IPPB Scale I & IBPS SO 2017 - Practice Quantitative Aptitude Questions (Quadratic Equation & Data Interpretation)

IPPB Scale I & IBPS SO 2017 - Practice Quantitative Aptitude Questions (Quadratic Equation & Data Interpretation)  Set-79:

Dear Readers, Important Practice Aptitude Questions for IBPS Clerk Mains and Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the examination can use this.

Direction (Q. 1-5): Two equations (I) and (II) are given in each question. On the basis of these equations. You have to decide the relation between 'x' and 'y' and give answer .

a)    If x > y

b)    If x < y

c)    If x ≥ y

d)    If x ≤ y

e)    If x = y or no relation can be decided between 'x' and 'y'.

1). I. x = (-7)²

II. y² - 46y - 147 = 0

2). I. 4x² - x - 3 = 0

II. 4y² - 16y + 15 = 0

3).I. 2x² - 117x + 1701 = 0

II. y = 992.25

4).I. 12x² - 41x + 35 = 0

II. 3y² - 17y - 28 = 0

5).I. 4x - 3y = 16

II. 7x - 8y = 17

Direction (Q. 6-10): Following bar graph shows the production of an item (In thousand) by two companies A and B over the years. The line graph shows the percentage sale of these companies in given years :-

6).What is the difference between total item produced by company A and Company B in the whole period of six years ?

a)    34000

b)    35000

c)    36000

d)    37000

e)    38000

7).What is the total sale of company A and B together in year 2008?

a)    50700

b)    51100

c)    52400

d)    53500

e)    54800

8).In the following years which year the percentage rise/fall in production of company B is maximum ?

a)    2009

b)    2010

c)    2011

d)    2012

e)    2013

9).Sale of company B in year 2009 is approximately what percentage of sale of company A in year 2012 ?

a)    64%

b)    72%

c)    78%

d)    84%

e)    96%

10).Sale of company A in year 2013 is approximately how much percentage more or less than the sale of company B in that year?

a)    53%

b)    57%

c)    61%

d)    63%

e)    67%

Directions (Q. 1-5):

1). C)x = (-7)²

= y² - 46y - 147 = 0

y² - 49y + 3y - 147 = 0,

= y (y-49) + 3 (y - 49) = 0

(y - 49) (y + 3) = 0  y = 49, -3

2). B) 4 x² - x - 3 = 0

=  4x² - 4x +3x - 3 = 0

=  4 x (x - 1) + 3 (x - 1) = 0

= (4x + 3) (x - 1) = 0

x = 3/4, 1

4y² - 16y + 15 = 0

4y² - 10y - 6y + 15 = 0

2y (2y – 5) –3 (2y - 5) = 0

(2y - 3) (2y - 5) = 0

y = 3/2, 5/2

3). D) 2x² - 117x + 1701

= 2x² - 54x - 63x + 1701

= 2x ( x - 27) -63 ( x - 27)

= (2x - 63) ( x - 27) = 0

x = 27, 63/2

y = √(992.25)

4). E)12x² - 41x + 35 = 0

= 12x² - 20x - 21x + 35 = 0,

= 4x (3x - 5) - 7 ( 3x - 5) = 0,

=  (4x - 7) (3x -5) = 0,

x = 7/4, 5/3

3y² - 17y - 28 = 0

3y² - 21y +4y - 28= 0

3y ( y - 7) + 4 ( y – 7) = 0

( y -7) ( 3y + 4) = 0

y = 7, -4/3

ie. no relation between ‘x’ and ‘y’.

5). A) Equⁿ (I) × 7 - Equⁿ (II) × 4

(28x -  21y = 112)  -  (28x – 32y = 68)

y = 4,& from this x = 7

6). C) A _Total = 377000 = , B_Total = 341000

Diff = 36000

7). B)Total Sale = 48000× (40/100) + 58000 × (55/100)

= 19200+31900 = 51100

8). B) % rise = [(72-42) / 42] × 100 = 71.428% (maximum)

9). D) B _O9 42000×(50/100) = 21000,

A₁₂ = 50000× (50/100) = 25000

Req.% =(21000 / 25000) × 100 = 84%

10). B)A₁₃ = 80000× (55/100) = 44000, B₁₃ = 70000× (40/100) = 28000

Req.% = [(44000 - 28000) / 28000] × 100

= (16000 × 100) / 28000 = 57.14%

More Practice Aptitude Questions for IBPS SO/IPPB 2016 -Click Here

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