Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-26)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-1)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-26):

Dear Readers, Nowadays most of the aspirants are facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.

Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). (609)^2 + 25% of 200 – 3/4 of 1976 = ?

1). Answer: d)
370881 + 50 - 494 × 3
= 370881 + 50 - 1482 = 369449

2. √17161 × 18 + 92 × 94 + 2/5 of 125 = ?

2). Answer: c)
? = √17161 × 18 + 92 × 94 + 2/5 of 125
= 131 × 18 + 8648 + 50
= 2358 + 8648 + 50 = 11056

3. ?% of 650 + 40% of 525 = 275

3). Answer: c)
?% of 650 + 40% of 525 = 275
?/100 × 650 + 210 = 275
6.5 × ? = 275 - 210 = 65
? = 650/65 = 10

4. 3√12167 ×√11881 + 70% of 6210=?

4). Answer: c)
? = 3√12167 ×√11881 + 70%of 6210
= 23 x 109 + 70/100 × 6210
= 2507 + 4347 = 6854

5). ∛35937 ×∛1331 ÷ √121 + 60% of 1295 = ?

5). Answer: d)
? = 3√35937 × 3√1331 ÷√121 + 60% of 1295
= 33 × 11 ÷ 11 + 3/5 × 1295
= 33 + 777 = 810

6. 15% of 240 + √11449 - 25% of 160 = ?

6). Answer: d)
? = 15/100 × 240 + 107 – 25/100 × 160
= 36 + 107 - 40 = 103

7. (64)^4.5 × (4096)^3.4 ÷ (16)^1.5 × (4)^3 = ?

7). Answer: d)
? = (64)^4.5 × (4096)^3.4 ÷ (16)^1.5 × (4)³
= (4³)^4.5 × (4^6)^3.4 ÷ (42)^1.5 × 4^3
= (4)^13.5 × (4)^20.4 ÷ (4)^3 × 4^3
= (4)^(13.5) × (4)^(20.4 – 3) × 4^3
= (4)^(13.5 + 17.4 + 3)
= (4)^(33.9)

8. (207)^2 + 20% of 200 × √1225 - 25% of 160 = ?

8). Answer: c)
? = (207)² + 20% of 200 × √1225 - 25.1% of 160
= 42849 + 1/5 × 200 × 35 – 1/4 × 160
= 42849 + 40 × 35 - 40 = 44209

9. √9216 ×∛1728 - 40%of 1200 = ?

9). Answer: d)
? = √9216 × ³√1728 - 40% of 1200
= 96 × 12 – 2/5 × 1200
= 1152 - 480 = 672

10. 2/5 of 1/4 of 5/3 of ∛46656 = ?

10). Answer: c)
? = 2/5 × 1/4 × 5/3 ×3√46656 =1/6 × 36 = 6

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11. (871% of 752) ÷ 251 = ?

11). Answer: a)
? = (871% of 752) + 251
= (870 / 100) × 750 × (1 / 250) = 26.1 ≈ 26

12. 0.5% of 349 × 8.2% of 574 = ?

12). Answer: a)
?= (0.5% of 349) × (8.2% of 574)
= (0.5% of 350) × 8% of 575
= [( 0.5 / 100) × 350] × [( 8 / 100) × 575]
= (1.75 × 46) = 80.5

13. 29.99% of 155.012 + 12.98% of 164.99 = ?

13). Answer: e)
? = 29.99% of 155.012 + 12.98% of 164.99
= (30% of 155) + (13% of 165)
= [ (30 / 100) × 155 ] + [ (13 / 100) × 165 ]
= 46.5 + 21.45 = 67.95 ≈ 68

14. 57% of 394 – 2.5% of 996 = ?

14). Answer: c)
? = (57% of 394) – (2.5% of 996) = ?
? ≈ [(57 × 400) / 100] – [(25 × 1000) / 1000]
(actual answer less than this)
= 228 – 25 = 203 = 200

15. (1.65% of 5471) – (0.61% of 8336) = ?

15). Answer: e)
? = (1.65% of 5471) – (0.61% of 8336) = ?
≈ (1.5% of 5470) – (0.5% of 8340)
= [(1.5 / 100) × 5470] – [(0.5 / 100) × 8340]
= 82.05 – 41.7 ≈ 40.35

16. 74.75% of 240 + 151% of 180 = ?

16). Answer: d)
(74.75% of 240) + (151% of 180) = ?
= (75% of 240) + (150% of 180)
= [(75 / 100) × 240] – [(150 / 100) ×180]
= (180 + 270) = 450

17. 49% of 2647 + 27% of 7589 = ?

17). Answer: b)
? = (49% of 2647) + (27% of 7589)
≈ (50% of 2650) + (25% of 7590)
= [(50 / 100) × 2650] – [(25 / 100) × 7590]
= (1325 + 1897.5) ≈ 3222.5

18. 23.5% of 4924.2 + ? % of 4324.4 = 1849.091

18). Answer: a)
23.5% of 4924.2 + ? % of 4324.4 = 1849.091
(? / 100) × 4325 ≈ 1850 – 4925 × (23.5 / 100)
? ≈ (693 × 100) / 4325
? = 16

19. (296% of 112) ÷ 73.92 = ?

19). Answer: e)
(296% of 112) ÷ 73.92 = ?
= (296% of 112) ÷ 74
= (296 / 100) × 112 × (1 / 74) ≈ 4.48

20.(37% of 1222 – 13% of 1211) ÷ 61 = ?

20). Answer: e)
? = (37% of 1222 – 13% of 1211) ÷ 61 = ?
= [(37 / 100) × 1200] – [(13 / 100) × 1200] × (1 / 60)
= [1200 / (100 × 60) ] × (37 – 13) = 4.8 ≈ 5

Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.
21. 2, 6, 18, 54, 162, ?, 1458

21). Answer: b)
The series is ×3, ×3, ×3, ×3,…..

22. 0, 3, 8, 15, 24, 35, 48, ?

22). Answer: c)
The series is 1² – 1, 2² – 1, 3² – 1, 4² – 1, 5² – 1, …..

23. 0, 7, 26, 63, 124, ?, 342

23). Answer: d)
The series is 1³ – 1, 2³ – 1, 3³ – 1, 4³ – 1, 5³ – 1,…..

24. 9, 11, 16, 26, ?, 69

24).Answer: e)
The difference of difference of the series is, 3, 5, 7, 9,..

25. 3, 4, 10, 33, 136, ?

25). Answer: a)
The series is,
3 x 1 + 1 = 4
4 x 2 + 2 = 10
10 x 3 + 3 = 33
33 x 4 + 4 = 136
136 x 5 + 5 = 685

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) if x > y
b) if x ≥ y
c) if x < y < br > d) if x ≤ y
e) if x = y or no relation can be established between x and y.

26). I. x² – 11x + 30 = 0
II. 2y² – 9y + 10 =0

26). Answer: a)
I.x² – 6x – 5x + 30 = 0
x (x-6) -5 (x- 6) = 0
(x-6) (x-5) = 0
=> x = 6, 5.
II. 2y² – 9y + 10 =0
2y² – 4y – 5y + 10 =0
2y (y-2) -5 (y-2) =0
=> y = 2, 5/2.
Therefore, x > y

27). I. 15x² + 8x + 1 =0
II. 3y² + 14y + 8 = 0

27). Answer: a)
I.15x² + 8x + 1 =0
15x² + 5x + 3x + 1 =0
5x (3x+1) + 1(3x+1)) = 0
(5x+1) (3x+1) = 0
=> x = -1/5, -1/3.
II. 3y² + 14y + 8 = 0
3y² + 12y +2y + 8 = 0
3y (y+4) +2(y+4) =0
=> y = -4, -2/3.
Therefore, x > y

28). I. 4x² – 17x+ 18 = 0
II. 2y² – 21y + 40 = 0

28). Answer: c)
I.4x² – 17x+ 18 = 0
4x² -8x -9x + 18 =0
4x (x-2)-9(x-2)) = 0
(x-2)(4x-9) = 0
=> x = 2, 9/4
II. 2y² – 21y + 40 = 0
2y² – 16y-5y + 40 = 0
2y(y-8)-5(y-8) =0
=> y = 8, 5/2.
Therefore, x < y

29). I. 6x² – 25x + 14 =0
II. 9y² -9y + 2 =0

29). Answer: b)
I. 6x² – 25x + 14 =0
6x² – 4x -21x + 14 =0
2x (3x-2)-7(3x-2)) = 0
(2x-7)(3x-2) = 0
=> x = 7/2, 2/3
II. 9y² -9y + 2 =0
9y² -6y -3y + 2 =0
3y(3y-2)-1(3y-2) =0
=> y = 2/3, 1/3.
Therefore, x ≥ y

30). I.8x² + 25x + 3 =0
II. 2y² + 17y + 30 = 0

30). Answer: e)
I. 8x² + 25x + 3 =0
8x² + 24x + x + 3 =0
8x (x+3)+1(x+3)) = 0
(8x+1)(x+3) = 0
=> x = -1/8, -3
II. 2y² + 17y + 30 = 0
2y² + 12y +5y + 30 = 0
2y (y+6) +5(y+6) =0
(2y+5) (y+6) =0
=> y = -5/2, -6.
Therefore, the relationship cannot be established.