Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-35):
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Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). 67.5% of 546 + 16.7% of 1245 = ?
1). Answer: b)
? = 368.55 + 207.915 = 576.465
2). (1/5) of 1670 + (1/4) of 2456 – (1/0.5) of 677 = ?? = 368.55 + 207.915 = 576.465
2). Answer: c)
? = 334 + 614 – 1354 = – 406
3).(169×4)^1/2 + (981÷9)^2 = 7371 + ?? = 334 + 614 – 1354 = – 406
3). Answer: a)
676^1/2 + 109^2 = 7371 + ?
26 + 11881 = 7371 + ?
? = 11907 – 7371 = 4536
4). 1238 .05÷125 × 32.03 + 0.04 = ?676^1/2 + 109^2 = 7371 + ?
26 + 11881 = 7371 + ?
? = 11907 – 7371 = 4536
4). Answer: d)
? = 9.9 × 32.03+0.04 = 317.14
5).(1243+654+342+ ?) ÷ (864+468+124) = 1.61? = 9.9 × 32.03+0.04 = 317.14
5). Answer: c)
(2239+?) = 1.61 * 1456
? = 2344.16 – 2239 = 105.16
6). 4325.6 + 659.6 – 543.3 + 3478 – 0.005 = ?(2239+?) = 1.61 * 1456
? = 2344.16 – 2239 = 105.16
6). Answer: a)
? = 8463.2 – 543.305 = 7919.89 = 7920
7). (15.25) ^2 + (0.50)^2 – (65.65)^2 + (26.67)^2 – (18.98)^2 = ?? = 8463.2 – 543.305 = 7919.89 = 7920
7). Answer: c)
? = 232.56+0.25- 4310 + 711.29 – 360.24 = -3726.14
8). (441/?) = (?/3364)? = 232.56+0.25- 4310 + 711.29 – 360.24 = -3726.14
8). Answer: a)
? = 21*58 = 1218
9). (0.0144)^1/2 + (2.5)^2 = ?? = 21*58 = 1218
9). Answer: c)
? = 0.12 + 6.25 = 6.37
10).(13824)^1/3 + (5776)^1/2 =x^2? = 0.12 + 6.25 = 6.37
10). Answer: d)
? = 24+76 = 100
Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?? = 24+76 = 100
11). 286.04×11.646+65.37×54.08=?+137.989
11). Answer: c)
?+137.989=286.04×11.646+65.37×54.08
286×12 + 65×54
3432+3510 = 6942
Or, ?+138 = 6942
? = 6942-138 = 6804 ≈ 6800
12). 85943 + 71206 + 37517 – 3512 + 119 = ??+137.989=286.04×11.646+65.37×54.08
286×12 + 65×54
3432+3510 = 6942
Or, ?+138 = 6942
? = 6942-138 = 6804 ≈ 6800
12). Answer: a)
? = 85940 + 71200 + 37520 – 3510 + 120 = 191270
? ≈ 191300
13). 20440÷639.890=√(?)? = 85940 + 71200 + 37520 – 3510 + 120 = 191270
? ≈ 191300
13). Answer: d)
√(?) = 20440÷640 = 31.94 ≈ 32
? = 32×32 = 1024
14). 122.05% of 120+149.99% of 150=?√(?) = 20440÷640 = 31.94 ≈ 32
? = 32×32 = 1024
14). Answer: a)
? = (122×120/100)+(150×150/100)
= (146.4+225)
= 371.4
? ≈ 371
15). (9.899)^3×(2.399)^2×(4.005)^4=?? = (122×120/100)+(150×150/100)
= (146.4+225)
= 371.4
? ≈ 371
15). Answer: c)
? = (9.9)^3×(2.4)^2×(4)^4
= (970.299)×(5.76)×256
≈ (970.3)×(5.75)×256 = 1428281.6 ≈ 1428200
16).999.99÷25.012 = ? – 235.448? = (9.9)^3×(2.4)^2×(4)^4
= (970.299)×(5.76)×256
≈ (970.3)×(5.75)×256 = 1428281.6 ≈ 1428200
16). Answer: c)
1000/ 25 = ? – 235
40 = ? – 235
? = 235+40 = 275
17). 633.72-569.21÷(11.9% of 80)=?1000/ 25 = ? – 235
40 = ? – 235
? = 235+40 = 275
17). Answer : b)
?=633.72-569.21÷(11.9% of 80)
= 634-570÷(80×12)/100
= 634-570/9.6 =634 – 59.375 =575 (approx)
18). 67.69 -11.78 + 19.63 =? + 22.41?=633.72-569.21÷(11.9% of 80)
= 634-570÷(80×12)/100
= 634-570/9.6 =634 – 59.375 =575 (approx)
18). Answer : b)
67.69 -11.78 + 19.63 =?+ 22.41
68 – 12+20 = ? + 22 = 88-12 -22 = 54
19). (49.999)^2+(59.96)^2+(64.501)^2 =?67.69 -11.78 + 19.63 =?+ 22.41
68 – 12+20 = ? + 22 = 88-12 -22 = 54
19). Answer : c)
?=(50)^2+(60)^2+(64.5)^2 = 2500+3600+4160.25 ≈ 10260
20). √1224 + √2210 – √5327 = √??=(50)^2+(60)^2+(64.5)^2 = 2500+3600+4160.25 ≈ 10260
20). Answer : a)
√? ≈ √1225 + √2209 – √5329
√? = 35 + 47 - 73 = 9
? = 81
Direction (21 – 25): What will come in place of (?) in the following number series.√? ≈ √1225 + √2209 – √5329
√? = 35 + 47 - 73 = 9
? = 81
21).872,872, 888, 824, 968, ?
21). Answer: a)
The series is,
872 – 0^2 = 872
872 + 4^2 = 888
888 – 8^2 = 824
824 + 12^2 = 968
968 – 16^2 = 712
22).69, 84, 189, ?, 1197, 2484The series is,
872 – 0^2 = 872
872 + 4^2 = 888
888 – 8^2 = 824
824 + 12^2 = 968
968 – 16^2 = 712
22). Answer: c)
The series is,
69+(1*3*5) = 84
84+(3*5*7) = 189
189+(5*7*9) = 504
504+(7*9*11) = 1197
1197+(9*11*13) = 2484
23). 156, 173, 131, 206, 90, ?The series is,
69+(1*3*5) = 84
84+(3*5*7) = 189
189+(5*7*9) = 504
504+(7*9*11) = 1197
1197+(9*11*13) = 2484
23). Answer: d)
The series is,
156+17*1 = 173
173-21*2 = 131
131 + 25*3 = 206
206-29*4 = 90
90+33*5 = 255
24). 980, 191, ?, 253, 508, 507The series is,
156+17*1 = 173
173-21*2 = 131
131 + 25*3 = 206
206-29*4 = 90
90+33*5 = 255
24). Answer: c)
The series is
980÷5 -5 = 191
191*4+4 = 768
768÷3-3 = 253
253*2+2 = 504
504÷1-1 = 503
25). 33, 165, 825, ? , 20625The series is
980÷5 -5 = 191
191*4+4 = 768
768÷3-3 = 253
253*2+2 = 504
504÷1-1 = 503
25). Answer: b)
The series is,
33*0.5÷0.1 = 165
165*1÷0.2 = 825
The series is,
33*0.5÷0.1 = 165
165*1÷0.2 = 825
825*1.5÷0.3 = 4125
4125*2÷0.4 = 20625
Direction (26-30): In each of these questions, two equations I & II are given. You have to solve both the equations and given answer:
a) If X > Y
b) If X < Y
c) If X ≥ Y
d) If X ≤ Y
e) If X = Y or relation cannot be established
26).I. 2X^2 + 11X + 12= 0
II.5Y^2 + 27Y + 10 = 0
26). Answer: e)
(2x+3)(x+4) = 0
X= -3/2, -4
(5y+2)(y+5) = 0
Y = -5, -2/5
Hence, the relation cannot be established.
27). I. 25X^2 + 25X + 6= 0(2x+3)(x+4) = 0
X= -3/2, -4
(5y+2)(y+5) = 0
Y = -5, -2/5
Hence, the relation cannot be established.
II.5Y^2 + 20Y + 20 = 0
27). Answer: a)
(5x+2)(5x+3) = 0
X = -2/5, -3/5
(5y+10)(y+2) = 0
Y = -2, -10/5 = -2, -2
Hence, x > y
28). I. 3X^2 + 7X + 4= 0(5x+2)(5x+3) = 0
X = -2/5, -3/5
(5y+10)(y+2) = 0
Y = -2, -10/5 = -2, -2
Hence, x > y
II.3Y^2 + 10Y + 8 = 0
28). Answer: c)
(x+1)(3x+4) = 0
x = -1, -4/3
(3y+4)(y+2) =0
y = -4/3, -2
Therefore x ≥ y
29). I.(x+y)^2 = 900(x+1)(3x+4) = 0
x = -1, -4/3
(3y+4)(y+2) =0
y = -4/3, -2
Therefore x ≥ y
II.Y + 1689 = 1705
29). Answer: b)
y = 1705 – 1689 = 16
(x + y)^2 = 900
x + y = 30
x = 30 – 16 = 14
Therefore, x < y
30). I.8X^2 + 3X – 38= 0y = 1705 – 1689 = 16
(x + y)^2 = 900
x + y = 30
x = 30 – 16 = 14
Therefore, x < y
II.6Y^2 – 29Y + 34 = 0
30). Answer: d)
8X^2 + 3X – 38= 0
(8x + 19) (x – 2) = 0
x = 2 or -19/8
6Y^2 – 29Y + 34 = 0
(y – 2) (6y – 17) = 0
y = 2 or 17/6
Therefore, x ≤ y
8X^2 + 3X – 38= 0
(8x + 19) (x – 2) = 0
x = 2 or -19/8
6Y^2 – 29Y + 34 = 0
(y – 2) (6y – 17) = 0
y = 2 or 17/6
Therefore, x ≤ y
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