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Study the given table carefully to answer the following questions.
Field Name
|
Side (in m)
|
Base (in m)
|
Height (in m)
|
Radius (in m)
|
Cost of flooring (in Rs. per sq. metre)
|
Cost of fencing (in Rs. per m)
|
|
---|---|---|---|---|---|---|---|
Parallelogram
|
|||||||
Arrival time
|
Departure time
|
Distance from origin (in km)
|
Number of passengers boarding at each station
|
Fare (in Rs.)
|
|
---|---|---|---|---|---|
Terminates
|
Arrival time
|
Departure time
|
Distance from origin
|
Number of passengers boarding at each station
|
Fare (in Rs.)
|
|
---|---|---|---|---|---|
12:00 noon
|
Terminates
|
Solutions
So, area of A = 1/2 × 16 × 12 = 96 sqm
So, cost of flooring of A = 96 × 50 = Rs.4800
2. Option A
So, cost of fencing of B = 60 × 15 = 900
Perimeter of C = 4 × 15 = 60 m
So, cost of fencing of C = 60 × 18 = Rs.1080
So, required difference = 1080 ⎯ 900 = Rs.180
3. Option D
Area of D = Base × Height
= 20 × 12 = 240 mtr sq
So, cost of flooring of D= 240 × 60 = Rs.14400
Perimeter of D = 2 (20 + 12) = 64 m
So, cost of fencing of D = 64 × 25 = Rs.1600
So, required ratio = 14400 : 1600 = 9 : 1
4. Option D
Perimeter of E = 2πr = 2 × 22/7 × 10 = 440/7 m
Cost of fencing of E = 440/7 × 22 = Rs.1382.85
Area of C = 15 * 15= 225 mtr square
So, cost of flooring of C = 225 × 40 = Rs.9000
So, required % = 1382.85 x 100 / 9000
= 15.36% of flooring cost of C.
Fencing cost of C = Rs.1080
Fencing cost of D = Rs.1600
Required % = 1080/1600 × 100 = 67.5%
6. Option A
Required percentage = 100/270 × 100 = 37.03%
7. Option A
Speed of Train A = 1280 / 10:20 am – 5:00 pm
= 1280 x 3 / 52 = 73.84 kmph
Speed of train B = 1280 / 12:00 noon ⎯ 6:00 pm
= 1280/18 hours = 71.11 kmph
So, difference between the speed of train A and train B = 73.84 ⎯ 71.11 = 2.73 kmph
8. Option B
Total passengers in train A = 400 + 100 + 90 + 300 + 150 = 1040
Total passengers in train B = 300 + 150 + 270 + 50 + 100 = 870
So, required ratio = 1040 : 870 = 104 : 87
9. Option E
Total income of train A = (400 × 50) + (500 × 70) + (590 × 280) + (890 × 100) + (1040 × 120) = Rs.434000
Total income of train B = (300 × 120) + (450 × 100) + (620 × 280) + (670 × 70) + (770 × 50) = Rs.340000
So, required % = 434000 x 100 / 340000
= 127.64% of the total income of train B.
10. Option C
If the average speed of train A increases by 10%
then its new speed = 73.84 × 110/100
= 81.22 kmph
Time taken by train A during the journey = 1280/81.22 = 15.75 hours = 15 hours 45 minutes
The time when the train will reach its destination = 5 pm + 15 hours 45 minutes = 8:45 am
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