IBPS Clerk/RRB Mains 2016 - Practice Quantitative Aptitude Questions (Data Interpretation & Data sufficiency) Set-73:
Dear Readers, Important Practice Aptitude Questions for IBPS Clerk Mains and Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the examination can use this.
Directions (Q. 1-5): Study the following graph and answer the questions that are given below:
Income of Railways from Passengers and Goods carriages
Total expenditure of Railways on both (Passengers and Goods carriage)
(Profit = income – expenditure)
1). In which of the following years the percentage increase/decrease in the total income of Railways is the maximum over its previous year?
a) 2010-11
b) 2007-08
c) 2008-09
d) 2009-10
e) None of these
2). In which of the following years the profit of Railways is the maximum?
a) 2006-07
b) 2007-08
c) 2008-09
e) None of these
3). In how many years the income from Passengers carriage is less than the average income from the same for all the given years?
e) None of these
4). What is the approximate per cent income from Goods carriage in 2007-08 with respect to the total income from Passengers carriage for all the given years?
e) None of these
5). What is the ratio of the total income in the year 2008-09 to that in the year 2009-10?
a) 45 : 65
b) 95 : 110
c) 195 : 209
d) 205 : 249
e) None of these
Directions (6 – 10): Each of the following questions consists of a question followed by three statements I, II and III. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
6). What is the speed of a boat in still water?
I. The boat covers 12 km in 2 hours downstream.
II. The boat covers the same distance in 4 hours upstream.
III. The speed of the stream is one-third that of the boat in still water.
a) Both I and II
b) I and either II or III
c) All I, II and III
d) The question cannot be answered even with the information in all three statements.
e) None of these
7). What is the speed of a train?
I. The length of the train is 240 metres.
II. The train crosses a pole in 24 seconds.
III. The train crosses a platform in 48 seconds.
a) Both I and III
b) Both I and II
c) Both II and III
d) Any two of the three
e) None of these
8). What is the age of a class teacher ?
I. There are 11 students in the class.
II. The average age of the students and the teacher is 14 years.
III. The average age of the teacher and the students is 3 years more than that of the students.
a) Both I and III
b) Both I and II
c) II and either I or III
d) All I, II and III
e) None of these
9). Sri Gupta borrowed a sum at compound interest. What is the amount returned in 2 years ?
I. The rate of interest is 5% per annum.
II. The simple interest incurred on the sum in 1 year is 600.
III. The borrowed sum is ten times the amount earned at simple interest in two years.
b) Only III
c) Both II and III
d) Either I or III
e) All I, II and III
10). What is the area of a given right-angled triangle?
I. The length of the hypotenuse is 5 cm.
II. The perimeter of the triangle is four times that of its base.
III. One of the angles of the triangle is 60°.
a) Only II
b) Only III
c) Either II or III
d) Both I and III
e) Question cannot be answered even with the information in all three statements
1)b 2)c 3)c 4)a 5)c 6)b 7)b 8)d 9)c 10)d
Solutions:
1). B)In 2007-08 = (99100−88600)/88600×100 = 11.86% increase
In 2008-09 = (99100−97500)/99100×100 = 1.6% increase
In 2009-10 = (104500 − 97500)/97500 = 7.17% increase
In 2010-11 = (116100−104500)/104500 = 11.10% increase
2). C)Profit = Income - Expenditure
Profit in 2006-07 = 88600 - 86000 = Rs. 600 crore
In 2007-08 = 99100 - 87500 = Rs. 11600 cr
In 2008-09 = 975OO - 785OO = Rs. 19000 cr
In 2009-10 = 104500 - 95000 = Rs. 9500 cr
In 2010-11 = 116100 - 105000 = Rs. 11100 cr
Hence the profit of the Railways in 2008-09 is the maximum.
3). C)Average income of the Railways by Passenger trains
= (25800+30500+28800+35500+36100)/5 = 156700/5 = 31340
Hence there are three years in which there is less income than the average income earned by Passenger trains.
4). A)Required percentage = 68600/156700 = 43.77% = 44%
5). C)Required Ratio = 97500/104500 = 195/209 = 195 : 209
6). B)Let the speed of the boat be u and that of the stream be v.
Then speed of boat downstream = u + v
From statement I:
v + u = 12⁄2 = 6 kmph ... (i)
And speed of boat upstream = u – v
From statement II
u – v = 12⁄4 = 3 kmph ... (ii)
From statement III
v = u⁄3... (iii)
From statement I and II
u+v=6; u−v=3
=> 2u=9 => u = 9⁄2 = 4.5 kmph
From statement I and III
Again, from eqn (i) and (iii), we get
u + 3u⁄3 = 6 or, 4u = 18
4u = 18⁄4 = 4.5 kmph
Hence, statement I and either II or III is sufficient to answer the question
7). B)From statement I. The length of the train = 240 m. Again, time is not given in the statement. Hence, I alone is not sufficient.
From II. Time taken by the train to cross a pole is 24 seconds. But the length (distance) is not given in the statement. Hence, statement II alone is not sufficient.
From III. Time taken by the train to cross the platform is 48 seconds. But the lengths of the train and the platform are not given. Therefore, statement III alone is not sufficient.
Now, on combining statements I and II, we get
Speed of the train = 240⁄24 = 10 m/s
Hence, both I and II together are sufficient to answer the question.
8). D)From I. There are 11 students in the class.
From II. The average age of students and class teacher is 14 years.
From III. The average age of class teacher is 3 years more than that of students.
Now, combining all three statements, we have
Average age of (students + teacher) = 14 × 12 = 168 years
Average age of 11 students = 14 – 3 = 11 years
Total age of 11 students = 11 × 11 = 121 years
Therefore, teacher’s age = 168 – 121 = 47 years
9). C)From I. R = 5% per annum
From II. SI for 1 year = 600 SI for 2 years = 600 × 2 = 1200
From III. P = 10 × SI = 10 × 1200 = `12000
Now, from II and III, we get
SI * 100/(P * T) = [(1200 * 100)/(12000 * 2)] = 5%
Therefore amount = P (1+5/100)2 = 12000 * 1.05 * 1.05
10). D)From I. AC = 5 cm
From II. Perimeter = 4 × base
From III. One of the angles of the triangle, say ∠C, be 60°
From I and III. cos 60° = BC/AC
or, BC = AC × cos 60°= 5⁄2
a = 5⁄2, b = 5 (∴ AC = b)
Now, area of the triangle ABC = ab sinᶿ
1⁄2 × 5⁄2 × sin 60°
5/4×√3/2 = (25/8) √3cm2
Hence, statement I and III are sufficient to answer the question.
More Practice Aptitude Questions for IBPS RRB/clerk 2016 -Click Here
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