Dear Readers, Important Practice Aptitude Questions for IPPB & IBPS SO Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the examination can use this.
Directions (Q. 1-5): What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value.)
1). [7.995 + 25.96 + 13.02] ÷ 2.490 = ?
a) 30
b) 4
c) 9
d) 19
e) 1
2). (5.95 x 8.06) ÷ (8.03 x 2.04) = ? - 4.95
a) 4
b) 16
c) 8
d) 40
e) 20
3). 4.014 ÷ 1.894 x 15.011 ÷ 8.971= (?)
a) 9
b) 15
c) 3
d) 12
e) 10
4). (6.90)3 - (2.99)3 - (6.02)3 = (?)2
a) 50
b) 25
c) 10
d) 1
e) 100
5). [(6.03 x 2.98) - (1.99 x 2.012)] / (2.053 —360.5) = ?
a) 1
b) 20
c) 10
d) 15
e) 5
Directions (Q. 6-10):Refer to the pie-chart and answer the given questions.
The students of ABC Institute take part in various extra-curricular activities, the distribution of which is as shown below. Total number of students = 800
6). What the difference between the, total number of students taking part in Volleyball and Swimming together and the total number of students talking part in Football?
a) 208
b) 190
c) 200
d) 220
e) 184
7). What is the ratio of the total number of students taking part in Tennis and Swimming together to that taking part in Cricket and Football together?
a) 19:18
b) 17:7
c) 10:9
d) 39:35
e) 28:19
8). What is the number of girls who take part in Volleyball, if the ratio of boys to girls is 5 : 11?
a) 143
b) 130
c) 156
d) 65
e) 67
9). What is the average number of students taking part in Tennis, Cricket, Football and Swimming?
a) 142
b) 148
c) 162
d) 122
e) 158
10). If out of the number of students taking part in Tennis, 79 are girls, what is the difference between the number of boys and that of girls taking part in Tennis?
a) 24
b) 21
c) 13
d) 10
e) Other than those given as options
11). The number of students taking part in Cricket is approximately what per cent more than that taking part in Football?
a) 12
b) 26
c) 29
d) 19
e) 20
1)d 2)c 3)c 4)c 5)e 6)c 7)a 8)a 9)b 10)e 11)a
1). d) ? = (7.995 + 25.96 + 13.02) ÷ 2.490
= (8 + 26 + 13) ÷ 2.5 = 47 ÷ 2.5 ≈ 19
2). c)? -. 4 95 = (5.95 × 8.06) ÷ (8.03 × 2.04)
or. ? – 5 = (6 × 8) / (8 × 2) = 3
? ≈ 3 + 5 = 8
3). c) (?) = 4.014 ÷ 1.894 × 15.011 ÷ 8.971
≈ 4 ÷ 2 × 15 ÷ 9 = 2 × 15 ÷ 9 = (30/9) ≈ 3
4). c) ( ?)2 = (6.90)3 - (2.99)3 - (6.02)3
≈ (7)3 - (3)3 - (6)3
= 343 - 27 - 216 = 343 - 243 = 100
? = √100 = 10
5). e)? = [ (6.03 x 2.98) - (1.99 x 2.012) ] / [ (2.05)3 -360.5]
= (6 × 3 – 2 × 22) / [(2)3 – (36)1/2] = 10 / (8-6) = 10/2 ≈ 5
6). c) Reqd difference = (26 + 16 - 17)% of 800 = 25% of 800 = 200
7). a) Required ratio = (22 + 16) / (19+17) = 38/36 = 19:18
8). a)Number of students taking part in Volleyball = (26 × 800)/100 = 208
Let the number of boys be 5x and girls be I I x.
Now, 5x + 11x = 208
or, I6x =.208
x = 208 /16 =13
Number of girl students who take part in Volleyball = I I x 13 = 143
9). b)Reqd average [ (22+19+17+16)%of 800 ] / 4
= (74% of 800) / 4= (74 x 800) / (100x4) = 148
10). e) Total number of students taking part in Tennis = 22% of 800 = (22 x 800) /100 = 176
Out of the number of students taking part in tennis, 79 are girls.
The number of boys who take part in Tennis = 176 — 79 = 97
Difference = 97 — 79 = 18
11). a) Reqd % more = [(19-17) /17] x100 = 200/17 ≈ 11.76 ≈ 12% more
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