Quant Quiz on "MIXED" for SSC CGL 2016

Directions (Q.1-5): Study the following graph carefully to answer these questions. Number of students in College A and College B over the years.

1. For which college(s) and in which year was the per cent rise in number of students from the previous year is the highest?

College A in year 2004 and College B in year 2005

Only College B in year 2004

College A in year 2004 and College B in year 2004

College A in year 2007 and College B in year 2004

Solution:

Percentage rise in number of students from college A in 2004 =(40 - 20 )/20×100=100% Similarly,
percentage rise in number of students from college B in 2004 =(60 - 30)/30×100=100%

2. What is the ratio of the total number of students of College A in years 2004, 2006 and 2007 together and the total number of students of College B in year 2003, 2004 and 2008?

35 : 32

33 : 37

34 : 31

32 : 35

Solution:

Number of students in college A in the years 2004, 2006 and 2007 =160×10³
 Also, number of students in college B in the year 2003, 2004 and 2008 =175×10³
 Required ratio = 160 : 175 = 32 : 35

3.What is the average number of students in College A for all the years together?

45,000

50,000

52,000

48,000

Solution:

Average of students in College A= (20+40+45+50+70+75)/6 = 50*1000

4. What is the approximate percentage rise in the number of students of College B from 2005 to 2006?

8

12

4

15

20

Solution:

%age increases = (5*100)÷65 ≈ 8

5.The number of students of College B in year 2008 is what per cent of the total students of College B in all the years together? (Round off to two digits after decimal)

20.61

23.79

21.79

17.29

Solution:

Required% =85/390×100=21.79%

6. Two numbers are in the ratio 1 1/2 ∶2 2/3. When each of these is increased by 15, they become in the ratio 1 2/3 ∶2 1/2. The greater of the number is:

27

36

48

64

Solution:

7.If a : b =2/9 ∶ 1/3,b∶c=2/7:5/14 and d∶c= 7/10 ∶ 3/5, then a : b : c : d is:

4 : 6 : 7 : 9

16 : 24 : 30 : 35

8 : 12 : 15 : 7

30 : 35 : 24 : 16

Solution:

8. The incomes of A, B and C are in the ratio 7 : 9 : 12 and their spending’s are in the ratio 8 : 9 : 15. If A saves one-fourth of his income, then the savings of A, B and C are in the ratio of:

56 : 99 : 69

69 : 56 : 99

99 : 56 : 69

99 : 69 : 56

Solution:

Let, the incomes of A, B and C be 7x, 9x and 12x respectively, and the expenditures 8y, 9y and 15y, we have to find the value of
(7x-8y) ∶(9x-9y):(12x-15y)
 Also, 7x-8y=7x/4 or, 7x-7x/4=8y
Or, x/y=32/21
Now, (7×32-8×21):(9×32-9×21):(12×32-15×21)=56∶99∶69.

9.In an alloy, the ratio of iron and chromium is 5 : 2. If 1.250 Kg of chromium is mixed in 17.500 Kg of alloy, then the ratio of iron and chromium will be:

2 : 1

2 : 3

3 : 2

1 : 2

Solution:

Amount of iron =5/7×17.5=12.5 kg
Amount of chromium =2/7×17.5=5
Now, the amount of chromium = 5 + 1.25 = 6.25 = 6.25 kg
∴ Required ratio = 12.5 : 6.25 = 2 : 1.

10. A man divides his property so that his son’s share to his wife’s and wife’s share to his daughter’s are both in the ratio 3 : 1. If the daughter gets Rs. 10,000 less than son, the value (in rupees) of the whole property is:

Rs. 16,250

Rs. 16,000

Rs. 18,250

Rs. 17,000

Solution:

Son : Wife = 3 : 1 = 9 : 3
Wife : daughter = 3 : 1
∴ Son : wife : daughter = 9 : 3 : 1
Sum of ratios = 9 + 3 + 1 = 13
Let, total wealth be Rs. x.
∴ Son’s share – daughter’s share = Rs. 10,000
 ⇒ 9x/13 - x/13=10000
 ⇒(9x - x)/13=10000
 ⇒8x=130000
 ⇒130000/8= Rs. 16250

11. Ram got twice as many marks in English as in Science. His total marks in English, Science and Mathematics are 180. If the ratio of his marks in English and Mathematics is 2 : 3, what are his marks in Science?

30

60

72

90

Solution:

Marks in English = 2x
Marks in Mathematics = 3x
Marks in Science = x
Now, according to the question, x + 2x + 3x = 180
⇒ 6x = 180 ⇒ x = 30

12. A box contains Rs. 56 in the form of coins of one-rupee, 50-paise and 25-paise. The number of 50-paise coins is double the number of 25-paise coins and four times the number of one-rupee coins. How many 50-paise coins are there in the box?

52

64

32

16

Solution:

Number of one-rupee coins = x
 Number of 50-paise coins = 4x
 Number of 25-paise coins = 2x
 ∴ Ratio of their values =x:4x/2 ∶ 2x/4=2∶4∶1
 ∴ Value of 50-paise coins =4/(2+4+1)×56
 =4/7×56= Rs. 32
 ∴ Their number = 32×2=64

13. Annual income of Amit and Veer are in the ratio 3 : 2, while the ratio of their expenditures is 5 : 3. If at the end of the year each saves Rs. 1,000, the annual income of Amit is:

Rs. 9,000

Rs. 8,000

Rs. 7,000

Rs. 6,000

Solution:

Amit’s income = Rs. 3x and his expenditure = Rs. 5y
Veer’s income = Rs. 2x and his expenditure = Rs. 3y
 ∴ 3x – 5y = 2x – 3y ⇒ x = 2y
 ∴ 3x – 5y = 1000
 ⇒ 6y – 5y = 1000 ⇒ y = 1000
 ∴ x = 2000
 ∴ Amit’s income = 3x = Rs (3 × 2000) = Rs. 6000

14. The population of town is 3,11,250. The ratio between women and men is 43 : 40. If there are 24% literate among men and 8% literate among women, the total number of literate persons in the town is:

41,800

48,900

56,800

99,600

Solution:

Women =43/83×311250=161250
Men = 311250 – 161250 = 150000
∴ Total number of literate persons =(161250×8)/100+150000×24/100
= 12900 + 36000 = 48900

15.The ratio of the sum of two numbers and their difference is 5 : 1. The ratio of the greater number to the smaller number is:

2 : 3

3 : 2

5 : 1

1 : 5

Solution:

Let the numbers be x and y, where x > y
Now, according to the question,
(x+y)/(x-y )=5/1 (By componendo and dividendo) 
⇒(x + y + x - y )/(x + y - x + y)=(5 + 1)/(5 - 1)
⇒x/y=6/4=3/2

               

ALL THE BEST