Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-1)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-1):

Dear Readers, Nowadays most of the aspirants were facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.

Here in Scoring Part we are providing 10 Questions in simplification, 10 Questions in Approximation, 5 Questions in number Series and 5 Questions in Quadratic Equations, total 30 questions in 20 Minutes. By practicing these questions regularly you can increase you calculation speed and it will help you to increase you score.

Direction (1-10): What will come in place of question mark (?) in the following questions:
1. 637.28 – 781.47 + 257.39 = ?

1).637.28 – 781.47 + 257.39 = 113.20
Answer: A

2. 6% of 350 + 2% of 700 = ?% of 1400

2). 6/100 × 350 + 2/100 × 700 = x/100 × 1400
14x = 21 + 14
14x = 35
X = 35/14 = 2.5
Answer: B

3. 4672 ÷ 40 ÷ 4 = ?.

3). 4672 ÷ 40 ÷ 4 = x
4672 / (40 × 4) = x
x = 29.2
Answer: C

4. 7 × ? = 546 ÷ 4

4). 7 × X = 546 ÷ 4
X = 546 / 28
X = 19.5
Answer: D

5. 672 ÷ 24 × 18 + 153 – 354 = ?

5). 672 ÷ 24 × 18 + 153 – 354 = X
X = 504 + 153 – 354
X = 303
Answer: E

6. 67.39 – 11.78 + 19.63 = ? + 22.41

6). (67.39 + 19.63) – (11.78 + 22.41) = ?
? = 87.02 – 34.19
? = 52.83
Answer: B

7. 44% of 125 + 75% of 840 = ?

7). 44/100 × 125 + 75/100 × 840 = ?
? = 44 × 5/4 + ¾ × 840
? = 55 + 630
? = 685
Answer: C

8. 8.5 × 6.4 + 4.5 × 11.6 = ? ÷ 4

8). 8.5 × 6.4 + 4.5 × 11.6 = ? ÷ 4
? = (54.4 + 52.2) × 4
? = 106.6 × 4
? = 426.4
Answer: D

9. √7921 + √3969 = ? .

9). √7921 + √3969 = ?
89 + 63 = ?
? = 152
Answer: C

10. 39.977 + 444.333 – 44444.43 + 44.33 – 39.77 = ?

10). 39.977 + 444.333 – 44444.43 + 44.33 – 39.77 = ?
? = - 43955.56
Answer: D

11. 1002 ÷ 49 × 99 – 1299 = ?

11). Values can be rounded off to the nearest ten’s places.
1002 = 1000; 49 = 50; 99 = 100 and 1299 = 1300
Now the equation will become
1000 ÷ 50 × 100 – 1300 = ?
20 × 100 – 1300 = ?
2000 – 1300 = ?
? = 700
Answer: A

12. 29.8% of 260 + 60.01% of 510 – 103.57 = ?.

12). The difference between two nearest values is 70 (210 and 280). So round off the numbers to the nearest integers.
29.8% of 260 = 30% of 260; 60.01% of 510 = 60% of 510 and 103.57 = 104
Now the equation will become
30% of 260 + 60% of 510 – 104 = ?
30/100×260 + 60/100×510 -104=?
78+306-104=?
? = 384 – 104 = 280
Answer: D

13. 16.001 × 30.999 × 8.998 = ?

13). ? ≈ 16 × 31 × 9 ≈ 4464
Required answer = 4450
Answer: A

14. (6.99)2 +(8.01)2 − √85 = ?

14). ? ≈ 7^2 + 8^2 − √81
≈ 49 + 64 - 9 ≈ 104
Answer: D

15. 49% of 5051 – (3/7) of 999 = ?.

15). [(49 × 5051) / 100] – (3/7) × 999 = 2475 – 430 = 2045.
Answer: A

16. 4329 / 19 + 6464 / 13 = ?

16).(4329 / 19) + (6464 / 13) = 228 + 497 = 725
Answer: B

17. (4.012)^3 + (29.997)^2 = ?

17). (4)^3 + (30)^2 = 64 + 900 = 964
Answer: B

18. 6575 / 17.98 × 42.03 / 6.87 = ?.

18). 6575 / 18 × 42 / 7 = (6575 / 18) × (42 / 7) = 365 × 6 = 2190 Answer: A

19. 12.002 × 15.005 – 8.895 × 6.965 = ?

19). 12 × 15 – 9 × 7 = 180 – 63 = 117
Answer: B

20. 12.664 × 22.009 × 17.932 = ?

20). 13 × 22 × 18 = 5148
Answer: C

Direction (21 – 25): What will come in place of the question mark (?) in the following number series?
21. 0, 3, 8, 15, 24, 35, 48, ?

21). The series 1^2 - 1, 2^2 - 1, 3^2 - 1, etc. The next number is 8^2 - 1 = 63 Answer: C

22. 2, 12, 36, 80, 150, ?

22). The series is 1^3 + 1^2, 2^3 + 2^2, 3^3 + 3^2 etc.
Answer: B

23. 1, 6, 13, 22, 33, ?

23). The pattern is + 5, + 7, + 9, + 11,...
.'. Missing number = 33 + 13 = 46.
Answer: C

24. 19, 2, 38, 3, 114, 4, ? .

24). The sequence is a combination of two series :
I. 19, 38, 114, (....) and II. 2, 3, 4
The pattern followed in I is * 2, * 3,...
.'. Missing number = 114 * 4 = 456.
Answer: D

25. 95, 115.5, 138, ?, 189.

25). The pattern is + 20.5, + 22.5,....
.'. Missing term = 138 + 24.5 = 162.5.
Answer: B

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) If x< y
b) If x ≤ y
c) If x = y, or no relation can be established between x and y.
d) If x > y
e) If x ≥ y

26. I. 9x^2 = 1
II.4y^2 + 11y – 3 =0

26). I. 9x^2 = 1
:. x2 = 1/9
:. x = ± 1/3
II.4y^2 +11y – 3 =0
Or, 4y^2 + 12y – y – 3= 0
Or, 4y(y + 3) – 1 (y + 3) = 0
:.y = 1/ 4, - 3
Hence, there is no relation between x and y.
Answer: C

27. I.3x^2 + 5x – 2 =0
II.2y^2 – 7y + 5 =0.

27). I. 3x^2 + 5x – 2 =0
Or, 3x^2 + 6x – x -2= 0
Or, 3x(x + 2) – 1(x + 2) =0
Or, (3x -1) (x +2) = 0
:. X = -2, 1/3
II. 2y^2 – 7y + 5 =0
2y^2 – 2y – 5y + 5 = 0
Or, 2y(y - 1) – 5 (y - 1) =0
:. y = 1, 5/2
Hence, x < y
Answer: A

28. I. 6x^2 + 13x + 5 =0
II.3y^2 + 11y + 10 =0

28). I. 6x^2 + 13x +5 =0
Or, 6x^2 + 3x +10x + 5=0
Or, 3x (2x +1)+ 5(2x + 1)= 0
Or, (3x + 5) (2x +1 ) = 0
:. X = - 5/3, -1/2
II.3y^2+11y+10 = 0
Or, 3y^2 + 6y + 5y+10 = 0
Or, 3y(y + 2) + 5(y + 2) = 0
Or, (3y + 5) (y + 2) = 0
:. y= - 5/3, -2
Hence, x ≥ y
Answer: E

29. I.7x – 4Y =29
II.5x + 3y – 50 =0

29). I. 7x – 4y = 29
II. 5x + 3y = 50
(I)×3 + (II)×4
21x - 12y = 87
20x + 12y = 200
41x = 287
:. x = 7
Putting the value of x in (I), we get
y = 5
Hence, x > y
Answer: D

30. I. x^2 – 5 =0
II.4y^2 – 24y + 35 =0.

30). I. x^2 = 5
:. x = ±√5 ≈ ± 2 .236
II.4y^2 – 24y + 35 =0
Or, 4y^2 – 14y – 10y + 35 = 0
Or, 2y (2y - 7) – 5(2y - 7)= 0
Or,(2y - 5) (2y - 7) = 0
:. y = 5/2, 7/2 = 2.5, 3.5
Hence, x< y
Answer: A