[Dated: 11th May] Mission SBI PO 2017: Data Interpretation Practice Questions:
Dear Readers, Important Practice Aptitude Questions for SBI PO 2017 Exam was given here with Solutions. Aspirants those who are preparing for SBI PO and all other Competitive examination can use this.
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Directions (Q. 1-5): Study the following pie-chart and table carefully and answer the questions given below.
Percentage distribution of the number of bikes sold by a dealer during six months
Total number of bikes sold = 75000
The ratio of the number of bikes of TVS Company to the number of computer of Bajaj Company sold during six months
1). What is the total number of bikes of Bajaj Company sold during November and December?
a) 7880
b) 9180
c) 8350
d) 9750
e) 8750
2). What is the ratio of the number of bikes of Bajaj Company sold during July to that sold during October?
a) 39:132
b) 132:139
c) 75:132
d) 122:39
e) 132 : 39
3). If 37% of the bikes of Bajaj Company were sold at a discount in November, how many bikes of Bajaj Company were sold without any discount during the same month?
a) 1697
b) 1681
c) 1701
d) 1709
e) 1721
4). If the dealer earned a profit of 517 on each computer of Bajaj Company sold during October, what was his total profit earned on the computer of that company during the same month?
a) 4756740
b) 2729760
c) 2595760
d) 3078790
e) 2098710
5). The number of bikes of TVS Company sold during July is approximately what per cent of the number of bikes of TVS Company sold during November?
a) 93%
b) 100%
c) 88%
d) 96%
e) 90%
Directions (Q. 6-10): Read the following information and answer the questions that follow.
In a Public sector bank, the electric gadgets being used are 17 tube lights of 40 W each, 14 fans of 80 W each, 16 bulbs of 60 W each, 11 bulbs of 100 W each, 11 AC’s of 2100 W each, 9 laptops of 200 W each and 10 TV’s of 120 W each. In a day, tube lights and TV’s are used for 8 h but 60 W bulbs are used for 7 h and 100W bulbs are used for 9 h whereas laptops and AC's are used for 5 h and 9 h respectively. However, fans are used for 11 h.
(Note: 1000 W = 1 unit, 1 month = 30 days).
6). What is the ratio of consumption of electricity in units by 60W and 120W together and consumption of electricity in units by 100W and 200W together in a month?
a) 136 : 157
b) 215 : 297
c) 274 : 317
d) 272 : 315
e) 280 : 323
7). What is the total electric energy consumed (in units) by 60 W bulbs in the whole month?
a) 181.5
b) 182.3
c) 267.2
d) 231.6
e) 201.6
8). Electricity consumed by all fans is what per cent of energy consumed by all the laptops?
a) 123.27%
b) 136.88%
c) 144.98%
d) 172.42%
e) 156.48%
9). Out of the following, which type of gadgets consumes more electricity in the bank?
a) Laptops
b) Tube lights
c) Fans
d) TV’s
e) Cannot be determined
10). If one electric unit costs 2.70 and power (used by AC's) unit costs 3.70, then what money is paid to the electricity department for one month?
a) 27368
b) 29453
c) 25962
d) 30524
e) 28124
Explanation With Answer Key:
1).Total number of bikes of Bajaj Company sold during the month of November and December together
= 75000 × 15/100 × 6/25 + 75000 × 11/100 × 11/15
= 2700 + 6050
Answer is: e)
2).Required ratio
= 750 × 13 × 4/25 : 750 × 22 × 8/25
= 1560 : 5280
= 39 : 132
Answer is: a)
3).Number of bikes sold by Bajaj Company in the month of November
= 75000 × 15/100 × 6/25 = 2700
37% of bikes sold by Bajaj Company at a discount
= 2700 × 37/100
Number of bikes sold without discount = 2700 - 999
Answer is: c)
4).Number of bikes sold in the month of October
= 75000 × 22/100
= 750 × 22 = 16500
Total number of bikes of Bajaj Company sold/during the month of October
= 16500 × 8/25
= 660 × 8 = 5280
Total profit = 5280 × 517
Answer is: b)
5).Total number of bikes TVS Company sold during the month of July
= 75000 × 21/25 × 13/100
= 750 × 21/25 × 13
Total number of bikes of TVS Company sold during the month of November
= 75000 × 19/25 × 15/100
= 750 × 19/25 × 15
Required % = 8190/8550 × 100
Answer is: d)
6).Consumption of electricity in units by 60W and 120W together
= 201.6 + 288 = 489.6
Consumption of electricity in units by 100W and 200W together
= 297 + 270 = 567
Required ratio = 489.6 : 567
= 4896 : 5670
= 272 : 315
Answer is: d)
7).Total electric energy consume by 60 W bulb in whole month
= 16 × 60 × 7 × 30 W
= 201.6 unit
Answer is: e)
8).Electricity consumed by all fans
= 14 × 80 × 11 × 30 W
Electricity consumed by all laptops
= 9 × 200 × 5 × 30
Required% = (14 × 80 × 11 × 30/9 × 200 × 5 × 30) × 100
Answer is: b)
9).Electricity consumed by all fans
= 14 × 80 × 11 × 30 = 369600 W
Electricity consumed by all laptops
= 9 × 200 × 5 × 30 = 270000 W
Electricity consumed by all tube lights
= 17 × 40 × 8 × 30 = 163200 W
Electricity consumed by all TV’s
= 17 × 120 × 8 × 30 = 288000 W
Electricity consumed by 100 W bulb
= 11 × 100 × 9 × 30 = 297000 W
Hence fans consumed more electricity.
Answer is: c)
10).One unit cost = 2.70.
Power (used by AC’s) Unit cost = 3.70
Electricity consumed by all equipment (except AC’s)
= (201.6 + 369.6 + 270 + 163.2 + 288 + 297) unit
= (1292.4 + 297.00) unit
= 1589.4 unit
Cost for these unit = 1589.4 × 2.7
Electricity consumed by AC’s
= 11 × 2100 × 9 × 30 W
= 623700 W
= 6237 Unit
Cost for it = 6237 × 3.7 = 23076.9
Total cost = 23076.9 + 4291.38
= 27368.28
Answer is: a)
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