Hi readers,
Today I am sharing Missing Table set, this type of DI set is trending in the exams. Solve now :-
No. of male students = ( 80-32) = 48
∴ No. of male students who were average
=(1/3 x 48)= 16
Today I am sharing Missing Table set, this type of DI set is trending in the exams. Solve now :-
Direction :-
A professor keeps data on students tabulated by performance and sex of the student. The data are kept on a computer disk but, unfortunately, some of them are lost because of a virus.Only the following could be recovered:
Panic buttons were pressed but of no avail. An expert committee was formed,which decided that the following facts were self -evident :
(a) Half the students were either excellent or good
(b) 40% of the students were females
(c) One third of the male students were average
1. How many students are both female and excellent?
2.What proportion of good students are male?
3. What proportion of female students are good ?
4. How many students are both and good?
5.Among average students, what is the ratio of male to female?
Solutions :
24___28 : First complete the table with the help of the facts provided as shown below:
No. of females = 32
But 40% of the students were females.
∴ Total no. of students = (100/40 x 32) = 80No. of male students = ( 80-32) = 48
∴ No. of male students who were average
=(1/3 x 48)= 16
1. No. of students who are both female and excellent = none.
2. Proportion of female students who are male
3. Proportion of female students who are good
4. No.of students who are both male and good = 22.
No comments:
Post a Comment