Quant Quiz for SSC CGL 2016

For the first time SSC examination will be held in Computer Based pattern and managing time will be one of the important factor while solving the questions. So in order to make students familiar with such a situations we are providing questions in a time based manner , which will help students to manage the time properly.

1.The difference between the compound interest and simple interest on a certain sum of money at 10% per annum for 3 years is Rs. 500. The sum is?

Rs. 45000

Rs. 50000

Rs. 55000

None of the above

Solution:

(d) D = pr^2(300+r)/(100)^3
500 = P(10)^2(300+10)/(100)^3
      p = 16129

2. A sum of Rs 731 is distributed among A, B and C, such that A receives 25% more than B and B receives 25% less than C. What is C’s share in the amount?

Rs 172

Rs 200

Rs 262

Rs 272

Solution:

(d) Let C's share be Rs x.
Then, B gets =0.75 x.
A gets = 1.25×0.75x
x+0.75x+0.9375x=731
2.6875x=731
x=731⁄2.6875 =272

3.A shopkeeper mixed two varieties of rice at Rs. 20/kg and Rs. 30/kg in the ratio 2 : 3 and sell the mixture at 10% profit. Find the price per kg at which he sold the mixture?

Rs.26

Rs.28.8

Rs.28

Rs.28.6

Solution:

. (d) CP of mixture = (20*2+30*3)/5 =26
SP of the mixture = 1.1×26=28.6

4. A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:

15 days

10 days

12 days

14 days

Solution:

(b) Total Unit of work=LCM(Time taken by A,Time taken by B,Time taken by C)=LCM(24,9,12)=72 A's 1 day work=72/24=3unit
B's 1 day work=72/9=8 unit
C's 1 day work=72/12=6unit
work done by(B+C) in 1 day=(8+6)unit=14 unit
work done by(B+C) in 3 day=14x3=42 unit
Remaining work=(Total work - work done by B+C in 3 days)= (72-42)=30unit
Remaining work done by A in=Remaining work/A's 1 day work= 30/3=10 days.(Answer)

5. A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?

40 days

30 days

60 days

50 days

Solution:

(c) Let A's 1 day's work = x and B's 1 day's work = y.
Both A's and B's 1 day work=1/30
i.e (A's 1 day + B's 1 day)=1/30
i.e x + y = 1/30........eq1
now, A having worked for 16 days,
B finishes the remaining work alone in 44 days
i.e work done by A in 16 days = 16x
Remaining work done B= 1 - 16x but
Remaining work is done by B in 44days
i.e 44y  i.e. 44y=1-16x i.e 16x+44y=1........eq2
solving eq1 & eq2,
we get,x = 1/60 and y = 1/60
B's 1 day's work = 1/60.
Hence, B alone shall finish the whole work in 60 days.

6.A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:

6 days

12 days

8 days

7 days

Solution:

(a) A takes twice much time then B i.e. 2A=B...(i)
A takes thrice much time then C
i.e. 3A=C...(ii)
It is given that working together they can finish in 2 days so A+B+C=1/2
Now put B=2A AND C=3A in this equ... A+B+C=1/2
A+2A+3A=1/2
6A=1/2 A=1/2*6=1/12
Now put the value of A in equ.(i) .
i.e B=2A =2*1/12 =1/6
Therefore B takes 6 days to complete the work.

7. Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is?

8 days

15 days

16 days

13 days

Solution:

(c) Tanya is 25% more efficient than Sakshi.
Tanya is 125. Sakshi is 100.
Ratio of efficiency is 5:4.
So, ratio of time will be 4:5.
Given, Sakshi can do work in 20 days means 5*4=20.
In the same way for Tanya 4*4=16.

8. A train travelling at the speed of 90 km/hr follows a goods train after 6 hours from a station and overtakes it in 4 hours. What is the speed of the train?

30 km/hr

60 km/hr

36 km/hr

42 km/hr

Solution:

.(c) Goods train travel for 6 + 4 = 10 hrs.
other train for 4 hrs, travel distance is same = v1t1 = v2t2
=> v1/v2 = t2/t1 = 10/4 = 5/2
Since v1 = 90 k/h
=> V2 = 36 km/hr

9. A man takes 5hr 45min in walking to certain place and riding back. He would have gained 2hrs by riding both ways. The time he would take to walk both ways is?

8 hr 45 min

6 hr 28 min

7 hr 45 min

10 hr 45 min

Solution:

(c): Let x be the speed of walked
Let y be the speed of ride
Let D be the distance
Then D/x + D/y = 23/4 hr -------1
D/y + D/y = 23/4 – 2 hr D/y = 15/8 --------2
Substitute 2 in 1
D/x + 15/8 = 23/4 = D/x = 23/4 -15/8 =46-15/8 =31/8
Time taken for walk one way is 31/8 hr
Time taken to walk to and fro is 2 x 31/8 = 31/4 hr =7 hr 45 min

10. In a 729 litres mixture of milk and water, the ratio of milk to water is 7 : 2. To get a new mixture containing milk and water in the ratio 7 : 3, the amount of water to be added is?

81 litres

71 litres

56 litres

50 litres

Solution:

(a): Quantity of milk in 729 litres of mixture = (7 x 729) / 9 = 567 litres
Quantity of water = (729-567) litres = 162 litre.
Let x litres of water is mixed to get the required ratio of 7 : 3 = 567 / (162 + x)= 7 / 3 = 7x + 1134 = 1701 = 7x = 1701 – 1134 = 567 = x = 567 / 7 = 81 litres