IPPB Scale I & IBPS SO 2017 - Practice Quantitative Aptitude Questions (Application Problems) Set-95:
Dear Readers, Important Practice Aptitude Questions for IPPB & IBPS SO Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the examination can use this.
1). Two pipes P1 and P2 can fill a tank in 24 minutes and 30 minutes respectively. If both the pipes are opened simultaneously, after how much time should P2 be closed so that the tank is full in 20 minutes ?
a) 4 minute
b) 5 minute
c) 6 minute
d) 7 minute
e) 8 minute
2). Mohan takes 8 days less than the time taken by Ravi to finish a piece of work. If both Mohan and Ravi together can finish it in 7.5 days, then how many days Ravi will take to finish the work alone ?
a) 15 days
b) 18 days
c) 20 days
d) 24 days
e) 28 days
3). A shopkeeper bought a bat and sold it at a loss of 15 %. If he had bought it for 20 % less and sold it for Rs.147.2 more, he would have had profit of 35 %. What is the cost price of bat ?
a) Rs.540
b) Rs. 600
c) Rs.625
d) Rs.640
e) Rs.720
4). Two equal amounts are deposited in two bank at same interest rate 12% p.a. for 7 years and 4.5 years respectively. If the different between the interest is Rs. 585 then what was each amount ?
a) Rs.1650
b) Rs.1750
c) Rs.1850
d) Rs. 1950
e) Rs.2050
5). An amount of money grows up to Rs.3136000 in 2 years, and up to Rs.3512320 in 3 years, on compound interest. What is the rate of interest per annum ?
a) 5 % p. a.
b) 8 % p. a.
c) 10 % p. a.
d) 12 % p. a.
e) 15 % p. a.
6). A dealer sells an item for Rs.667, and makes a profit of 16%. He sells another item of a loss of 10% and in whole process he makes no profit no loss. What was the cost of second item ?
a) Rs.900
b) Rs.920
c) Rs.950
d) Rs.980
e) None of these
7). A mixture contains milk and water in the ratio of 4 : 3 on adding 5 litre of water the ratio of milk and water becomes 9 : 8. Find the quantity of water in the mixture ?
a) 9 litre
b) 15 litre
c) 21 litre
d) 24 litre
e) 27 litre
8). In how many ways can a party of 6 men and 6 women be seated at a round table, so that no two women are adjacent ?
a) 518400
b) 86400
c) 14400
d) 1440
e) 840
9). In a simultaneous throw of 2 dice, find the probability of getting a total of 9 ?
a) 1/6
b) 1/36
c) 25/36
d) 9/36
e) 1/9
10) . 8 men can complete a piece of work in 15 days and 7 women can complete the same piece of work in 25 days. If all the 8 men and 7 women work together, in how many days will the work get completed ?
a) 7(3/5) days
b) 6(2/3) days
c) 9(3/8) days
d) 9(2/3) days
e) 9 days
1) b 2) c 3) d 4) d 5) d 6) b 7) e 8) b 9) e 10) c
Solutions:
1). Let the pipe P2 is closed after ‘x’ mins
x [(1/24) + (1/30)] + (20 - x) × (1/24) = 1
= (3x/40) + (5/6) – (x/24) = 1
= (9x – 5x) / 120 = 1 – (5/6) = 1/6
= (4x / 120) = 1/6
x = 120 / (6 × 4)= 5 min
Answer: b)
2). Let Ravi takes ‘x’ days to finish the work, so Mohan will take (x - 8) days to finish the work.
(1/x) + [1/(x - 8)] = 2/15 (i. e Ravi + Mohan 1 day work)
(2x - 8) / (x2 – 8x) = 2/15 (x - 4) ×15 = x2 - 8x
x2 - 23 x + 60 = 0 x2 - 20x - 3 x + 60 = 0
x ( x - 20) - 3 ( x - 20) = 0
x = 20, 3
We discard x = 3 as it is less than 8.
x = 20 days
Answer: c)
3). Let cost is ‘x’ S.P = 17x/20
Now, C. P = 4x/5
S. P = (17x / 20) + 147.2 = (17x + 2944) / 20
{ [(17x + 2944) / 20] – (4x / 5) } × (5/4x) × 100 = 35
[(17x + 2944 – 16x) / 20] × (125 / x) = 35
[(x + 2944) / 4] × (25/x) = 35
25x + 73600 = 140x ,
73600/115 = 640
Answer: d)
4). Let the amount is ‘x’ = [(x × 12 × 7) / 100] × [(x × 12 × 4.5) / 100] = 585
x (84 - 54) = 58500
x = 58500 / 30 = 1950
Answer: d)
5). C. I for third year is 3512320 - 3136000 = 376320
Which is S. I for Rs. 3136000 in one year.
r = (376320 × 100) / (3136000 × 1) = 12% p.a.
Answer: d)
6). Cost of first item = (667 × 100) / 116 = 575
Profit = 667 - 575 = 92
Let the cost of second item is ‘x’
Answer: b)
7). Let the quantity of milk and water are 4x and 3x respectively
4x / (3x + 5) = 9/8, 32x = 27x + 45
x = 45/5= 9
Quantity of water = 3x = 27 litres.
Answer: e)
8). First the six men can sit on round table in (6 - 1)! = 5!ways
Now for no two women adjacent, there are six vacant seat between each pair of men.
So number of ways 6 women can sit on these six vacant seat is 6P6 = 6! ways
So total number of arrangements = 5! ×6! = 120×720 = 86400
Answer: b)
9). n(S) = 6×6 = 36
n (E) = 4 à { (3,6)(4,5)(5,4)(6,3)} P(E) = 4/36 = 1/9
Answer: e)
10). Req. No. of days = (15 × 25) / 40 = 75/8 = 9 3/8days
Answer: c)
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