Solutions for Aptitude Practice Test (IBPS)

August 23, 2015    

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1. From I, difference b/w SI & CI for 2 years is
(P x R2)÷ 1002  => (28000 x R2 )÷ (100*100) =1120 
=> R2 = 400 => R = 20%
From II, In 5 years, 100% interest and in 1 year 20%
2. From I, we can get Perimeter
From II, Cost to calculate
Both are required to get the answer
3. We can't get anything From I
From II, 55% is 1584 
100% is (100÷54)*1584 = 2880 
Only II is sufficient
4. Both are not sufficient as length of the train is not given.
5. From I, B is the youngest person
From II, A is younger to C.
From both the statements, it is clear that C is the eldest.
6. 11÷ 20 of 7% of 48% of 200000 = 3696
7. Qualified male candidates from B = (3÷ 5) of 18% of 61% of 200000 = 13176 
Qualified male candidates from D = (3÷ 5) of 23% of 45% 200000 = 12420 
The ratio = 122 : 115
Shortcut:  (3÷ 5) of 18% of 61% of 200000 :  (3÷ 5) of 23% of 45% 200000 
=>18 x 61 : 23 x 45 = 122 : 115
8. Number of candidates qualified from D = 23% of 45% of 200000 = 20700
Number of female candidates =  (2÷ 5) of 20700 = 8280
Number of candidates qualified from E = 12% of 65% of 200000 = 15600
Number of female candidates =  (7÷ 12) of 15600 = 9100
Number of candidates qualified from F = 19% of 57% of 200000 = 21660
Number of female candidates = (7÷ 15) of 21660 = 10108
Required % 
=((8280 + 9100 + 10108  x 100)÷ (20700 + 15600 + 21660))*100=47.42%
9. Number of male candidates qualified from
A = (4÷ 5) of 15% of 49% of 200000 = 11760 
Number of male candidates qualified from
C = (5÷ 8) of 6% of 54% of 200000 = 4050
Required number = 11760 + 4050 = 15810
10. Number of candidates from
A = 15% of 200000 = 30000
Number of candidates not qualified from
A = 51% of 30000 = 15300
Number of candidates from
B = 18% of 200000 = 36000
Number of candidates not qualified from
B = 39% of 36000 = 14040
Required % = ((15300 + 14040) ÷(30000 + 36000)) *100 = 44.45 
11. 6615 ÷ 4.5 = 1470
1470 ÷ 4 = 367.5
367.5 ÷ 3.5 = 105
105 ÷3 = 35
35 ÷ 2.5 = 14
14 ÷ 2 = 7
10% of 367.5 + ? = 50 => ? = 13.25
12. 17 * 1 + 12 = 18
18 * 2 +22 = 40
40 * 3 + 32 = 129
129 * 4 +42= 532
532 * 5 +52 = 2685
2685 * 6 + 62 = 16146
16146 ÷32+ ? = 2000 =>? = 206
13. 2 * 2.5 = 5
5 * 3 = 15
15 * 2.5 = 37.5
37.5 * 3 = 112.5
112.5 *2.5 = 281.25
281.25 * 3 = 843.75
(843.75 * 4 - 11) = 58
14. 365 - 61 = 304
304 - 59 = 245
245 - 57 = 188
188 - 55 = 133
133 - 53 = 80
80 - 51 =29
245 + (1936) = ?2 
15. 32 * 3 = 96
96 - 5 = 91
91 * 3 = 273
273 - 5 = 268...
((96÷ 2)+16) = 8
16. r2h ÷  2πrh ) = (924 ÷ 264) => r = 7
2πrh = 264 => 2 * (22÷7) * 7 *  h = 264 => h = 6
17. Expenditure = Income - Saving
Let the incomes be 5x and 3x
∴ (5x - 2600)÷(3x - 1800) =  (9÷ 5)
=>  x =1600 
Their incomes are Rs.8,000, Rs.4,800
18. 12.5% = 2.5 kg
Then 100% is (100÷12.5) * 2.5 = 20 kg
Reduced price is (100÷ 20)= Rs.5
19. ((34÷100)* 320) + ((?÷ 100)*460) = 237.6 
  ?= ( (237.6 - 108.8)÷ 4.6) = 28
20. ((35 * 35) ÷  7) + √(?) = 224 
=> √(?) = 224 - 175 = 49 
=>?= 492 = 2401

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Solutions for Aptitude Practice Test (IBPS) 4.5 5 Yateendra sahu August 23, 2015 sponsored links 1. From I, difference b/w SI & CI for 2 years is (P x R 2 ) ÷ 100 2   => (28000 x R 2 ) ÷ (100*100) =1120  ...


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