Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-12)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-12):

Dear Readers, Nowadays most of the aspirants are facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.

Here in Scoring Part we are providing 10 Questions in simplification, 10 Questions in Approximation, 5 Questions in number Series and 5 Questions in Quadratic Equations, total 30 questions in 20 Minutes. By practicing these questions regularly you can increase your calculation speed and it will help you to increase your score.

Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). 924 × 0.75 + 848 × 1.25 = ? × 0.25

1). Answer: c)
0.25 × ? = 693 + 1060 = 1753
? = 1753 / 0.25 = 7012

2. 17/7 of 3/8 × 5/4 of ? = 4590

2). Answer: b)
? = 4590 × 7 × 8 × 4 / (17 × 3 × 5)
? = 4032

3. [(342)^3 ÷ (57)^2] ÷ 216 = ?

3). Answer: a)
? = [(342)^3 / (57)^2] ÷ 216
? = 36 × 342 / 216 = 57

4. 26.8% of 480 - 13.4% of 180 = ? × 0.06

4). Answer: b)
0.06 × ? = 26.8 × 480 / 100 – 13.4 × 180 / 100
0.06 × ? = 128.64 - 24.12
? = 104.52 / 0.06 = 1742

5). [(3.673)^3 + (7.327)^3] ÷ [(3.673)^2 + (7.327) ^2 - (3.673 × 7.327)] = ?

5). Answer: b)
Wkt, (a + b) = (a^3 + b^3) / (a^2 + b^2 – ab)
? = (3.673 + 7.327) = 11

6. √53.29 ÷ (30)^-2 = ?

6). Answer: b)
√53.29 ÷ (30)^-2 = 7.30 × 900 = 6570

7. 13% of 1335 + ?% of 1135 = 366.5

7). Answer: d)
? = [366.5 - (1335 × 0.13)] / 1135 × 100
? = 192.95 × 100 / 1135 = 17

8. 11/113 of 7/85 of 115260 = ?

8). Answer: e)
? = 115260 × 11 × 7 / (113 × 85)
? = 924

9. 2786 + 105 × ? = 304 × 14

9). Answer: b)
105 × ? = (304 × 14) - 2786
105 × ? = 4256 - 2786
? = 1470 / 105 = 14

10.³√1061208 = ?

10). Answer: c)
³√1061208 = 102

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11.872 × 7 × ? = 336633

11). Answer: b)
? = 336633 / (872 × 7)
? = 55.1495 ≈ 55

12. (442 . 22 + 788.08) ÷ 6.06 = ?

12). Answer: a)
? ≈ (442 + 788)/6
? = 1230/6 = 205

13. 113.03 × 14.969 - 12.08 × 8.98 = ?

13). Answer: c)
? ≈ (113 × 15) - (12 × 9)
? = 1695 - 108
? = 1587 ≈ 1590

14. ³√389000 = ?

14). Answer: b)
(73)^3 = 389017
Therefore, ? = ³√389000 ≈ 73

15. 7640.16 / 120.08 × √1220 = ?

15). Answer: c)
? ≈ 7640 / 120 × 35
? = 63.6 × 35 = 2226

16. √730 + √3365 = ? × 4.936

16). Answer: c)
? ≈ (27 + 58) / 5
? = 85 / 5 = 17

17. 7824 ÷ 47.87 + 3236 ÷ 57.011 = ?

17). Answer: b)
? ≈ 7824 ÷ 48 + 3236 ÷ 57
? = 163 + 56.77
? = 219.77 ≈ 220

18. 2.8% of 312 + 1.2% of 416 = ?

18). Answer: c)
? = 2.8 × 3.12 + 1.2 × 4.16
? = 8.736 + 4.992
? = 13.728 ≈ 14

19. 189.089 × 3.27 + 4.004 × 111.819 = ?

19). Answer: c)
? ≈ 190 × 3.25 + 4 × 112
? = 617.5 + 448
? = 1065.5 ≈ 1065

20.(324% of 5842) ÷ 194.79 = ?

20). Answer: d)
? ≈ (324 × 58.42) ÷ 195
? ≈ 18928 ÷ 195 = 97

Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.21. 150, 102, 70 , 46 , 26 , ?

21). Answer: b)
The difference of difference of the series is -16, -8, -4, -2

22. 10 , 14 , 28 , 52 , 134 , ?

22). Answer: d)
The first series is, 10, 28, 134
10 x 3 - 2= 28
28 x 5 - 6= 134
The second series is 14, 52, ?
14 x 4 - 4= 52
52 x 6 - 8= 304
i.e, The sequence of the series is x 3 – 2, x 4 – 4, x 5 – 6, x 6 - 8

23. 4500 , 900 , 90 , 6 , ? , 0.012

23). Answer: a)
The series is,
4500/5 = 900
900/10 = 90
90/15 = 6
6/20 = 0.3
0.3/25 = 0.012

24. 24 , 11 , 10 , 14 , 27 , ?

24). Answer: d)
The sequence in the series is,
24 x (1/2) – 1 = 11
11 x (2/2) – 1 = 10
10 x (3/2) – 1 = 14
14 x (4/2) – 1 = 27
27 x (5/2) – 1 = 66.5

25. 8 , 7 , 12 , 33 , 128 , ?

25). Answer: e)
The series is,
8 x 1 – 1 = 7
7 x 2 – 2 = 12
12 x 3 – 3 = 33
33 x 4 – 4 = 128
128 x 5 – 5 = 635

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) x = y or No relation
b) x > y
c) x < y
d) x ≥ y
e) x ≤ y

26. I. x - 7 = 0
II. 3y^2 - 10y + 7 = 0

26). Answer: b)
From I, x - 7 = 0
x = 7 …..(1)
From II, 3y^2 - 10y + 7 = 0
3y^2 - 3y - 7y + 7 = 0
(3y - 7)(y - 1) = 0
y = 1, 7/3 ....(2)
From (1) and (2), we have x > y.

27.I. 4y^2 + 8y = 4y + 8
II. x^2 + 9x = 2x - 12

27). Answer: c)
From I, 4y^2 + 8y = 4y + 8
Y^2 + 2y = y + 2
y^2 + 2y – y – 2 = 0
(y- 1) (y + 2) = 0
y= 1, - 2 ...(1)
From II, x^2 + 9x = 2x - 12
X^2 + 7x +12 = 0
(x + 4) (x + 3) = 0
x = - 4, - 3 ....(2)
From (1) and (2), we have y > x.

28. I. 2x^2 + 40 =18x
II. y^2 = 13y - 42

28). Answer: c)
From I, 2x^2 + 40 = 18x
2x^2 + 40 - 18x = 0
X^2 - 9x + 20 = 0
(x - 4)(x - 5) = 0
x= 4, 5 ...(1)
From II, y^2 = 13y - 42
Y^2 - 13y + 42 = 0
(y - 7)(y - 6) = 0
y = 7, 6 ...(2)
From (1) and (2), we have y > x.

29. I. 2x^2 = 128
II. y^2 – 10y + 25 = 0

29). Answer: a)
From I, 2x^2 =128
X^2 = 64
x = √64 = 8 or -8 …..(1)
From II, y^2 - 10y + 25 = 0
Y^2 - 5y - 5y + 25 = 0
(y – 5) (y - 5) = 0
y = 5, 5 ….(2)
From 1 and 2 there is no relation between x and y.

30. I. x^2 – 5x + 6 = 0
II. y^2 + 24 = 10y

30). Answer: c)
I. x^2 - 3x – 2x + 6 = 0
x (x - 3) - 2(x - 3) = 0
(x - 3)(x - 2) = 0
x = 3, 2
y^2 -10y + 24 = 0
y^2 - 6y – 4y + 24 = 0
y (y - 6) - 4(y - 6) = 0
(y - 6) (y - 4) = 0
y = 6, 4
Therefore, x < y.