Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-5)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-5):

Dear Readers, Nowadays most of the aspirants are facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.

Here in Scoring Part we are providing 10 Questions in simplification, 10 Questions in Approximation, 5 Questions in number Series and 5 Questions in Quadratic Equations, total 30 questions in 20 Minutes. By practicing these questions regularly you can increase your calculation speed and it will help you to increase your score.

Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). 1/6 of (92)% of 1 1/23 of (650) = 85 + ?

1). Answer: c)
650 × 24/23 × 92/100 × 1/6 = 85 + ?
or, ? = 104 - 85 = 19

2. 92 × 576 ÷ (2 × √1296) = (?)^3 + √49

2). Answer: c)
92 × 576 ÷ (2 × √1296) = (?)^3 + √49
or, 92 × 576 / 72 = (?)^3 + 7
or, 736 - 7 = ?^3
?3 = 729
? = ³√729 = 9

3. 3 1/4 + 2 1/2 – 1 5/6 = (?)^2 /10 + 1 5/12

3). Answer: e)
(3 + 2 – 1 – 1) + (1/4 + 1/2 – 5/6 – 5/12) = ?^2 / 10
3 + ((3 + 6 – 10 – 5) / 12) = ?^2 / 10
3 - 6/12 = ?^2 / 10
3 – 1 /2 = ?^2 / 10
?2 = 5/2 × 10 = 25
? = 5.

4. (√8 × √8)^(1/2) + (9)^(1/2) = (?)^3 + √8 – 340

4). Answer: a)
(√8 × √8)^(1/2) + (9)^(1/2) = (?)^3 + √8 – 340
√8 + 3 = (?)^3 + √8 – 340
(?)^3 = 340 + 3
(?)^3 = 343
? = 7

5. (15 × 0.40)^4 ÷ (1080 ÷ 30)^4 × (27 × 8)^4 = (3 × 2)^(?+5)

5). Answer: b)
(15 × 0.40)^4 ÷ (1080 ÷ 30)^4 × (27 × 8)^4 = (3 × 2)^(? + 5)
6^4 ÷ (36)^ 4 × (216)^ 4 = (6)^(? + 5)
6^4 ÷ (6^2)^4 × (6^3)^ 4 = (6)^ (? + 5)
6^(4 + 12 – 8) = (6)^(? + 5)
(6)^ 8 = (6)^(? + 5)
? + 5 = 8
? = 3

6. 1664 × 1.75 + 1008 × 1.25 - 1220 × 0.65 = ?

6). Answer: c)
? = 2912 + 1260 - 793 = 3379

7. (?% of 999) ÷ 0.9 = 166.5

7). Answer: b)
? × 999 / 100 = 166.5 × 0.9
? = 14985 / 999 = 15

8. {(157.8)^2 - (117.2)^2} × 0.008 = ?

8). Answer: a)
? = {(157.8 + 117.2) × (157.8 - 117.2)} × 0.008
? = (275 × 40.6) × 0.008 = 11165 × 0.008
= 89.32

9. 82992 ÷ ? = 76 × 42

9). Answer: c)
? = 82992 / (76 × 42) = 26

10. [{(486)^2 ÷ (27)^2} × 15] ÷ 12 = ?

10). Answer: e)
? = {[(486 × 486) / (27 × 27)] × 15} ÷ 12
? = 324 × 15 / 12 = 405

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11. (24/9)^2 × 399 / 39 ÷ 41 / 899 = ?

11). Answer: a)
(24/9)^2 × (399/39) ÷ (41/899) = ?
? ≈ (576 / 81) × (400/40) ÷ (40/900)
? = 1600

12. 67.99% of 1401 - 13.99% of 1299 = ?

12). Answer: c)
68% of 1400 - 14% of 1300
= 952 - 182 = 770

13. 5466.97 - 3245.01 + 1122.99 = ? + 2309.99

13). Answer: d)
5467 - 3245 + 1123 - 2310 = ?
? = 1035

14. 5998 ÷ 9.98 + 670.99 - 139.99 = ?

14). Answer: d)
5998 ÷ 9.98 + 670.99 - 139.99 = ?
? ≈ 6000/10 + 670 – 140
? = 600 + 670 – 140
? = 1130

15.– (4.99)^3 + (29.98)^2 - (3.01)^4 = ?

15). Answer: e)
? = – (4.99)^3 + (29.98)^2 - (3.01)^4
? ≈ - 5^3 + 30^2 - 3^4
? = – 125 + 900 – 81
? = 694 ≈ 690

16. 2874.78% of 124.06 ÷ √26 = ?

16). Answer: c)
? ≈ (2875 × 124 / 100) ÷ 5
? = 3565 / 5
? = 713 ≈ 710

17. 44.4 × 4.44 ÷ 7.98 + √24000 = ?

17). Answer: a)
? = 44.4 × 4.44 / 8 + √24000
? ≈ 197 / 8 + 154.9
? ≈ 25 + 155 = 180

18. 134.9% of 127.89 + 115.05% of 23.94 = ?

18). Answer: d)
? = 135 × 128 / 100 + 115 × 24 / 100
? = 172.8 + 27.6 = 200.4 ≈ 200

19. (83.98)^2 ÷ 13.49 = ?

19). Answer: b)
? = (83.98)^2 / 13.49
? = (84)^2 / 13.5
? = 522.66 ≈ 525

20. (2904 ÷ 34.95 - 12.99) × 5.96 = ?

20). Answer: c)
? = (2900/35 – 13) × 6
? ≈ (83 – 13) × 6
? = 70 × 6 = 420

Direction (21 – 25): What value should come in place of the question mark (?) in the following number series?21. 19 , 16 , 44 , 107 , ?

21). Answer: c)
The difference of difference between numbers is + 25, +35, +45, ….

22. 11 , 14 , 23 , 50, ?

22). Answer: d)
The series is,
11 + 3^1 = 11 + 3 = 14;
14 + 3^2 = 14 + 9 = 23;
23 + 3^3 = 23 + 27 = 50;
50 + 3^4 = 50 + 81 = 131

23. 19 , 25 , 42 ,71 , 113 , ?

23). Answer: a)
The difference of difference between numbers is +11, +12, +13, +14, …

24. 21 , 35 , 30 , 44 , 39 ,?

24). Answer: b)
The series is,
21 + 14 = 35;
35 – 5 = 30;
30 + 14 = 44;
44 – 5 = 39;
39 + 14 = 53

25. 7, 14, 30, 56 , 93 , ?

25). Answer: a)
The difference of difference between the numbers is, +9, +10, +11, +12, …..

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) P < Q
b) P ≤ Q
c) P ≥ Q
d) P = Q or no relation can be established between P and Q
e) P > Q

26. Ⅰ. 9P^2 – 9P + 2 = 0
Ⅱ. 18Q^2 + 3Q = 1

26). Answer: e)
Ⅰ. 9P^2 – 9P + 2 = 0
Or, 9P^2 – 6P – 3P + 2 = 0
Or, (3P – 1)(3P – 2) = 0
∴ P = (1 / 3), (2 / 3)
Ⅱ. 18Q^2 + 3Q – 1 = 0
Or, 18Q^2 + 6Q – 3Q – 1 = 0
Or, (6Q – 1)(3Q + 1) = 0
∴ Q = - (1 / 3), (1 / 6)
Hence , P > Q

27. Ⅰ. P^2 + 13P + 42 = 0
Ⅱ. 2Q^2 + 22Q + 60 = 0

27). Answer: b)
Ⅰ. P^2 + 13P + 42 = 0
Or, P^2 + 7P + 6P + 42 = 0
Or, (P + 7)(P + 6) = 0
∴ P = -7, -6
Ⅱ. 2Q^2 + 22Q + 60 = 0
Or, Q^2 + 11Q + 30 = 0
Or, (Q + 5)(Q + 6) = 0
∴ Q = -5, -6
Hence , Q ≥ P

28. Ⅰ. 6P + 7Q = 45
Ⅱ. 2P + 3Q = 17

28). Answer: e)
P = 4 and Q = 3
Hence P > Q

29. Ⅰ. 3P^2 + 192 = - 48P
Ⅱ. Q^2 + 16Q + 64 = 0

29). Answer: d)
Ⅰ. 3P^2 + 48P + 192 = 0
Or, P^2 + 16P + 64 = 0
Or, (P + 8)^2 = 0
∴ P = -8 , -8
Ⅱ. Q^2 + 16Q + 64 = 0
Or, (Q + 8)^2 = 0
∴ Q = -8, -8
Hence , P = Q

30.Ⅰ. 15P^2 - 8P + 1 = 0
Ⅱ. 45Q^2 + 21Q = 6

30). Answer: c)
Ⅰ. 15P^2 – 8P + 1 = 0
Or, 15P^2 – 3P – 5P + 1 = 0
Or, (3P – 1)(5P – 1) = 0
∴ P = (1 / 3), (1 / 5)
Ⅱ. 45Q^2 + 21Q – 6 = 0
15Q^2 + 7Q – 2 = 0
Or, 15Q^2 + 10Q – 3Q – 2 = 0
Or, (5Q – 1)(3Q + 2) = 0
∴ Q = (1 / 5), - (2 / 3)
Hence , P ≥ Q

       

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