important Practice Aptitude Questions for Upcoming SB...


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