Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-14)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-14):

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Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). 243 × 124 - 25340 = ?

1). Answer: b)
? = 243 × 124 - 25340
? = 30132 - 25340 = 4792

2. 92 ÷ 8 ÷ 2 = ?

2). Answer: b)
? = 92 / (8 × 2)
? = 5.75

3. (121)^3 × 11 ÷ (1331)^2 = (11)^?

3). Answer: c)
(121)^3 × 11 ÷ (1331)^2 = (11)^?
or (11^2)^3 × 11 / (11^3)^2 = (11)^?
(11) ^? = (11)^6 × 11 / (11)^6
(11)^? = (11)^1
? = 1

4. 283.56 + 142.04 + 661.78 = ?

4). Answer: e)
? = 283.56 + 142.04 + 661.78
? = 1087.38

5). 7028 ÷ 25 = ?

5). Answer: e)
7028 ÷ 25 = 281.12

6. 390.5 × √? = 284 × 22

6). Answer: d)
390.5 × √? = 284 × 22
or 284 × 22 / 390.5 = √?
62480 / 3905 = √?
√? = 16
? = 256

7. 12.5 × 8.4 × 7.6 = ?

7). Answer: e)
? = 12.5 × 8.4 × 7.6 = 798

8. 4477 ÷ (44 × 5.5) = ?

8). Answer: d)
? = 4477 / (44 × 5.5)
? = 4477 / 242
? = 18.5

9. 33.5% of 250 = ?

9). Answer: d)
? = 33.5 /100 × 250
? = 33.5 × 2.5
? = 83.75

10.1/2 of 3/5 of 4/9 of 5820 = ?

10). Answer: c)
? = 1/2 × 3/5 × 4/9 × 5820
? = 69840 / 90
? = 776

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11.8787 ÷ 343 × √50 = ?

11). Answer: c)
? = 8787 ÷ 343 × √50
? = 25.61 × 7.07 = 181.09 ≈ 180

12. ³√54881 × (303 ÷ 8) = (?)^2

12). Answer: b)
³√54881 × (303 ÷ 8) = (?)^2
(?)^2 = 38 × 37.8
(?)^2 ≈ 38 × 38
? = 38

13. 5/8 of 4011.33 + 7/10 of 3411.22 = ?

13). Answer: c)
? = 5/8 × 4011.33 + 7/10 × 3411.22
? = 20056.65 / 8 + 23878.54 / 10
? = 2507.08 + 2387.854
? ≈ 2507 + 2388
? = 4895 ≈ 4890

14. 23% of 6783 + 57% of 8431 = ?

14). Answer: e)
? = 23% of 6783 + 57% of 8431
? = 23/100 × 6783 + 57/100 × 8431
? = 23 × 67.83 + 57 × 84.31
? = 1560.09 + 4805.67
? = 6365.76 ≈ 6360

15. 335.01 × 244.99 ÷ 55 = ?

15). Answer: a)
? = 335.01 × 244.99 ÷ 55
? ≈ 335 × 245 ÷ 55
? = 335 × 245/55 = 82075 / 55
? = 1492.27 ≈1490

16. (280% of 1525) ÷ 16.96 = ?

16). Answer: e)
? ≈ 280 × 1525 / (100 × 17)
? = 251.17 ≈ 250

17. 668.612 + 119.19 × 21.86 - 79.54 = ?

17). Answer: c)
? ≈ 670 + 119 × 22 - 80
? = 670 + 2618 - 80 = 3288 - 80
? = 3208 ≈ 3200

18. 612.98 ÷ 15.05 ÷ 6.12 = ?

18). Answer: a)
? ≈ 613 / (15 × 6) = 6.81 ≈ 7

19. ³√615 = ?

19). Answer: e)
(8.5) ^3 = 614.125 ≈ 615
³√615 ≈ 8.5

20.(314% of 711) ÷ 114 = ?

20). Answer: b)
? ≈ 314 × 710 / (100 × 114)
? = 19.55 ≈ 20

Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.21. 40, 326, 2946, 29418, 323607

21). Answer: c)
The series is,
40 x 8+6 = 326
326 x 9+7 = 2941 ≠ 2946
2941 x 10+8 = 29418
29418 x 11+9 = 323607

22. 560, 1089, 1725, 2443, 3284, 4245

22). Answer: b)
The difference between numbers is +23^² ,+25^² , +27^² , +29^² .......
Therefore, 1089 + 25^2 = 1714 ≠ 1725

23. 3250, 3082, 2958, 2876, 2826

23). Answer: a)
The difference between numbers is -(13^²+1), -(11^²+1), -(9^²+1) , -(7^²+1), -(5^²+1)
3250 - (13^²+1) = 3080 ≠ 3082

24. 2442 , 1222 , 614 , 312 ,163 , 90 , 56.25

24). Answer: c)
The series is,
2442/2 + 1 = 1222
1222/2 + 3= 614
614/2 + 5 = 312
312/2 + 7 =163
163/2 + 9 = 90.5 ≠ 90
90.5/2 + 11 = 56.25

25. 1254, 1322, 1450, 1674, 2024, 2544

25). Answer: e) The difference between numbers is +(4^³+4) , +(5^³+5), +(6^³+6) , +(7^³+7), +(8^³+8)
1322 + (5^³+5) =1452 ≠ 1450

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) If x > y
b) If x ≤ y
c) If x < y
d) If x ≥ y
e) If x = y or relationship between x and y can't be established.

26. I. 4x^2 - 13x - 17 =0
II. 3y^2 + 10y + 8 = 0

26). Answer: a)
I. 4x^2 - 13x - 17 = 0
or, 4x^2 -17x + 4x - 17 = 0
or, 4x(x + 1) --17(x + 1) = 0
or, (4x - 17) (x + 1) = 0
x = 17/4, -1
II. 3y^2+ 10y + 8 = 0
or, 3y^2 + 6y + 4y + 8 = 0
or, 3y (y + 2) + 4(y + 2) = 0
or, (3y + 4) (y + 2) = 0
y = - (4/3) , -2
Hence x > y

27.I. 7x + 3y = 7
II. 5x - 6y = 8

27). Answer: a)
I. 7x + 3y =7 ...(i)
II. 5x – 6y = 8 …(ii)
Solving (i) x 6 + (ii) x 3, we get
42x +18y = 42
15x -18y = 24
57x =66
x = 66/57 = 22/19
Putting the value of x in equation (i), we get
7× (22/19) + 3y = 7
Or, 3y = 7 – (154/19) = - (21/19)
y = - (7/19)
Hence x > y

28. I. x^2 +10x – 96 = 0
II. 3y^2 + 11y -14=0

28). Answer: e)
I. x^2 + 10x - 96 = 0
or, x^2+ 16x - 6x - 96 = 0
or, x(x + 16) - 6(x + 16) = 0
or, (x - 6) (x + 16) = 0
x = 6, -16
II. 3y^2 + 11y - 14 = 0
or, 3y^2 + 14y - 3y - 14 = 0
or, 3y(y - 1)+ 14(y- 1) = 0
or, (3y + 14) (y - 1) = 0
y = - (14/3), 1
Hence no relationship can be established.

29. I. x^2 - 6x + 5 = 0
II. y^2 - 4y + 3 = 0

29). Answer: e)
I. x^2 - 6x + 5 = 0
or, x^2 - 5x - x + 5 = 0
or, x(x - 5) - 1(x - 5) = 0
or, (x - 1) (x - 5) = 0
x = 1, 5
Il.y^2 - 4y + 3 = 0
or, y^2 - 3y - y + 3 = 0
or, y(y - 3) - 1(y - 3) = 0
or, (y -1) (y - 3) = 0
y = 1, 3
Hence no relation can be established.

30. I. x^2 - 11x + 30 = 0
II. y^2 - 7y + 10 = 0

30). Answer: d)
I. x^2 – 11x + 30 = 0
or, x^2 - 6x - 5x + 30 = 0
or, x(x -6) – 5 (x - 6) = 0
or, (x - 5) (x - 6) = 0
x = 5, 6
II. y^2 - 7y + 10 = 0
or, y^2 - 5y - 2y + 10 = 0
or, y(y - 5) – 2(y – 5) = 0
or, (y - 2) (y - 5) = 0
y = 2, 5
Hence x ≥ y