Quadratic Equations - How to Solve Quickly

May 18, 2016    

quant
Today I am sharing quick technique to solve Quadratic Equations quickly. I will also share practice questions on same to;



A polynomial of degree 2 is called Quadratic Equation.
For example:
  • 2x2-5x+1=0
  • x2-5=0
A general form of quadratic equation is ax2+bx+c=0
Where a, b, c all belong to real numbers
Now if you compare the equations I and II with the general form.
  • a=2, b=-5 and c=1
  • a=1, b=0 and c=-5

Zeros or the solutions of Quadratic Equation

The real value of x for which the value of the P(x) = ax2+bx+c becomes zero is known as the root of 
the quadratic equation  ax2+bx+c =0.
  • Determine whether 3and 4 are the zeros of the polynomial P(x) =x2-7x+12
            Solution:
                         P (3)   = 32-7.3+12
                                    = 9-21+12
                                    = -12+12
                                    = 0
                       P (4) = 42-7.4+12
                                = 16-28+12
                                = -12+12
                                = 0
Therefore 3 and 4 are the zeros or the solutions or the roots of the polynomial P(x)=x2-7x+12

Kinds of a Quadratic Equation

There are two types of quadratic equations 
  • Pure quadratic equation
  • Adfected quadratic equation

Pure quadratic equation:

An equation of the form ax2+c=0 , a ≠0 is known as the pure quadratic equation .It means that the 
quadratic equation ax2+bx+c =0, having no term containing single power of x, known as pure 
quadratic equation . Clearly in a quadratic equation a ≠0 and b=0.
For example
  • x2-4=0
  • 3/8x2=5

Adfected quadratic equation:

A quadratic equation of the form ax2+bx+c =0, a ≠0 is known adfected quadratic equation or general 
quadratic equation. An adfected quadratic equation has also a term containing single power of x .In 
adfected quadratic equation
ax2+bx+c =0, a ≠0, b ≠0
For example:
  • x2-5x+11=0
  • 0.3x2+17x-2.3=0

Solving a pure quadratic equation

There are two methods for solving a pure quadratic equation of the form ax2+c=0:
  • By square root 
  • By factorization

                To solve a quadratic equation by square root

ax2+c=0 is a pure quadratic equation. To solve it , bring the constant term the RHS (right hand side) 
and divide both side by a, coefficient of x2 and take the square root.
For example :

To solve a pure quadratic equation by factorization

Bring the equation ax2+c=0 in the form p2-q2 =0. Use the p2-q2=(p+q)(p-q). Equate each factor to 
zero  and find the values of x in each case, the two values of x so obtained are roots of the equation 
For example :
(4x)2-(5)2 = 0
(4x+5) (4x-5) =0

Solving an Adfected Quadratic Equation

There are two methods for solving an adfected quadratic equation ax2 + bx+c=0, a ≠0, b ≠0.
(i)                  By factorization                                         (ii)           By completing square

To solve the quadratic equation ax2 + bx+c=0 by the method factorization

In this method the middle term (i.e term containing single power of x) is broken into two suitable 
parts so that the factors are formed.
Example:             solve.    8x2 + 7x – 15 = 0
                
Solution:                                 8x2 +7x- 15 =0
                Or                           8x2-8x + 15x-15=0
                Or                           8x (x-1) +15(x-1) =0
                Or                           (8x +15)(x-1)=0
Therefore                                      8x+15=0
                                                      8x=-15
                                x= -15/8
And                        x-1 =0
                                x-1
Hence   -15/8 and 1 are the required roots.

To solve ax2 + bx+ c=0 by completion of  square

The famous Indian mathematician ShreedharAcharya had invented a formula for solving the 
quadratic equation ax2 +bx+c=o.
If the equation ax2 +bx +c =0 has roots α and β, then
Quadratic Equations
Where      a = coefficient of x2
                b = coefficient of x,
                c = constant term
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Quadratic Equations - How to Solve Quickly 4.5 5 Yateendra sahu May 18, 2016 Today I am sharing quick technique to solve Quadratic Equations quickly. I will also share practice questions on same to; A polynomial ...


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